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What is 75% of the area of a circle with a circumference of 10 units? Round the solution to the nearest square unit.

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Answer:

75% of the area of the circle is 6 square units.

Step-by-step explanation:

Given:

Circumference of a circle = 10 units

Now we have to find the radius of the circle, then we have to find the area of the circle.

Circumference of a circle = 2*π*r            [π = 3.14]

2*3.14*r = 10

6.28r = 10

Dividing both side by 6.28, we get

r = 10/6.28

r = 1.59

Now let’s find the area of the circle.

The area of the circle = π*r^2

= 3.14*1.59*1.59

The area of the circle = 7.94, which is 100 %

Now we have to find the 75% of the area of the circle.

75% = 0.75

75% of the area of the circle = 0.75*7.94

= 5.95

To round off to the nearest whole number, we get 6 square units.

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A circle has an area of 12. If the radius is increased by a factor of 2, what is the new area of the circle?

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Answered by answersmine AT 22/10/2019 – 02:38 AM

A=12. A=π×r^2(area of a circle)
π×r^2=12
r×2:
π×(r×2)^2= π×r^2×4. Here you can see that the calculation is exactly the same as above except from the Factor 4. This Shows that the area is four times bigger than before: 12×4

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Each point that lies on a circle satisfies that equation for that circle

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Each point that lies on a circle satisfies that equation for that circle

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The area of circle b is 25 times greater than the area of circle a. The radius of circle a is 3. What is the radius of circle a of circle b

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The area of circle b is 25 times greater than the area of circle a. The radius of circle a is 3. What is the radius of circle a of circle b

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What’s the approximate area of a segment of a circle with a height 6 m and the length of the chord is 20 m? Round your answer to the nearest whole number. A. 746.67 m2

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Hello!

The Correct Answer to this would be 100%:

Option “85.4”.

(Work Below)

Given:
height = 6m
chord = 20 m

We need to find the radius of the circle.

20 m = 2 √ [ 6m( 2 x radius – 6 m ) ] 
20 m / 2 = 2 √[ 6m( 2 x radius – 6 m ) ] / 2 
10 m = √ [ 6m( 2 x radius – 6 m ) ] 
(10 m)² = √[ 6m( 2 x radius – 6 m ) ] ² 
100 m² = 6 m( 2 x radius – 6 m ) 
100 m² = 12 m x radius – 36 sq m 
100 m² + 36 m² = 12 m x radius – 36 m² + 36 m² 
136 m² = 12 m x radius 
136 m² / 12 m = 12 m x radius / 12 m 
11.333 m = radius 

the area beneath an arc: 

Area = r² x arc cosine [ ( r – h ) / r ] – ( r – h ) x √( 2 x r x h – h² ). 

r² = (11.333 m)² = 128.444 m² 
r – h= 11.333 m – 6 m = 5.333 m 
r * h = 11.333 m x 6 m = 68 m²

Area = 128.444 m² x arc cosine [ 5.333 m / 11.333 m ] – 5.333 m x √[ 2 x 68 m² – 36 m² ] 

Area = 128.444 m² x arc cosine [ 0.4706 ] – 5.333 m x √ [ 100m² ] 

Area = 128.444 m² x 1.0808 radians – 5.333 m x 10 m 

Area = 138.828 m² – 53.333 m² 

Area = 85.4 m²

Hope this Helps! Have A Wonderful Day! 🙂

And as Always…

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Please help meee!!!! A circle has its center at (1, 4) and a radius of 2 units. What is the equation of the circle? (x − 1)2 + (y − 4)2 = 4 (x + 2)2 + (y + 4)2 = 2 (x + 1)2 + (y − 4)2 = 4 (x − 1)2 + (y − 4)2 = 2

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Answer:

A. (x-1)^2+(y-4)^2=4

Step-by-step explanation:

We have been given that a circle has its center at (1, 4) and a radius of 2 units. We are asked to write the equation of the given circle.

Since we know that the center-radius form of circle equation is:

(x-h)^2+(y-k)^2=r^2, where (h,k) is the center of circle and r is radius of circle.

Upon substituting our given values in above format we will get,

(x-1)^2+(y-4)^2=2^2

(x-1)^2+(y-4)^2=4

Therefore, the equation of our given circle is (x-1)^2+(y-4)^2=4 and option A is the correct choice.

