Categories
IT & Software

Feature Engineering for Machine Learning

Created by Soledad GalliLast updated 10/2019EnglishEnglish Subs [Auto-generated]This course includes

  • 9.5 hours on-demand video
  • 18 articles
  • 6 downloadable resources
  • Full lifetime access
  • Access on mobile and TV
  • Assignments
  • Certificate of Completion

What you’ll learn

  • Learn multiple techniques for missing data imputation
  • Transform categorical variables into numbers while capturing meaningful information
  • Learn how to deal with infrequent, rare and unseen categories
  • Transform skewed variables into Gaussian
  • Convert numerical variables into discrete
  • Remove outliers from your variables
  • Extract meaningful features from dates and time variables
  • Learn techniques used in organisations worldwide and in data competitions
  • Increase your repertoire of techniques to preprocess data and build more powerful machine learning models

Course contentall 120 lectures 09:25:37Requirements

  • A Python installation
  • Jupyter notebook installation
  • Python coding skills
  • Some experience with Numpy and Pandas
  • Familiarity with Machine Learning algorithms
  • Familiarity with Scikit-Learn

Description

NEW! Updated in November 2019 for the latest software versions, including use of new tools and open-source packages, and additional feature engineering techniques.

Welcome to Feature Engineering for Machine Learning, the most comprehensive course on feature engineering available online. In this course, you will learn how to engineer features and build more powerful machine learning models.

Who is this course for?

So, you’ve made your first steps into data science, you know the most commonly used prediction models, you perhaps even built a linear regression or a classification tree model. At this stage you’re probably starting to encounter some challenges – you realize that your data set is dirty, there are lots of values missing, some variables contain labels instead of numbers, others do not meet the assumptions of the models, and on top of everything you wonder whether this is the right way to code things up. And to make things more complicated, you can’t find many consolidated resources about feature engineering. Maybe even just blogs? So you may start to wonder: how are things really done in tech companies?

This course will help you! This is the most comprehensive online course in variable engineering. You will learn a huge variety of engineering techniques used worldwide in different organizations and in data science competitions, to clean and transform your data and variables.

What will you learn?

I have put together a fantastic collection of feature engineering techniques, based on scientific articles, white papers, data science competitions, and of course my own experience as a data scientist.

Specifically, you will learn:

  • How to impute your missing data
  • How to encode your categorical variables
  • How to transform your numerical variables so they meet ML model assumptions
  • How to convert your numerical variables into discrete intervals
  • How to remove outliers
  • How to handle date and time variables
  • How to work with different time zones
  • How to handle mixed variables which contain strings and numbers

Throughout the course, you are going to learn multiple techniques for each of the mentioned tasks, and you will learn to implement these techniques in an elegant, efficient, and professional manner, using Python, NumPy, Scikit-learn, pandas and a special open-source package that I created especially for this course: Feature- engine.

At the end of the course, you will be able to implement all your feature engineering steps in a single and elegant pipeline, which will allow you to put your predictive models into production with maximum efficiency.

Want to know more? Read on…

In this course, you will initially become acquainted with the most widely used techniques for variable engineering, followed by more advanced and tailored techniques, which capture information while encoding or transforming your variables. You will also find detailed explanations of the various techniques, their advantages, limitations and underlying assumptions and the best programming practices to implement them in Python.

This comprehensive feature engineering course includes over 100 lectures spanning about 10 hours of video, and ALL topics include hands-on Python code examples which you can use for reference and for practice, and re-use in your own projects.

REMEMBER, the course comes with a 30-day money back guarantee, so you can sign up today with no risk. So what are you waiting for? Enrol today, embrace the power of feature engineering and build better machine learning models.Who this course is for:

  • Data Scientists who want to get started in pre-processing datasets to build machine learning models
  • Data Scientists who want to learn more techniques for feature engineering for machine learning
  • Data Scientist who want to limprove their coding skills and best programming practices for feature engineering
  • Software engineers, mathematicians and academics switching careers into data science
  • Data Scientists who want to try different feature engineering techniques on data competitions
  • Software engineers who want to learn how to use Scikit-learn and other open-source packages for feature engineering

Size: 3.76 GB

Friendly Websites

Related Posts

Categories
Assignment Help

You used three methods of analysis to find the acceleration of the cart on the track: a two-point difference from v(t), an average of a(t) that was itself calculated by a succession of first differences of the v(t) data, and a line fit to v(t). some criteria to help you consider which method is best are part a in which type of graph(s) is it easiest to see whether the acceleration was constant?

[ad_1]

Answered by answersmine AT 22/10/2019 – 02:29 AM

The best way to find that you want is the line fit. When acceleration is constant the speed(v) changes smoothly every moment, so the v line must be straight. Differently, the accelaration changes.

