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## Two different species in the same ecosystem can share a _____. population habitat carrying capacity niche

Two different species in the same ecosystem can share a _____. population habitat carrying capacity niche

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## Suppose you have a 19-foot boat. what information will be shown on your boat’s capacity plate?

If your possible answers are maximum weight and/or number of people the boat can carry safely
maximum gallons of fuel the boat can carry
minimum weight of people and/or gear needed for stability
minimum load capacity of a trailer for this boat

maximum weight and/or number of people the boat can carry safely

Maximum gallons of fuel is decided based on your tank size, while a minimum load is not as important. It’s mostly about how much weight can it carry, regardless of the form of the weight, either in people, cargo, or combined.

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## A metal sample is heated and placed into the water in a calorimeter at room temperature. Which statement best describes how the calorimeter can be used to determine the specific heat capacity of the metal sample? Energy transfers to the metal from the water and calorimeter until they are all at room temperature. Energy transfers from the metal to the water and calorimeter until they are all at room temperature. Energy transfers to the metal from the water and calorimeter until they all reach a single temperature. Energy transfers from the metal to the water and calorimeter until they all reach a single temperature.

This problem is to apply Roult’s Law.

Roult’s Law states that the vapor pressure, p, of a solution of a non-volatile solute is equal to the vapor pressure of the pure solvent, Po solv, times the mole fraction of the solvent, Xsolv

p = Xsolv * Po sol

X solv = number of moles of solvent / number of moles of solution

The solvent is water and the solute (not volatile) is glycerin.

Number of moles = mass in grams / molar mass

mass of water = 132 ml * 1 g/ml = 132 g

molar mass of water = 18 g/mol

=> number of moles of water = 132 g / 18 g/mol = 7.33333 mol

mass of glycerin = 27.2 g

molar mass of glycerin:, C3H8O3: 3 * 12 g/mol + 8 * 1 g/mol + 3*16 g/mol = 92 g/mol

number of moles of glycerin = 27.2g / 92 g/mol = 0.29565

total number of moles = 7.33333 moles + 0.29565 moles = 7.62898 moles

=> X solv = 7.33333 / 7.62898 = 0.96125

=> p = 0.96125 * 31.8 torr ≈ 30.57 torr ≈ 30.6 torr.

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## 50 POINTS AND WILL MAKE BRAINLEIST Describe the relationship between heat capacity and the temperature change of a swimming pool, Lake Michigan, and a glass of water exposed to the same amount of sunlight for the same 12 hour time period. (Hint: would one change more than the others, would any remain unchanged, or would the all remain the same)

This problem is to apply Roult’s Law.

Roult’s Law states that the vapor pressure, p, of a solution of a non-volatile solute is equal to the vapor pressure of the pure solvent, Po solv, times the mole fraction of the solvent, Xsolv

p = Xsolv * Po sol

X solv = number of moles of solvent / number of moles of solution

The solvent is water and the solute (not volatile) is glycerin.

Number of moles = mass in grams / molar mass

mass of water = 132 ml * 1 g/ml = 132 g

molar mass of water = 18 g/mol

=> number of moles of water = 132 g / 18 g/mol = 7.33333 mol

mass of glycerin = 27.2 g

molar mass of glycerin:, C3H8O3: 3 * 12 g/mol + 8 * 1 g/mol + 3*16 g/mol = 92 g/mol

number of moles of glycerin = 27.2g / 92 g/mol = 0.29565

total number of moles = 7.33333 moles + 0.29565 moles = 7.62898 moles

=> X solv = 7.33333 / 7.62898 = 0.96125

=> p = 0.96125 * 31.8 torr ≈ 30.57 torr ≈ 30.6 torr.

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## An automobile’s radiator has a capacity of fifteen quarts, and it currently contains twelve quarts of a thirty percent antifreeze solution. How many quarts of pure antifreeze must be added to strengthen the solution to forty percent? 2 quarts 3 quarts 4 quarts

Option C – BD=76 cm

Step-by-step explanation:

Given : You are designing a diamond-shaped kite. you know that AD = 44.8 cm, DC = 72 cm, and AC = 84.8 cm.

To find : How long BD should it be?

Solution :

First we draw a rough diagram.

The given sides were AD = 44.8 cm, DC = 72 cm and AC = 84.8 cm.

According to properties of kite

Two disjoint pairs of consecutive sides are congruent.

DC=BC=72 cm

The diagonals are perpendicular.

So, AC ⊥ BD

Let O be the point where diagonal intersect let let the partition be x and y.

AC= AO+OC

AC=   …….[1]

Perpendicular bisect the diagonal BD into equal parts let it be z.

BD=BO+OD

BD=z+z

Applying Pythagorean theorem in ΔAOD

where H=AD=44.8 ,P= AO=x , B=OD=z

………[2]

Applying Pythagorean theorem in ΔCOD

where H=DC=72 ,P= OC=y , B=OD=z

…………[3]

Subtract [2] and [3]

……….[4]

Add equation [1] and [4], to get values of x and y

Substitute x in [1]

Substitute value of x in equation [2], to get z

We know, BD=z+z

BD= 38.06+38.06

BD= 76.12

Nearest to whole number BD=76 cm

Therefore, Option c – BD=76 cm is correct.

