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14. Within a single use of the scientific method, which of the following steps can only be performed after data is collected? A. Controls and variables are chosen. B. The initial experiment is designed. C. The initial hypothesis is formed. D. Conclusions are drawn.

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The answer is D. Conclusions are drawn. 
This is the only choice that can be done after data gathering, formulation, and analysis.

Other choices are in correct

A. Controls and variables are chosen.  (Identified before an experiment)
B. The initial experiment is designed. (Has been planned before an experiment is done.)
C. The initial hypothesis is formed. (Before the experiment a hypothesis is already drawn.

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A family has 8 girls and 4 boys. A total of 2 children must be chosen to speak on the behalf of the family at a local benefit. What is the probability that 1 girl and 1 boy will be chosen?

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A family has 8 girls and 4 boys. A total of 2 children must be chosen to speak on the behalf of the family at a local benefit. What is the probability that 1 girl and 1 boy will be chosen?

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Witch of the following shows the use of the correct form of the past participle A. I was shocked to hear no one has fallen off that roof B. I have swam more this summer than last summer C. My little sister has finally chosen the calico cat

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Witch of the following shows the use of the correct form of the past participle A. I was shocked to hear no one has fallen off that roof B. I have swam more this summer than last summer C. My little sister has finally chosen the calico cat

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bridge hand is made up of 13 cards from a deck of 52. Find the probability that a hand chosen at random contains at least 1 nine. The probability that a bridge hand chosen at random contains at least 1 nine is:

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C(n,r) = n!/(r!(n-r)!)

You take the number of possible 13 card hands with no 9 in them and subtract that from the total number of possible 13 card hands 9’s included.

so C(52,13) – C(48,13)
The number of all possible 13 card hands is:
52!/13!(52-13)! or 52!/13!*39! which is 635,013,559,600

The number of all possible 13 card hands with no 9s is:

48!/13!(48-13)!  or 48!/13!*35! = 192,928,249,296

The difference is 635,013,559,600 – 192,928,249,296 = 442,085,310,304

So 442,085,310,304 out of 635,013,559,600 hands will have at least 1 nine.  The ratio of  442,085,310,304 to 635,013,559,600 is 0.696182472…  So roughly 70% of the time 

27,630,331,894/39,688,347,475 is the best I could do for a whole number ratio.

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The 4 aces are removed from a deck of cards. A coin is tossed and one of the aces is chosen. What is the probability of getting heads on the coin and the ace of hearts?

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The 4 aces are removed from a deck of cards. A coin is tossed and one of the aces is chosen. What is the probability of getting heads on the coin and the ace of hearts?

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Three cards are chosen from a standard deck of 52 playing cards with replacement. What is the probability every card will be an Ace? Can someone please help

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Three cards are chosen from a standard deck of 52 playing cards with replacement. What is the probability every card will be an Ace? Can someone please help

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Read the sentence and answer the question. Nine more pilots were selected in 1962 fourteen were chosen in 1963. Which correctly shows where a semicolon is needed in the sentence? Nine more pilots were selected; in 1962 fourteen were chosen in 1963. Nine more pilots were selected in 1962 fourteen were chosen; in 1963. Nine more pilots were selected in 1962; fourteen were chosen in 1963. Nine more pilots; were selected in 1962 fourteen were chosen in 1963. Description

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Read the sentence and answer the question. Nine more pilots were selected in 1962 fourteen were chosen in 1963. Which correctly shows where a semicolon is needed in the sentence? Nine more pilots were selected; in 1962 fourteen were chosen in 1963. Nine more pilots were selected in 1962 fourteen were chosen; in 1963. Nine more pilots were selected in 1962; fourteen were chosen in 1963. Nine more pilots; were selected in 1962 fourteen were chosen in 1963. Description

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His was the moment Zachary had been waiting for. He had rehearsed his lines for weeks, silently in his head as he biked to school, out loud in the mirror when he was home alone, and, to get used to an audience, in front of his sister’s stuffed animals and a slightly confused dog. Zachary had not prepared well for last year’s audition, and at the last minute had chosen not to go—too embarrassed—or too scared—he did not know which. Now, as he stood backstage, he thought about last year. He had been so disappointed in himself as he walked home alone, snuck to his room, and flopped sadly into his bed. “Next year will be different,” he vowed then and there. “I will be better prepared.” And he was. He just hoped it was enough. His throat was dry, his palms were sweaty, his heart was pounding, but he was ready to face the spotlight. A hushed silence fell across the auditorium as the drama teacher called his name. Zachary Hamilton. Based on the passage, how do you think Zachary will deal with the conflict in the remainder of the story?

