Home / Assignment Help / 1.The table shows climate data for Death Valley, California, as recorded at the Cow Creek Station. The temperatures are rounded to the nearest integer. Climate data for Death Valley, CaliforniaTemperature Record high52 Record low Daily mean25 (a)Plot and label these values on a number line. (b)For each pair of temperatures found in the table, calculate the difference. Organize your work using a table. Climate data for Death Valley, CaliforniaTemperature Record high52 Record low Daily mean25

1.The table shows climate data for Death Valley, California, as recorded at the Cow Creek Station. The temperatures are rounded to the nearest integer. Climate data for Death Valley, CaliforniaTemperature Record high52 Record low Daily mean25 (a)Plot and label these values on a number line. (b)For each pair of temperatures found in the table, calculate the difference. Organize your work using a table. Climate data for Death Valley, CaliforniaTemperature Record high52 Record low Daily mean25

Posted in Mathematics

This question still doesn’t make any sense, unfortunately.


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Posted in Mathematics

Solve for x. round to nearest tenth if needed. 1. 7r-7=2r+18 a.r=-5 b.r=5 c.r=2.2 d.r=1.2 2. 2x+12=18-x a.x=3 b.x=10 c.x=6 d.x=2 3. 8x-3=15x+18 a.x=-3 b.x=3 c.x=2.1 d.x=0.9 4. 6y-6=4y+16 a.y=2.2 b.y=-2.2 c.y=11 d.y=5 5. 3(x-4)=5(x+2) a.x=11 b.x=-11 c.x=1 d.x=-1