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The circumference of a circle can be found using c=2/pi r. use the formula to solve for the radius of a circle, r.

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Answer:  r=dfrac{C}{2pi}, where C is the circumference of the circle.

Step-by-step explanation:

We know that the formula to calculate the circumference of the circle is given by :-

C=2pi r, where r is the radius of the circle.

To find the expression for r , we divide 2pi on the both sides , we get

dfrac{C}{2pi}=r

OR

r=dfrac{C}{2pi}

Hence, the expression for r will be:-

 r=dfrac{C}{2pi}, where C is the circumference of the circle.

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What is the shortest route around the earth A) straight line across a map B) great circle route C) flying diagonally to longitudes D) winkel tripel route

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What is the shortest route around the earth A) straight line across a map B) great circle route C) flying diagonally to longitudes D) winkel tripel route

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Quadrilateral OPQR is inscribed inside a circle as shown below. Write a proof showing that angles O and Q are supplementary. It can either be two-column or paragraph.

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Quadrilateral OPQR is inscribed inside a circle as shown below. Write a proof showing that angles O and Q are supplementary. It can either be two-column or paragraph.

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A metal washer is made by cutting out a circle 13.2 mm in diameter from a larger circle. To the nearest tenth, what is the area of the washer?

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A metal washer is made by cutting out a circle 13.2 mm in diameter from a larger circle. To the nearest tenth, what is the area of the washer?

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The following graph shows the demand curve for a group of consumers in the U.S. market (blue line) for Blu-ray players. The market price of a Blu-ray player is shown by the black horizontal line at $150. Each rectangle you can place on the following graph corresponds to a particular buyer in this market: orange (square symbols) for Antonio, green (triangle symbols) for Caroline, purple (diamond symbols) for Dmitri, tan (dash symbols) for Frances, and blue (circle symbols) for Jake. Use the rectangles to shade the areas representing consumer surplus for each person who is willing and able to purchase a Blu-ray player at a market price of $150. (Note: If a person will not purchase a Blu-ray player at the market price, indicate this by leaving his or her rectangle in its original position on the palette.

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On December 15, 1791, the Bill of Rights (the first ten amendments to the United States Constitution) were ratified by the states.

The Bill of Rights were added to the Constitution to address fears raised by the Anti-Federalists during the ratification of the Constitution that the Constitution did not provide sufficient protection against abuses of power by the federal government. 

James Madison, the Father of the Constitution, originally did not think a Bill of Rights was necessary. He thought the Constitution gave no power to the federal government that would allow for a violation of the rights of the people.

Madison later changed his position, persuaded mainly by Thomas Jefferson, and, with the help of others, drafted twenty amendments that were proposed to the first United States Congress in 1789.

Twelve of the proposed amendments were accepted by Congress and were then sent to the states for ratification. Only ten were ratified.

These ten amendments list our basic rights and place limits on the federal government. They include the freedoms of speech and religion, the right to bear arms, the right to be free from unreasonable searches and seizures, and an assurance that the powers not delegated to the federal government in the Constitution are reserved to the states and the people. Many of these provisions were based upon similar protections provided by state constitutions that limited the power of state and local government authorities.

Of the remaining amendments that were not ratified in 1791, one was later adopted in 1992 as the twenty-seventh amendment to the Constitution. That amendment prevents changes in the compensation for senators and representatives until after a subsequent election of representatives. The other proposed amendment has never been adopted.

The Bill of Rights illustrates that our Founders understood that for personal freedoms to be broad, the power of the federal government must be limited.

Our nation, however, has moved away from its founding principles, especially during recent decades. Our ever-growing federal government is intervening into more and more aspects of our lives, especially through bureaucratic regulations, and is reducing our personal freedoms in the process.

Government at all levels is doing more and more things that were once left to private individuals and groups, and the federal government is doing more and more things that were once the province of state and local governments, where greater accountability to the public is often possible.

One need only look at the HHS mandate—forcing employers to violate their religious beliefs, under pain of penalty, by paying for and providing abortion pill insurance coverage—to see the harm caused by an overreaching government.

