Categories
Assignment Help

While at the local bowling alley, jesse was robbed in front of a large group of people. unfortunately, no one called the police or ran to jesse’s aid. this phenomenon is a manifestation of:?

[ad_1]

Answered by answersmine AT 22/10/2019 – 02:32 AM

The phenomenon is a manifestation of diffusion of responsibility. The diffusion of responsibility is when there is a presence of others and there are consequences or events that has occured, a person involved or present around the area would likely take responsibility. It is a way of a person would think that other people around the area would be the one to take the responsibility or help the people involved or in need that the person who thinks that way won’t likely want to be involved. 

Post your answer

[ad_2]

Categories
Assignment Help

Your friends invite you to go bowling with them. The bowling alley provides bowling balls free of charge, but you'll need to rent special shoes. You'll also have to pay for each game of bowl. You and your friends want to bowl 2 games. Write a formula that will help you determine your total cost. Let's let S=shoe rental G=cost of each game C=total cost

[ad_1]

Your friends invite you to go bowling with them. The bowling alley provides bowling balls free of charge, but you’ll need to rent special shoes. You’ll also have to pay for each game of bowl. You and your friends want to bowl 2 games. Write a formula that will help you determine your total cost. Let’s let S=shoe rental G=cost of each game C=total cost

[ad_2]

Categories
Assignment Help

A bowling ball weighs 7.26 kg and takes 3.64 seconds to travel the 19.2 m length of the bowling alley. assuming the velocity is constant, what is the kinetic energy of the bowling ball?

[ad_1]

The gravitational force Fg between two objects is given by the equation:

Fg=(G*m₁*m₂)/r₂, where G=6.67*10^-11 m³ kg⁻¹ s⁻² is the gravitational constant, m₁ and m₂ are the masses of the two bodies and r is the distance between those bodies. 

Due to the gravitational attraction the pencil and the eraser will attract if we there is no friction on the surface. 

m₁=10 g=0.01 kg is the mass of the pencil
m₂=20 g=0.02 kg is the mass of the eraser
r=2.5 cm = 0.025 m

First we calculate the Fg:

Fg={(6.67*10^-11)*0.01*0.02}/(0.025²)=2.1344*10^-11 N

To get the velocity v of the pencil:

v²=2as, where a is the acceleration of the pencil and s is the path. In our case s=r so we can write:

v²=2ar

a=Fg/m₁= 2.133*10^-9 m/s²

v²=2*(2.133*10^-9)*0.025=1.0665*10^-10

v=√(1.0665*10^-10)=1.0327*10^-5 m/s

We have the velocity and the acceleration, so we can calculate the time t with the equation:

t=v/a=(1.0327*10^-5)/(2.133*10^-9)=4841.6 s

1 hour has 3600 s so when we divide time t in seconds by 3600 we get time T in hours:

T=t/3600=4841.6/3600=1.3449 h. 

So the time for the pencil and eraser to touch is T=1.3449 hours. 

Also time T can be expressed like T= 1h and 20 mins and 41.64 s

[ad_2]