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Answer:

The literary elements suggest that Zachary learned from last year and will have more success this time.

Explanation:

this time Zachary learned to come prepared so he could get the part that he wanted so you should always practice for what you want

hope this helps

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In square qrst, points u and v are midpoints. if the square has a side length of 18 mm, what is the probability that a point chosen at random in the square lies in the shaded triangle region? round the answer to the nearest thousandth. a. 0.028 b. 0.056 c. 0.125 d. 0.222

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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A box contains 60 colored balls: 45 of the balls are purple, and 30 of the purple balls have stars on them. if a purple ball being randomly chosen and a ball with stars being randomly chosen are independent events, how many of the 60 colored balls have stars on them? use conditional probability to justify your answer.

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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your friend gets chosen to play on the school soccer team but you do not. as a result you begin to feel jealous. what might a jealous reaction be towards your friend if it is not controlled? what is the healthier way of reacting?

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Charlie had a waist circumference of 47 inches and a BMI of 29 this shows that she is overweight. BMI test level is high from normal ranges shows that she is at higher risk of disease. She should lose weight and concern to the doctor.

Further Explanation:

Body mass index (BMI) is a measured value derived from the height of a person and mass.

{text{BMI}}=dfrac{{{text{mass (kg)}}}}{{{{left( {{text{height}}}right)}^2}{{left({text{m}}right)}^2}}}

BMI indicates whether the person is healthy or overweight mainly used by physicians.

• Range of BMI in a normal person is 18.5-25mathbf{kg/m}^{2}

• Range of BMI in skinfold person is 25-30mathbf{kg/m}^{2}

• Range of BMI in underweight person is 15-18.5mathbf{kg/m}^{2}

The skinfold measurement test is used to determine a person’s body fat percentage and body composition.

In this test, we are the proportion of body fat by determining skinfold thickness at pinches specific part of the body. The estimate of these folds is determined the fat beneath the skin, also called subcutaneous adipose tissue.  

The tester pinches the skin at the site and drags the fold of skin away from the muscle so only the fat tissue and skin are being held. The skinfold thickness is measured by skinfold calipers in millimeters.

Skin test includes the seven locations of the body:

1. Triceps

2. Quadriceps

3. Suprailiac

4. Pectoral

5. Subscapular

6. Midaxilla

7. Abdomen

Charlie had a waist circumference of 47 inches and a BMI of 29 this shows that she is overweight. Females with waist size 47 inches have higher risk of having disease. BMI test level is high from normal ranges shows that she is at higher risk of disease.She should lose weight and concern to the doctor.

Learn more:  

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2. Learn more about core muscle stabilization brainly.com/question/1231927

3. Learn more about energy storagehttps://brainly.com/question/523624

Answer Details:

Grade: High School

Subject: Health

Chapter: Physical Fitness

Keywords:

Body index mass, weight, doctor, triceps, abdomen, midaxilla, Quadriceps, skinfold, mass, height, pectoral.

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Half of the population of cool town owns a bicycle, and 25% of the population owns a car. if 10% of the population owns both a car and a bicycle, what is the probability that a person chosen at random from cool town owns either a car or a bicycle or both?

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Answer:  The correct option is (C). 10 = square root of the quantity of x minus 8 all squared plus y minus 9 all squared

Step-by-step explanation:  Given that the segment AB has point A located at (8, 9). The distance from A to B is 10 units.

We are to select the correct option that could be used to calculate the coordinates for point B.

Let, (x, y) be the co-ordinates of point B.

According to distance formula, the distance between two points (a, b) and (c, d) is given by

d=sqrt{(c-a)^2+(d-b)^2}.

Therefore, the distance between the points A(8, 9) and B(x, y) is given by

d=sqrt{(x-8)^2+(y-9)^2}.

Since, distance between A and B is 10 units, so

d = 10.

Therefore,

10=sqrt{(x-8)^2+(y-9)^2}.

Thus, the correct statement is

10 = square root of the quantity of x minus 8 all squared plus y minus 9 all squared.