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## Comparisons of cranial capacity between A. africanus and the later species H. erectus and A. boisei show that H. erectus had much larger brains, while A. boisei had only slightly larger brains, than A. africanus. There is evidence that A. africanus and H. erectus used tools, though the tools made by H. erectus required more skill and planning to craft. How do you think the toolmaking abilities of A. boisei would have compared? (A)A. boisei would have had very little ability to make tools, unlike the other two hominids.(B) A. boisei would have been able to make more advanced tools than the other two hominids. (C)A. boisei would have been able to make tools that were less advanced than H. erectus. (D)A. boisei would have made tools that were less advanced than those made by A. africanus.

The correct answer is a. Amy: wildlife in or near water = turtles, crayfish, goldfish non-water wildlife = fox, deer, bobcat.

Explanation:

According to the question students were asked to contrast their observations based on the location so according to the location, animals should be differentiated into water animals and land animals.

So turtles, crayfish, goldfish are the wildlife found in or near the water and fox, deer, bobcat are non-water animals according to their location. Therefore the correct answer is a. Amy: wildlife in or near water = turtles, crayfish, goldfish non-water wildlife = fox, deer, bobcat.

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## What is a solution that has the capacity to hold additional solute at a given temperature called? A. Unsaturated B. Saturated C. Supersaturated D. Oversaturated E. Undersaturated

This problem is to apply Roult’s Law.

Roult’s Law states that the vapor pressure, p, of a solution of a non-volatile solute is equal to the vapor pressure of the pure solvent, Po solv, times the mole fraction of the solvent, Xsolv

p = Xsolv * Po sol

X solv = number of moles of solvent / number of moles of solution

The solvent is water and the solute (not volatile) is glycerin.

Number of moles = mass in grams / molar mass

mass of water = 132 ml * 1 g/ml = 132 g

molar mass of water = 18 g/mol

=> number of moles of water = 132 g / 18 g/mol = 7.33333 mol

mass of glycerin = 27.2 g

molar mass of glycerin:, C3H8O3: 3 * 12 g/mol + 8 * 1 g/mol + 3*16 g/mol = 92 g/mol

number of moles of glycerin = 27.2g / 92 g/mol = 0.29565

total number of moles = 7.33333 moles + 0.29565 moles = 7.62898 moles

=> X solv = 7.33333 / 7.62898 = 0.96125

=> p = 0.96125 * 31.8 torr ≈ 30.57 torr ≈ 30.6 torr.

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## Prompt: Write an analytical essay in which you analyze and evaluate the British World War II propaganda directed at women. Which statement is the strongest thesis for the writing prompt? In order to show that women were essential to the war effort, the British government created a series of posters and disseminated them during the war. During the war, the British government engaged in a campaign to convince the general public that every man and woman must in some way join the war effort in order to support their country. In order to convince women to join the war effort in some capacity, the government disseminated posters that depicted them as strong, capable, and necessary for Britain’s victory. The government felt that if women worked in factories or hospitals or found another type of wartime employment, Britain would have a better chance at winning the war

Helicases unwind the two parental DNA’s strands and creates the replication fork; single strand binding proteins keep the single strand from joining.

Further information:

• DNA replication: a biological method occurring in all living organisms that is the basis for biological inheritance

Helicase: It is an enzyme that may unwinds the DNA helix ahead of the replication machinery.

Origin of replication: a specific sequence in a genome at which replication is started.

Steps of DNA replication:

• During initiation, proteins fix to the source of replication while helicase unwinds the DNA helix and two replication forks are formed at the source of replication.

• During elongation, a primer sequence is added with complementary RNA nucleotides, which are then substituted by DNA nucleotides.

• During elongation the leading strand is made constantly, while the lagging strand is made in portions called Okazaki fragments.

• During termination, primers are detached and substituted with new DNA nucleotides and the backbone is stuck down by DNA ligase.

Purpose of DNA replication:

The purpose of DNA replication is to produce two duplicate copies of a DNA molecule. This is essential for cell division during development or repair of damaged tissues. DNA replication ensures that each new cell receives its own replica of the DNA.

Subject: Biology

Level: High school

Keywords:

• DNA replication

• Helicase

• Origin of replication

• Steps of DNA replication

brainly.com/question/9434044

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## When a multi-product factory operates at full capacity, decisions must be made about which products to emphasize. in making such decisions, products should be ranked based on?

When a multi-product factory operates at full capacity, decisions must be made about which products to emphasize. in making such decisions, products should be ranked based on?

