function has the function rule y = -7x – 2. If the input is -4, what is the output?

Posted in Mathematics

Plug in the input to the equation and you will get x=26


Related Questions

Posted in Mathematics

What is the range of the function f(x) = 3×2 + 6x – 9

I have a solution here however with a slight change in the equation:

 f(x)=3x^2-6x+1

My solution is:

The domain is all real numbers–there are no restrictions like a square root or variable in the denominator 

this is a U shape parabola and you want to find the bottom point, it is at the vertex 

x=-b/2a =- (-6) /2 (3) =1 
f(1) =3(1)^2 -6(1) +1 =3-6+1 =-2 
the minimum is (1, -2) 
so the range is all real numbers >= -2

By examining my solution, you could just answer the problem on your own! I hope it helps!

Posted in Mathematics

Solve the equation for y 2x+6y=13

So here is how we are going to solve for y for the given equation above:
2x+6y=13
Next, transfer 2x to the right side and it will look like this:
6y=13-2x
Now, divide both sides by 6, and it will look like this:
y=13-2x
    ——–
       6
So, this is the final answer for y.
Hope this answers your question. Have a great day!

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Posted in Mathematics

The discriminant of a quadratic equation is negative. One solution is 3+4i . What is the other solution? A.4-3i B.3-4i C.4+3i D.-3+4i

The way you stated the problem, there is an infinity of possibilities for the other solution. 

► For instance, the quadratic equation: 
   x² – (6 + 4i)x + (9 + 12i) = 0 
has for discriminant: 
   Δ = (6 + 4i)² – 4(9 + 12i) = 36 – 16 + 48i – 36 – 48i = -16 
which is indeed negative. 
Its solutions will then be: 
   x₁ = [(6 + 4i) + 4i]/2 = 3 + 4i 
   x₂ = [(6 + 4i) – 4i]/2 = 3 
And the other solution here is 3. 

► If you are not convinced, the quadratic equation: 
   x² – (6 + 5i)x + (5 + 15i) = 0 
has for discriminant: 
   Δ = (6 + 5i)² – 4(5 + 15i) = 36 – 25 + 60i – 20 – 60i = -9 
which is indeed negative. 
Its solutions will then be: 
   x₁ = [(6 + 5i) + 3i]/2 = 3 + 4i 
   x₂ = [(6 + 5i) – 3i]/2 = 3 + i 
And the other solution here is 3+i. 

► In fact, every quadratic equation of the form: 
   x² – [6 + (4 + α)i]x + (3 + 4i)(3 + αi) = 0 
where α is any real, has for discriminant: 
   Δ = [6 + (4 + α)i]² – 4(3 + 4i)(3 + αi) 
      = 36 – (4 + α)² + 12(4 + α)i – 36 + 16α – 12(4 + α)i 
      = 16α – (4 + α)² 
      = 16α – 16 – 8α – α² 
      = -16 + 8α – α² 
      = -(α – 4)² 
WILL be negative. 
Their solutions will then be: 
   x₁ = [ [6 + (4 + α)i] – (α – 4)i ]/2 = 3 + 4i 
   x₂ = [ [6 + (4 + α)i] + (α – 4)i ]/2 = 3 + αi 
And the other solution will then be is 3+αi. 

Since α can take any real value, you’ll obtain an infinity of solutions of the form 3+αi. 

► So conclusively: 
If the discriminant of a quadratic is negative AND one of the solutions is 3+4i, the only thing we can say about the other solution is that its real part must be 3. 

Posted in Mathematics

Each set of ordered pairs represents a function. Write a rule that represents the function. 1. (0,0),(1,4),(2,16),(3,36),(4,64) 2. (0,0),(1,0.5),(2,2),(3,4.5),(4,8)

My answer to the question is as follows:

First one looks like you are squaring the number, then multiplying the result by 4, i.e.

y=4x2

second one is similar, but instead of squaring and multiplying by 4, you are squaring and then dividing by 2

I hope my answer has come to your help. God bless and have a nice day ahead!

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Posted in Mathematics

Solve for x. round to nearest tenth if needed. 1. 7r-7=2r+18 a.r=-5 b.r=5 c.r=2.2 d.r=1.2 2. 2x+12=18-x a.x=3 b.x=10 c.x=6 d.x=2 3. 8x-3=15x+18 a.x=-3 b.x=3 c.x=2.1 d.x=0.9 4. 6y-6=4y+16 a.y=2.2 b.y=-2.2 c.y=11 d.y=5 5. 3(x-4)=5(x+2) a.x=11 b.x=-11 c.x=1 d.x=-1