Option (C) is correct.

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Exit A bag contains 4 red marbles and 5 blue marbles. If two marbles are chosen at random, one at a time and without replacement, what is the probability of getting two red marbles?

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Exit A bag contains 4 red marbles and 5 blue marbles. If two marbles are chosen at random, one at a time and without replacement, what is the probability of getting two red marbles?

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Kim is taking part in a group discussion about the book they are reading for class. She quickly becomes aware that the rest of the group did not prepare for this discussion. Which action is a definite sign that the group did not prepare? A. They keep flipping the pages of their books, looking for something to say. B. They seem to be very comfortable reading aloud from the textbook. C. They have chosen a section of the book that they think is important to discuss. D. They are confident when the moderator brings up a topic to discuss. 100 POINT easy question easy answer please help me

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Hey there!

Correct answer is D. Comma or Period Inside Rule

A. Question mark or exclamation point inside: those are not really necessary.

B. Colon or semicolon: not, a semicolon would divide the whole sentence and it would be shorten; a colon would work but after requested, when there is already a comma.

C. Question mark or Exclamation Point Outside Rule: would not work, becase it is an very polite and affirmative sentence.

D: A comma or period inside rule: actually, just a comma would work. Please, Cooper’s dad requested, go… Cooper’s dad requested must be in between commas as it is a vocative.

Hope this helps

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A number is chosen at random from the first twenty integers. Find the probability that the number is a multiple of 3. 3/10 3/5 6

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127=7 (mod n) means when 127 is divided by n, the division leaves a remainder of 7.

The statement is equivalent to
120=0 (mod n), meaning that n divides 120.

All divisors of 120 will satisfy the statement because 120 divided by a divisor (factor) will leave a remainder of 0.

Factors of 120 are:
n={1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120}, |n|=16.
You can count how many such values of n there are, and try to check that each one satisfies 127=7 mod n.

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“Shakespeare’s Romeo and Juliet has many themes, including the powerful nature of both love and fate. Choose one or more SECONDARY characters in the play (Tybalt, Mercutio, Nurse, Friar Lawrence, or another secondary character of your choice – NOT Romeo or Juliet) and write a 3-5 paragraph essay that discusses how this character contributes to the overall theme of the play. You may want to consider some or all of the following in your writing: – How does the secondary character you have chosen influence Romeo and/or Juliet? – How do the actions of the secondary character you have chosen impact the eventual tragic ending? – What, if anything, would have been different if this character had not been created? Would the ending be different? Why or why not? – Discuss what theme this character contributes to and how? Provide examples wherever possible.”

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Answer:  The correct answer is : When writing a research paper you should avoid: slang, first or second person, formality, contractions, jargon.

Explanation:    When writing this type of work should take into account the impersonality, not make too many subordinate sentences, use more nouns and verbs than adjectives and adverbs, use connectors when necessary, be accurate and precise, avoid metaphors, the text should be clear and understandable.

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A six person committee is chosen at from a group of 12 people. How many different committees are possible?

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Parallel lines…means ur equations will have the same slope and different y int’s.

x – 2y = 8….-2y = -x + 8….y = 1/2x – 4…slope is 1/2, y int is -4
2x + 4y = 12…4y = -2x + 12….y = -1/2x + 3…slope is – 1/2, y int is 3
not this one…different slopes

x – 2y = 8…slope is 1/2, y int is -4
2x – 4y = 12…-4y = -2x + 12…y = 1/2x – 3….slope is 1/2, y int is -3
same slope, different y int’s…..these are parallel lines..but this is not ur graph because the graph has a negative slope.

x + 2y = 8….2y = -x + 8….y = -1/2x + 4..slope is -1/2, y int is 4
2x + 4y = 12…4y = -2x + 12….y = -1/2x + 3…slope is -1/2, y int is 3
same slope, different y int’s…parallel lines…and ur y int’s match the graph…this is ur answer <===

x + 2y = 8…slope is -1/2, y int is 4
2x – 4y = 12..slope is 1/2, y int is 3
different slopes, different y int….this has 1 solution and ur lines are not parallel…not this one

therefore, ur answer is : 3rd answer choice

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When we insert a new node into a red-black tree, we set the color of the newly inserted node n to red. observe that if we had chosen to set n’s color to black, then property 4 of a red-black tree would not be violated. why didn’t we choose to set n’s color to black?