The preservation of our liberties is a daily battle, something our Founders understood. The process of scaling back the size and role of government and returning limits to it is a long one. But, since the federal government is supposed to be our servant and not our master, no one should doubt the importance of this endeavor.

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A semi- circle sits on top of a rectangle. Find it’s area and perimeter. Use 3.14 for pi. The height is 4in and the base is 3in

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Check the picture below

if the width or base of the rectangle is 3 units, that means the diameter of the semi-circle is 3, and thus the radius is half that, notice the red radius line

the area of the figure is the area of the rectangle 3×4, plus the area of the semi-circle

bf textit{area of a circle}\\
A=pi r^2\\
-------------------------------\\
textit{area of a semi-circle}\\ A=cfrac{pi r^2}{2}qquad 
begin{cases}
r=radius\
-----\
r=frac{3}{2}
end{cases}implies A=cfrac{pi frac{3^2}{2^2}}{2}implies A=cfrac{frac{9pi }{4}}{frac{2}{1}}
\\\
A=cfrac{9pi }{4}cdot cfrac{1}{2}implies A=cfrac{9pi }{8}

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Look at the figure which is the tangent to the circle? Segment OX segment RS segment PQ Segment YZ

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Look at the figure which is the tangent to the circle? Segment OX segment RS segment PQ Segment YZ

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Brenda throws a dart at this square-shaped target: Part A: Is the probability of hitting the black circle inside the target closer to 0 or 1? Explain your answer. (5 points) Part B: Is the probability of hitting the white portion of the target closer to 0 or 1? Explain your answer. (5 points)

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Either way.  The probability of hitting the circle is:

P(C)=Area of circle divided by area of square

P(W)=(area of square minus area of circle divided by area of square

P(C)=(πr^2)/s^2

P(W)=(s^2-πr^2)/s^2

Okay with know dimensions, r=1 (because r=d/2 and d=2 so r=1), s=11 we have:

P(inside circle)=π/121  (≈0.0259  or 2.6%)

P(outside circel)=(121-π)/121  (≈0.9744 or 97.4%)

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If the diameter of a circle is 8.5 kilometers, find the circumference of the circle to the nearest tenth.A. 13.4 kilometers B. 26.7 kilometers C. 39.4kilometersD. 53.4 kilometers

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If the diameter of a circle is 8.5 kilometers, find the circumference of the circle to the nearest tenth.A. 13.4 kilometers B. 26.7 kilometers C. 39.4kilometersD. 53.4 kilometers

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What is the equation of a circle with diameter line AB that has endpoints A(0,0) and B(8,6)

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The equation of a circle is
(x-h)²+(y-k)²=r²
center is (h,k) and radius is r

find the midpoint to find the center of the circle

midpoint of (x1,y1) and (x2,y2) is ((x1+x2)/2,(y1+y2)/2)
so midpoint of (0,0) and (8,6) is ((0+8)/2,(0+6)/2)=(8/2,6/2)=(4,3)

(x-4)²+(y-3)²=r²
input a point to find r
(0,0)
(0-4)²+(0-3)²=r²
16+9=r²
25=r²
5=r

anwya equation is
(x-4)²+(y-3)²=5²

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Which is an equation of a circle with center (-5,-7) The pass through the point (0,0)

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The equation of a circle that has a center at (h,k) and radius of r is
(x-h)²+(y-k)²=r²

so given center (-5,-7)
(x-(-5))²+(y-(-7))²=r²
(x+5)²+(y+7)²=r²

passes through (0,0)
sub the point to find r
(0+5)²+(0+7)²=r²
25+49=r²
74=r²

the equation is
(x+5)²+(y+7)²=74 or equivilently
(x+5)²+(y+7)²=(√74)²

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Sasha sits on a horse on a carousel 3.5 m from the center of the circle. She makes a revolution once every 8.2 seconds. What is Sasha’s tangential speed?

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Sasha sits on a horse on a carousel 3.5 m from the center of the circle. She makes a revolution once every 8.2 seconds. What is Sasha’s tangential speed?

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A 0.023 kg beetle is sitting on a record player 0.15 m from the center of the record. If it takes 0.070 N of force to keep the beetle moving in a circle on the record, what is the tangential speed of the beetle?