1)  The answer is: [B]: r = 5 .
__________________________
Explanation:
__________________________ 
Given: 7r − 7 = 2r + 18 ; Round your answer to the nearest tenth, if necessary.
____________________________
Since “r” is the only variable given, let us assume we want to solve for “r” (instead of “x”).
___________________________
→ Subtract “2r” from EACH SIDE of the equation; and & add “7” to EACH SIDE of the equation:
_____________
→ 7r − 7 − 2r + 7 = 2r + 18 − 2r + 7 ;  to get: → 5r = 25 ;
_____________
→ Now, divide EACH SIDE of the equation by “5”; to isolate “r” on one side of the equation; and to solve for “r” :
______________
→ 5r / 5 = 25 / 5 → r = 5 → which is: “Answer choice: [B]”.
_________________
Let us check our answer, by plugging in “5” for “r” in the original equation:
_________________
 → 7r − 7 = 2r + 18 ;  →  7(5) − 7 =? 2(5) + 18? ;
______________________
→ 35 − 7 =? 10 + 18 ?;     → 28 =? 28? Yes!
______________________
 2) The answer is: [D]: x = 2 .
_____________
Explanation: 
_____________
Given: 2x + 12 = 18 − x ; Solve for “x” (round to nearest tenth, if necessary).
_______________
→ Add “x” to EACH SIDE of the equation, & subtract “12” from EACH SIDE of the equation:  → 2x + 12 + x − 12 = 18 − x + x − 12 ; 
______________
→ To get: 3x = 6 ;  → Divide EACH SIDE of the equation by “3”;
to isolate “x” on one side of the equation; and to solve for “x”:
_____________
→ 3x / 3 = 6 / 3 ; → x = 2 ; which is: “Answer choice: [D]”.
______________
Let us check our answer, by plugging in “2” for “x” in the original equation:
________________
→ 2x + 12 = 18 − x ; → 2(2) + 12 =? 18 − 2 ?
________________
→ 4 + 12 =? 18 − 2 ? ;   → 16 =? 16?  Yes!
________________________________
3)  The answer is: [A]: x = -3 . 
_____________
Explanation:
________________
Given:  8x − 3 = 15x + 18 ; Solve for “x”. Round your answer to the nearest tenth, if necessary.
_________________
→ Subtract “8x” from EACH SIDE of the equation, & add “3” to EACH SIDE of the equation:
_______________
→ 8x − 3 − 8x + 3 = 15x + 18 − 8x + 3 ; to get:
_______________
→ 0 = 7x + 21 ; → Subtract “21” from EACH SIDE of the equation;
_______________
→ 0 − 21 = 7x + 21 − 21 ; to get:
_______________
→  -21 = 7x ; Now divide EACH SIDE of the equation by “7”;
    to isolate “x” on one side of the equation; & to solve for “x”:
_______________
→ = -21 / 7 = 7x / 7 ; →  -3 = x ; which is “Answer choice: [A].”
_________________
Let us check our answer, by plugging in “-3” for “x” in the original equation:
________________
→  8x − 3 = 15x + 18 ;  → 8(-3) − 3 =?  15(-3) + 18 ?;
________________________
→ -24 − 3 =?  -45 + 18 ? ;   →  -27 =? -27?  Yes!
___________________________
4)  The answer is: [C]: y = 11 .
_____________
Explanation:
____________
Given: 6y − 6 = 4y + 16 ; Solve for “y”; Round to the nearest tenth, if necessary.
____________
(Note: Since “y” is the only variable given; assume we are to solve for “y” instead of “x”).
____________
→ Subtract “4y” from EACH SIDE of the equation, & add “6” to EACH SIDE of the equation; → 6y − 6 − 4y + 6 = 4y + 16 − 4y + 6 ; to get:
_______________
→ 2y  = 22 ; Now, divide EACH SIDE of the equation by “2”; to isolate “y” one side of the equation; and to solve for “y” ;
_______________
→ 2y / 2 = 22 / 2 ; →  y = 11 → which is “Answer choice: [C]”.
_______________________________
Let us check our answer, by plugging in “11” for “y” in the original equation:
___________________
→  6y − 6 = 4y + 16 ; → 6(11) − 6 =? 4(11) + 16 ?
_______________________
→ 66 − 6  =? 44 + 16 ?  → 60 =? 60 ?  Yes!
__________________
5)  The answer is: [B]: x = -11 .
_____________________
Explanation:
_________________
Given: 3(x − 4) = 5(x + 2) ; Solve for “x”. Round to the nearest tenth, if necessary.
___________
→Note the “distributive property of multiplication”: 
_____________
a*(b + c) = ab + ac ;  and: a*(b − c) = ab − ac ;
_______________
→ Let us expand EACH SIDE of our given equation.
→Start with the “left-hand side”:
____________
3(x − 4) = (3*x)  − (3*4) = 3x − 12;
______________________________
→Now let us expand the “right-hand side” of the given equation:
____________
→  5(x + 2) = (5*x) + (5*2) = 5x + 10 ;
______________
→Now, we can rewrite the original equation:
_______________
→ 3(x − 4) = 5(x + 2) ; by substituting the expanded values for EACH SIDE of the question:   →  3x − 12 = 5x + 10 ;
__________________
→ Subtract “3x” from EACH SIDE of the equation; and add “12” to EACH SIDE of the equation: →  3x − 12 − 3x + 12 = 5x + 10 − 3x + 12 ; to get:
________________
→  0 = 2x + 22;  → Now subtract “22” from EACH SIDE of the equation:
______________
→  0 − 22 = 2x + 22 − 22 ; to get:  →  -22 = 2x ;
__________
→ Divide EACH SIDE of the equation by “2”; to isolate “x” on one side of the equation; & to solve for “x” ;
_____________
→  -22 / 2 = 2x /2 ;  →  -11 = x ; which is “Answer choice: [B]”.
______________
Let us check our answer, by plugging in “-11” for “x” in the original equation:
___________
→ 3(x − 4) = 5(x + 2) ; →  3(-11 − 4) =? 5(-11 + 2) ? ; 
_______________________
→3(-15) =? 5(-9) ? ; → -45 =? -45 ?  Yes!
_____________________________________________
Hope these answers and explanations are helpful. Best of luck!

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Posted in Mathematics

Which rule represents the translation of hexagon DEFGHI to hexagon D’E’F’G’H’I’? (x, y)→(x – 8, y – 7) (x, y)→(x – 7, x – 8) (x, y)→(x – 4, x – 5) (x, y)→(x – 5, y – 4)

Correct answer is A.

Each vertex of the hexagon is translated 8 units left and 7 units down. So, the x-coordinate is 8 units smaller (x – 8), and the y-coordinate is 7 units smaller (y – 7).

Therefore (x, y) → (x – 8, y -7)

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