1)  The answer is: [B]: r = 5 .
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Explanation:
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Given: 7r − 7 = 2r + 18 ; Round your answer to the nearest tenth, if necessary.
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Since “r” is the only variable given, let us assume we want to solve for “r” (instead of “x”).
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→ Subtract “2r” from EACH SIDE of the equation; and & add “7” to EACH SIDE of the equation:
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→ 7r − 7 − 2r + 7 = 2r + 18 − 2r + 7 ;  to get: → 5r = 25 ;
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→ Now, divide EACH SIDE of the equation by “5”; to isolate “r” on one side of the equation; and to solve for “r” :
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→ 5r / 5 = 25 / 5 → r = 5 → which is: “Answer choice: [B]”.
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Let us check our answer, by plugging in “5” for “r” in the original equation:
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 → 7r − 7 = 2r + 18 ;  →  7(5) − 7 =? 2(5) + 18? ;
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→ 35 − 7 =? 10 + 18 ?;     → 28 =? 28? Yes!
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 2) The answer is: [D]: x = 2 .
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Explanation: 
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Given: 2x + 12 = 18 − x ; Solve for “x” (round to nearest tenth, if necessary).
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→ Add “x” to EACH SIDE of the equation, & subtract “12” from EACH SIDE of the equation:  → 2x + 12 + x − 12 = 18 − x + x − 12 ; 
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→ To get: 3x = 6 ;  → Divide EACH SIDE of the equation by “3”;
to isolate “x” on one side of the equation; and to solve for “x”:
_____________
→ 3x / 3 = 6 / 3 ; → x = 2 ; which is: “Answer choice: [D]”.
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Let us check our answer, by plugging in “2” for “x” in the original equation:
________________
→ 2x + 12 = 18 − x ; → 2(2) + 12 =? 18 − 2 ?
________________
→ 4 + 12 =? 18 − 2 ? ;   → 16 =? 16?  Yes!
________________________________
3)  The answer is: [A]: x = -3 . 
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Explanation:
________________
Given:  8x − 3 = 15x + 18 ; Solve for “x”. Round your answer to the nearest tenth, if necessary.
_________________
→ Subtract “8x” from EACH SIDE of the equation, & add “3” to EACH SIDE of the equation:
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→ 8x − 3 − 8x + 3 = 15x + 18 − 8x + 3 ; to get:
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→ 0 = 7x + 21 ; → Subtract “21” from EACH SIDE of the equation;
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→ 0 − 21 = 7x + 21 − 21 ; to get:
_______________
→  -21 = 7x ; Now divide EACH SIDE of the equation by “7”;
    to isolate “x” on one side of the equation; & to solve for “x”:
_______________
→ = -21 / 7 = 7x / 7 ; →  -3 = x ; which is “Answer choice: [A].”
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Let us check our answer, by plugging in “-3” for “x” in the original equation:
________________
→  8x − 3 = 15x + 18 ;  → 8(-3) − 3 =?  15(-3) + 18 ?;
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→ -24 − 3 =?  -45 + 18 ? ;   →  -27 =? -27?  Yes!
___________________________
4)  The answer is: [C]: y = 11 .
_____________
Explanation:
____________
Given: 6y − 6 = 4y + 16 ; Solve for “y”; Round to the nearest tenth, if necessary.
____________
(Note: Since “y” is the only variable given; assume we are to solve for “y” instead of “x”).
____________
→ Subtract “4y” from EACH SIDE of the equation, & add “6” to EACH SIDE of the equation; → 6y − 6 − 4y + 6 = 4y + 16 − 4y + 6 ; to get:
_______________
→ 2y  = 22 ; Now, divide EACH SIDE of the equation by “2”; to isolate “y” one side of the equation; and to solve for “y” ;
_______________
→ 2y / 2 = 22 / 2 ; →  y = 11 → which is “Answer choice: [C]”.
_______________________________
Let us check our answer, by plugging in “11” for “y” in the original equation:
___________________
→  6y − 6 = 4y + 16 ; → 6(11) − 6 =? 4(11) + 16 ?
_______________________
→ 66 − 6  =? 44 + 16 ?  → 60 =? 60 ?  Yes!
__________________
5)  The answer is: [B]: x = -11 .
_____________________
Explanation:
_________________
Given: 3(x − 4) = 5(x + 2) ; Solve for “x”. Round to the nearest tenth, if necessary.
___________
→Note the “distributive property of multiplication”: 
_____________
a*(b + c) = ab + ac ;  and: a*(b − c) = ab − ac ;
_______________
→ Let us expand EACH SIDE of our given equation.
→Start with the “left-hand side”:
____________
3(x − 4) = (3*x)  − (3*4) = 3x − 12;
______________________________
→Now let us expand the “right-hand side” of the given equation:
____________
→  5(x + 2) = (5*x) + (5*2) = 5x + 10 ;
______________
→Now, we can rewrite the original equation:
_______________
→ 3(x − 4) = 5(x + 2) ; by substituting the expanded values for EACH SIDE of the question:   →  3x − 12 = 5x + 10 ;
__________________
→ Subtract “3x” from EACH SIDE of the equation; and add “12” to EACH SIDE of the equation: →  3x − 12 − 3x + 12 = 5x + 10 − 3x + 12 ; to get:
________________
→  0 = 2x + 22;  → Now subtract “22” from EACH SIDE of the equation:
______________
→  0 − 22 = 2x + 22 − 22 ; to get:  →  -22 = 2x ;
__________
→ Divide EACH SIDE of the equation by “2”; to isolate “x” on one side of the equation; & to solve for “x” ;
_____________
→  -22 / 2 = 2x /2 ;  →  -11 = x ; which is “Answer choice: [B]”.
______________
Let us check our answer, by plugging in “-11” for “x” in the original equation:
___________
→ 3(x − 4) = 5(x + 2) ; →  3(-11 − 4) =? 5(-11 + 2) ? ; 
_______________________
→3(-15) =? 5(-9) ? ; → -45 =? -45 ?  Yes!
_____________________________________________
Hope these answers and explanations are helpful. Best of luck!

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Posted in Mathematics

Give 3 ordered pairs that satisfy the equation y=12x

To find ordered pairs that fit this equation, you just have to choose an x-value then record the answer for your y-value. you can literally go for anything you want, but it’s easiest to pick smaller values:

when x = 1…
y = 12(1)
y = 12
ordered pair: (1, 12)

when x = 0…
y = 12(0)
y = 0
ordered pair: (0, 0)

when x = 2…
y = 12(2)
y = 24
ordered pair: (2, 24)

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