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A folder can include everything from documents and music, to applications [like Word or Excel or your favorite browser]. But computer folders can also contain other folders, lots of them, and those sub-folders can contain folders of their own. This is the called folder tree. The trunk of the tree is the Desktop. Then there are several folders like Recycle Bin, Control Panel,..The most important branch is the
one called ‘Libraries’. Here are the Photos, Music, Videos,…
Using a windows computer, to expand a branch of the folder tree you would right click beside various folders and drives to expand the folder tree.

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In how many ways can 50 cards be chosen from a standard deck of 52 cards?

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Solution:

The Given Rectangle having dimensions

Length = 80 cm

Breadth = 50 cm

Let the Six squares which has been cut from this rectangle have side of length a cm.

Area of each square = (Side)²= a²

Area of 6 Identical Squares = 6 × a²= 6 a²

If four squares are cut from four corners and two along Length,

then , Length of Box = (80 – 3 a)cm, Breadth of Box = (50 – 2 a)cm, Height = a cm

Volume of Box =V = Length × Breadth × Height

    V = (80 – 3 a)× (50 – 2 a)× a

     V   = 4000 a – 310 a² + 6 a³

For Maximum Volume

V’= 0 , where V’ = Derivative of V with respect to a.

V’= 4000 – 620 a + 18 a²

V’ =0

18 a² – 620 a + 4000= 0

9 a² – 310 a + 2000=0

using determinant method

a = frac{310pmsqrt{96100-72000}}{18}=frac{310pm155}{18}=frac{310-155}{18}=8.6 cm

V”=1 8 a – 310 = -ve

which shows , when a = 8.6 cm , volume is maximum.

So, V = 4000×8.6 – 310×(8.6)²+6×(8.6)³=15288.736 cm³

OR

If four squares are cut from four corners and two along Breadth,

then , Length of Box = (80 – 2 a)cm, Breadth of Box = (50 –  3 a)cm, Height = a cm

Volume of Box =V = Length × Breadth × Height

    V = (80 – 2 a)× (50 – 3 a)× a

     V   = 4000 a – 340 a² + 6 a³

For Maximum Volume

V’= 0 , where V’ = Derivative of V with respect to a.

V’= 4000 – 680 a + 18 a²

V’ =0

18 a² – 680 a + 4000= 0

9 a² – 340 a + 2000=0

Using Determinant method

a = frac{340pmsqrt{115600-72000}}{18}=frac{340pm209}{18}=frac{131}{18}=7.6 cm

V”=18 a -340= -ve value when a = 7.6 cm, shows volume is maximum when a = 7.6 cm

V= 4000×7.6 -340 × (7.6)² +6× (7.6)³=13395.456 cubic cm

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You want to make five-letter codes that use the letters A, F, E, R, and M without repeating any letter. What is the probability that a randomly chosen code starts with A? 0.10 0.15 0.20 0.25

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The triangle ABC is similar to triangle LMP. The order here is very important. The letters correspond to one another
A corresponds to L (first letters of each sequence) 
B corresponds to M (second letters of each sequence)
C corresponds to P (third letters of each sequence)

In a similar fashion, the segments also correspond to one another. 
AB corresponds to LM (first two letters of each sequence)
AC corresponds to LP (first and last letters of each sequence)
BC corresponds to MP (last two letters of each sequence)

————————————

AB corresponds to LM. AB is 4 units long. LM is 2 units long. So AB is twice as long as LM. This ratio (of 2:1) will be applied to every paired corresponding value.

Also, the right angle is at angle M for triangle LMP. The right angle will be at angle B for triangle ABC (since B corresponds to M). The answer will have an x coordinate of 7. So the answer is either choice B or choice C.

If we move 4 units down from point B, we land on (7,-10). That isn’t listed as an answer choice. Let’s try moving 4 units up from point B. We land on (7,-2). This is an answer choice

So the final answer is choice C) (7,-2)

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Choose one of the distribution methods. Write 1-2 paragraphs of 100-200 words that explains the distribution method that you have chosen. In your response, be sure to answer the following questions: Who receives the good or service from this distribution method? Who does not receive the good or service? What are the advantages of this method? What are the disadvantages of this method? Is this method efficient (or not wasting resources)? Is it fair (or free from bias)? Can your chosen method be used to distribute large amounts of goods and services to many people each day? Why or why not? please help me

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 Not sure if this is a “Select all that apply” question, because most of these could work. However, I’m going to assume the answer is easy movement on people, products, and ideas.Improve transportation has allowed better import and exports, faster transportation cross country, even around the world. At the same time, the answer could be increase greenhouse gases and increase pollution, because they release toxic fumes through exhaust. So, if it’s a Select all that apply question, i would select those three.