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## How many joules of heat energy would be needed to raise the temperature of 248 grams of water from 25.0 degrees Celsius to 55.0 degrees Celsius? The specific heat capacity of liquid water is 4.18J/(C x g)

How many joules of heat energy would be needed to raise the temperature of 248 grams of water from 25.0 degrees Celsius to 55.0 degrees Celsius? The specific heat capacity of liquid water is 4.18J/(C x g)

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## How are Phase 1 and Phase 2 of logistic growth different? A. A population is increasing, moving toward its carrying capacity during both phases. B. A population is at its carrying capacity during both phases. C. Population grows rapidly in Phase 1 but slows in Phase 2. D. The emigration rate is higher than the immigration rate during both phases.

Rate of transpiration will become negligible

Explanation:

Water is a polar solvent which means it can reorient its molecular structure is a way that it can have positive and negative configuration. Due to this specific characteristics , it can adhere to any surface and also it can join with any other polar molecule.

The transpiration process require lot of such physical interactions which are possible only due to the polar nature of water.

When water is substituted by any non polar solvent , then the rate of transpiration shall become negligible after some time.

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## Badwater Basin in Death Valley is covered with white salt crystals. What is likely to be true of this area? A.The white salt crystals have a high albedo. B.The white salt crystals are immune to insolation. C.The white salt crystals have no heat capacity. D.The white salt crystals absorb most radiation.

Each parent had at least one allele for white petals.

Explanation:

According to the law of inheritance, it is necessary that each offspring must inherit one allele from each of its parents for a given gene.

Since in the given question, a rose plant inherits a white flower petal allele, it is necessary that the plant must have an inherited one allele from each parent, therefore, the two parents must have had at least one allele for white petal.

The cross is shown below ,

W—> red petal

w —-> white petal

Atleast one allele => Ww X Ww —> WW Ww Ww ww

More than one allele => ww X ww —-> ww

Here ww is the offpsring with white petals.

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## Minor Electric has received a special one-time order for 1,500 light fixtures (units) at \$5 per unit. Minor currently produces and sells 7,500 units at \$6.00 each. This level represents 75% of its capacity. Production costs for these units are \$4.50 per unit, which includes \$3.00 variable cost and \$1.50 fixed cost. To produce the special order, a new machine needs to be purchased at a cost of \$1,000 with a zero salvage value. Management expects no other changes in costs as a result of the additional production. Should the company accept the special order?

The actual cash received from cash sales was \$14,356 and the amount indicated by the cash register total was \$14290

a.what is the amount deposited in the bank for the day’s sales?

14,356
Because this is the amount which is actually received by sales

b.What is amount recorded for the day’s sales?

14,290
Because this is the amount which has been recorded in the cash register.

c.How should the difference be recorded?

Dr Cash 14,356
Cr Over/Short 66
Cr Sales 14,290

d. If a cashier is consistently over or short what action should be taken?

First of all we need to find out that whether the cashier is genuinely making mistakes or there is a case of theft.There would be some close monitoring. If they are just mistakes, maybe some extra mentoring in cash handling would help.

E5-18

Part a and b are informational and thus we dont have to do anything with them.

Part c and d are reconciling terms.

Parts e and f needs entries to adjust the company’s books. For e there needs to be a debit to cash for the incorrect amount and a credit for the correct amount. For f there needs to be a credit to cash.

E.
(Dr) Cash in bank \$540
(Cr) Accounts payable \$540
\$710 – \$170

F.
(Dr) Bank charges \$50
(Cr) Cash in bank \$50

Bank reconciliation:
Cash balance per book \$24,010
Less: Debit memo \$50

Cash balance per bank \$22,750
Less: Outstanding checks \$7,350

Hope you get it.

Get back to me in case you have any doubts.
I would be happy to help.

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## An institution's evaluation of whether a person is suitable to receive credit is called: A. Credit Rating B. Compound Interest C. The three C's (character, collateral, and capacity) D. Personal profile

An institution’s evaluation of whether a person is suitable to receive credit is called: A. Credit Rating B. Compound Interest C. The three C’s (character, collateral, and capacity) D. Personal profile

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## Tank a has a capacity of 9.5 gallons. 6 1/3 gallons of the tank’s water are poured out. how many gallons of water are left in the tank?

gallons are left in the tank.

• The total capacity of the tank = 9.5 gallons
• The total amount of water poured out in gallons =

## Further Explanation

To determine the total amount left in the tank = Total capacity of the tank – Total amount of water poured out in gallons

= 9.5 (also expressed as 95/10) – (otherwise expressed as 19/3)

= 95/10 – 19/3

= (95 x 3) – (19 x 10) / 30

= (285) – (190) / 30

= 285 – 190 / 30

= 95/30

= 19/6

= gallons

The above solution to the given mathematical problem was derived as a result of following the rules of BODMAS.

The math problem has an element of fractions in it.

9.5 is the given value of the tank, and was expressed as fraction i.e 95/10 because the volume of water poured out of the tank was given as a fraction and whole number ( ), which was then factored to get a fractional value (19/3).

To determine the remaining gallons left in the tank, the Lowest Common Multiples of the denominators (30) was factored out, and is divided by the denominators and then multiplied to by the numerators of both fractions.

The derived values were subtracted from each other, and broken down to their lowest factors to finally derive the total amount of gallons of water left in the tank.