Home / Assignment Help / Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers. Find the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length. 1 2 3 4 5 6 7 8 9 0 check mark ^1 ^2 ^3 ^4 ^5 ^6 ^7 ^8 ^9 ^0 X Y

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers. Find the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length. 1 2 3 4 5 6 7 8 9 0 check mark ^1 ^2 ^3 ^4 ^5 ^6 ^7 ^8 ^9 ^0 X Y

Answer:

The initial height is 5 feet.

The object will hit the ground after approximately 4.57 seconds.

Step-by-step explanation:

An object is launched into the air. The projectile motion of the object can be modeled using the function h(t) = -16t^2 + 72t + 5, where t is the time in seconds since the launch and h(t) represents the height in feet of the object after t seconds

General equation is

h(t)= -16t^2 + v_0t+h_0

V_0 is the initial velocity

h_0 is the initial height

From the given equation , the initial height is 5 feet

Initial velocity is +72 feet / sec

When the onbject hits the ground, the height becomes 0

So we plug in 0 for h(t) and solve for t

0 = -16t^2 + 72t + 5

USe quadratic formula to solve for t

t= frac{-b+-sqrt{b^2-4ac} }{2a}

a=-16, b= 72, c= 5

t= frac{-72+-sqrt{72^2-4(-16)(5)} }{2(-16)}

t= -0.06  and t= 4.568

The object will hit the ground after approximately 4.57 seconds.

To find out the height after 3 seconds, plug in 3 for t

h(t) = -16(3)^2 + 72(3) + 5=77

At t=0 , h(0) = 5

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