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A box contains ten cards labeled J, K, L, M, N, O, P, Q, R, and S. One card will be randomly chosen. What is the probability of choosing a letter from L to Q?

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A box contains ten cards labeled J, K, L, M, N, O, P, Q, R, and S. One card will be randomly chosen. What is the probability of choosing a letter from L to Q?

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How many ways can a president, vice-president, secretary, and treasurer be chosen from a club with 9 members? assume that no member can hold more than one office?

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Let the boxes be Box 1, Box 2, Box 3. 

consider the 3 white balls. They can be all of them in one box:

(3, 0, 0) (3 in Box 1, 0 in box 2 and 0 in box 0)
(0, 3, 0)
(0, 0, 3)

We can have 2 in one box, and 1 in one of the remaining boxes:

(2, 0, 1)
(2, 1, 0)
(0, 2, 1)
(1, 2, 0)
(0, 1, 2)
(1, 0, 2)

and there is only one way: (1, 1, 1) to place one white ball in each box

In total there are: 3+6+1=10 ways to place the white balls. Similarly there are 10 ways to place the black ones.

Since every placement of the white balls can be combined with any placement of the black balls, there are 10*10=100 ways to place the 3white balls and the 3 black bals in the boxes.

Answer: 100

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What is a papacy? the ceremony in which the pope is chosen an empire led by a pope the office of the pope all the people who follow a pope

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What is a papacy? the ceremony in which the pope is chosen an empire led by a pope the office of the pope all the people who follow a pope

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In a batch of 890 calculators, 12 were found to be defective. What is the probability that a calculator chosen at random will be defective? Write the probability as a percent. Round to the nearest tenth of a percent if necessary

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The probability of drawing a king and a queen from a deck of 52 cards is boxed{frac{8}{{663}}}.

Further explanation:

The formula of combination can be expressed as,

boxed{^n{C_r}=frac{{n!}}{{r!left({n-r}right)!}}}

The probability can be defined as the ratio of favorable number outcomes to the total number of outcomes.

boxed{{text{Probability}}=frac{{{text{Favorable number of outcomes}}}}{{{text{Total number of outcomes}}}}}

Given:

A deck contains 52 playing cards.

Calculation:

Two cards are drawn from a deck of 52 cards.

The number of total possible outcomes can be obtained as,

{text{Total Possible}}{kern 1pt}{text{ outcomes}}={{kern 1pt}^{52}}{C_2}

Substitute 52 for n and 2 for r in equation {^n{C_r}=frac{{n!}}{{r!left({n - r}right)!}}} to obtain the possible outcomes.

begin{aligned}{text{Possible}}{kern1pt}{text{outcomes}}&={{kern 1pt}^{52}}{C_2}\&=frac{{52!}}{{2!left({52 - 2}right)!}}\&=frac{{52!}}{{50!left( {2!}right)}}\&=frac{{52times51times50!}}{{50!{kern1pt}times2times1}}\&=1326\end{aligned}

There are 4 kings and 4 queens in a deck of 52 cards.

Favorable number of outcomes can be obtained as,

begin{aligned}{text{Favorable number of outcomes}}&={}^4{C_1}times {}^4{C_1}\&=4times4\&=16\end{aligned}

The probability of drawing a king and a queen from a deck of 52 cards can be obtained as,

begin{aligned}{text{Probability}}&=frac{{16}}{{1326}}\&=frac{8}{{663}}\end{aligned}

Hence, the probability of drawing a king and a queen from a deck of 52 cards is boxed{frac{8}{{663}}}.

Learn more:

1. Learn more about inverse of the function brainly.com/question/1632445

2. Learn more about range and domain of the function brainly.com/question/3412497

3. Learn more about profit and loss brainly.com/question/2479097

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Probability

Keywords: picks, king, queen, possible, outcomes, select, combination, randomly picks, a deck contains 52 cards, aces, jacks.

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