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Answer:

0.68 m/s

Explanation:

The centripetal force that keeps the beetle moving in circle is given by:

F=mfrac{v^2}{r}

where

m is the mass of the beetle

v is the tangential speed of the beetle

r is the distance of the beetle from the center of the record

In this problem, we know the force (F=0.070 N), the mass of the beetle (m=0.023 kg) and the distance from the center (r=0.15 m), therefore we can re-arrange the equation to find the tangential speed:

v=sqrt{frac{Fr}{m}}=sqrt{frac{(0.070 N)(0.15 m)}{0.023 kg}}=0.68 m/s

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To the nearest tenth, what is the area of a circle with circumference 35.6 centimeters?A. 100.9 cm2B. 211.8cm2C. 316.8cm2D. 403.4cm2

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To the nearest tenth, what is the area of a circle with circumference 35.6 centimeters?A. 100.9 cm2B. 211.8cm2C. 316.8cm2D. 403.4cm2

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PLEASE HELP Mr. Utterson the lawyer was a man of a rugged countenance, that was never lighted by a smile; cold, scanty and embarrassed in discourse; backward in sentiment; lean, long, dusty, dreary, and yet somehow lovable. At friendly meetings, and when the wine was to his taste, something eminently human beaconed from his eye; something indeed which never found its way into his talk, but which spoke not only in these silent symbols of the after-dinner face, but more often and loudly in the acts of his life. He was austere with himself; drank gin when he was alone, to mortify a taste for vintages; and though he enjoyed the theatre, had not crossed the doors of one for twenty years. But he had an approved tolerance for others; sometimes wondering, almost with envy, at the high pressure of spirits involved in their misdeeds; and in any extremity inclined to help rather than to reprove. "I incline to, Cain's heresy*," he used to say. "I let my brother go to the devil in his quaintly 'own way.'" In this character, it was frequently his fortune to be the last reputable acquaintance and the last good influence in the lives of down-going men. And to such as these, so long as they came about his chambers, he never marked a shade of change in his demeanour. No doubt the feat was easy to Mr. Utterson; for he was undemonstrative at the best, and even his friendship seemed to be founded in a similar catholicity of good-nature. It is the mark of a modest man to accept his friendly circle ready-made from the hands of opportunity; and that was the lawyer's way. His friends were those of his own blood or those whom he had known the longest; his affections, like ivy, were the growth of time, they implied no aptness in the object. Hence, no doubt, the bond that united him to Mr. Richard Enfield, his distant kinsman, the well-known man about town. It was a nut to crack for many, what these two could see in each other, or what subject they could find in common. It was reported by those who encountered them in their Sunday walks, that they said nothing, looked singularly dull, and would hail with obvious relief the appearance of a friend. For all that, the two men put the greatest store by these excursions, counted them the chief jewel of each week, and not only set aside occasions of pleasure, but even resisted the calls of business, that they might enjoy them uninterrupted. *The biblical story of Cain and Abel is a story about two brothers who gave offerings to God. Abel’s offering was accepted by God, but Cain’s was not. Jealous, Cain killed his brother. When God asked Cain where Abel was, Cain said, “Am I my brother’s keeper?” By saying this, Cain implied that what his brother did was his own business. (Genesis 4:1-16) What is significant about “Cain’s heresy” in this passage? A.It shows that Mr. Utterson is a deeply religious and righteous person. B.It shows that Mr. Utterson tries not to judge others or get in their business. C.It shows the Mr. Utterson wants to steal from other people’s businesses. D.It shows that Mr. Utterson does not believe in any kind of religion at all.

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PLEASE HELP Mr. Utterson the lawyer was a man of a rugged countenance, that was never lighted by a smile; cold, scanty and embarrassed in discourse; backward in sentiment; lean, long, dusty, dreary, and yet somehow lovable. At friendly meetings, and when the wine was to his taste, something eminently human beaconed from his eye; something indeed which never found its way into his talk, but which spoke not only in these silent symbols of the after-dinner face, but more often and loudly in the acts of his life. He was austere with himself; drank gin when he was alone, to mortify a taste for vintages; and though he enjoyed the theatre, had not crossed the doors of one for twenty years. But he had an approved tolerance for others; sometimes wondering, almost with envy, at the high pressure of spirits involved in their misdeeds; and in any extremity inclined to help rather than to reprove. “I incline to, Cain’s heresy*,” he used to say. “I let my brother go to the devil in his quaintly ‘own way.'” In this character, it was frequently his fortune to be the last reputable acquaintance and the last good influence in the lives of down-going men. And to such as these, so long as they came about his chambers, he never marked a shade of change in his demeanour. No doubt the feat was easy to Mr. Utterson; for he was undemonstrative at the best, and even his friendship seemed to be founded in a similar catholicity of good-nature. It is the mark of a modest man to accept his friendly circle ready-made from the hands of opportunity; and that was the lawyer’s way. His friends were those of his own blood or those whom he had known the longest; his affections, like ivy, were the growth of time, they implied no aptness in the object. Hence, no doubt, the bond that united him to Mr. Richard Enfield, his distant kinsman, the well-known man about town. It was a nut to crack for many, what these two could see in each other, or what subject they could find in common. It was reported by those who encountered them in their Sunday walks, that they said nothing, looked singularly dull, and would hail with obvious relief the appearance of a friend. For all that, the two men put the greatest store by these excursions, counted them the chief jewel of each week, and not only set aside occasions of pleasure, but even resisted the calls of business, that they might enjoy them uninterrupted. *The biblical story of Cain and Abel is a story about two brothers who gave offerings to God. Abel’s offering was accepted by God, but Cain’s was not. Jealous, Cain killed his brother. When God asked Cain where Abel was, Cain said, “Am I my brother’s keeper?” By saying this, Cain implied that what his brother did was his own business. (Genesis 4:1-16) What is significant about “Cain’s heresy” in this passage? A.It shows that Mr. Utterson is a deeply religious and righteous person. B.It shows that Mr. Utterson tries not to judge others or get in their business. C.It shows the Mr. Utterson wants to steal from other people’s businesses. D.It shows that Mr. Utterson does not believe in any kind of religion at all.

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A circle has a radius of 9 m. Find the lengths s of the arc intercepted by a central angle of 18 degrees.

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A circle has a radius of 9 m. Find the lengths s of the arc intercepted by a central angle of 18 degrees.

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What's the formula for finding area of a circle

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What’s the formula for finding area of a circle

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A 0.023 kg beetle is sitting on a record player 0.15 m from the center of the record. if it takes 0.070 n of force to keep the beetle moving in a circle on the record, what is the tangential speed of the beetle? 0.68 m/s 0.46 m/s 0.33 m/s 0.11 m/s

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Answer:

Tangential speed is 0.68 m/s

Explanation:

It is given that,

Mass of the beetle, m = 0.023 kg

It is placed at a distance of 0.15 m from the center of record i.e. r = 0.15 m.

If it takes 0.070 n of force to keep the beetle moving in a circle on the record i.e. centripetal force acting on it is, F = 0.070 N

We have to find the tangential speed of the beetle. The formula for centripetal force is given by :

F=dfrac{mv^2}{r}

v is tangential speed

v=sqrt{dfrac{Fr}{m}}

v=sqrt{dfrac{0.070times 0.15}{0.023}}

v = 0.675 m/s

or

v = 0.68 m/s

Hence, the correct option for tangential speed is (A).

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If the area of circle p is 1,600 units squared, in units what is the diameter?

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Answer:  The correct option is (C). 10 = square root of the quantity of x minus 8 all squared plus y minus 9 all squared

Step-by-step explanation:  Given that the segment AB has point A located at (8, 9). The distance from A to B is 10 units.

We are to select the correct option that could be used to calculate the coordinates for point B.

Let, (x, y) be the co-ordinates of point B.

According to distance formula, the distance between two points (a, b) and (c, d) is given by

d=sqrt{(c-a)^2+(d-b)^2}.

Therefore, the distance between the points A(8, 9) and B(x, y) is given by

d=sqrt{(x-8)^2+(y-9)^2}.

Since, distance between A and B is 10 units, so

d = 10.

Therefore,

10=sqrt{(x-8)^2+(y-9)^2}.

Thus, the correct statement is

10 = square root of the quantity of x minus 8 all squared plus y minus 9 all squared.

Option (C) is correct.

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