[ad_2]

Categories
Assignment Help

Calculate the average acceleration from the following data points; V1=150m/s, v2=975m/s, t1=15s, t2=55s

[ad_1]

Calculate the average acceleration from the following data points; V1=150m/s, v2=975m/s, t1=15s, t2=55s

[ad_2]

Categories
Assignment Help

The data set shown below represents the number of times some families went out for dinner the previous week. 4, 2, 2, 0, 1, 6, 3, 2, 5, 1, 2, 4, 0, 1 Create a dot plot to represent the data. What can you conclude about the dot plot of the data set? Check all that apply. The range of the number line should be 0 to 7 to represent the frequency. Four families said they ate out twice the previous week. One family said they ate out 5 times the previous week. The data set is symmetrical. The median best represents the data set.

[ad_1]

Answer:

The correct options are:

  • Four families said they ate out twice the previous week.
  • One family said they ate out 5 times the previous week.
  • The median best represents the data set.

Step-by-step explanation:

We are given a data set as:

4, 2, 2, 0, 1, 6, 3, 2, 5, 1, 2, 4, 0, 1

On arranging this data set in the frequency table we get:

Number of times they went for dinner    Number of families  

           0                                                          2

           1                                                           3

           2                                                          4

           3                                                           1

           4                                                           2

           5                                                           1

           6                                                            1

  • Hence, the range of the number line is between 0 to 6.
  • Also there are 4 dots above 2.

    Hence,  Four families said they ate out twice the previous week.

  • Also there is one dot above 5.

        Hence,  One family said they ate out 5 times the previous week.

  • The data set is not symmetrical since the median is 2 and the data points to the left and to the right do not have symmetry.

Hence, the data set is not symmetrical.

  • Also we know that the median of the data is the central tendency of the data and always best represents the data.

Hence, The median best represents the data set.

[ad_2]

Categories
Assignment Help

In a situation where handicapped person can only input data into the computer using a stylus or light pen, which keyboard configuration might be the solution?

[ad_1]

In a situation where handicapped person can only input data into the computer using a stylus or light pen, which keyboard configuration might be the solution?

[ad_2]

Categories
Assignment Help

14. Within a single use of the scientific method, which of the following steps can only be performed after data is collected? A. Controls and variables are chosen. B. The initial experiment is designed. C. The initial hypothesis is formed. D. Conclusions are drawn.

[ad_1]

The answer is D. Conclusions are drawn. 
This is the only choice that can be done after data gathering, formulation, and analysis.

Other choices are in correct

A. Controls and variables are chosen.  (Identified before an experiment)
B. The initial experiment is designed. (Has been planned before an experiment is done.)
C. The initial hypothesis is formed. (Before the experiment a hypothesis is already drawn.

[ad_2]

Categories
Assignment Help

A data set contains three points, and two of the residuals are -6 and 12. What is the third residual

[ad_1]

A data set contains three points, and two of the residuals are -6 and 12. What is the third residual

[ad_2]

Categories
Assignment Help

Find the outlier on the set of data. 24, 21, 13, 11, 19, 34, 23, 17 i know this question was already asked before but the dumb website won't let me view it again

[ad_1]

Find the outlier on the set of data. 24, 21, 13, 11, 19, 34, 23, 17 i know this question was already asked before but the dumb website won’t let me view it again

[ad_2]

Categories
Assignment Help

The historian is more concerned with the accuracy of the data than the interpretation of it.

[ad_1]

The historian is more concerned with the accuracy of the data than the interpretation of it would be false. 
This is because both the accuracy and interpretation are important for historians. They need the accuracy of the data so they can built the accurate, or exact history. And interpretation is also very important because with interpretation they can understand and process the facts. 

HOPED THIS HELPED 🙂

[ad_2]

Categories
Assignment Help

11. Patients who have been denied health care services by their insurance companies have the right to A. validate the data. B. appeal the denial. C. pend the claim. D. confirm the diagnoses submitted by the physician.

[ad_1]

11. Patients who have been denied health care services by their insurance companies have the right to A. validate the data. B. appeal the denial. C. pend the claim. D. confirm the diagnoses submitted by the physician.

[ad_2]

Categories
Assignment Help

This type of connection is best to use when downloading large files on a network. A. Data B. Ethernet C. Router D. Wi-Fi

[ad_1]

This type of connection is best to use when downloading large files on a network. A. Data B. Ethernet C. Router D. Wi-Fi

[ad_2]

Categories
Assignment Help

Suppose you are testing different soils to determine which grows healthier bean plants. You count and record the number of leaves on each test every three days for six weeks. What type of graph would be best to display your data?

[ad_1]

Suppose you are testing different soils to determine which grows healthier bean plants. You count and record the number of leaves on each test every three days for six weeks. What type of graph would be best to display your data?

[ad_2]

Categories
Assignment Help

Which statement correctly describes the slope of the linear function that is represented by the data in the table? Table (It may move to the left a bit when it is actually posted, sorry. It shouldn’t be hard to read though) x y 8 -8 8 -4 8 0 8 4 8 8 a.The slope is positive. b.The slope is negative. c.The slope is zero. d.There is no slope.

[ad_1]

Answer: d. There is no slope.

Step-by-step explanation:

We know that slope ==frac{text{change in y coordinate}}{text{change in x coordinate}}

For the given table, since there is no change in x coordinate .

Thus the change in x coordinate is 0.

Therefore, slope==frac{text{change in y coordinate}}{0}=infty

which means the slope does not exist.

Hence, (d) is the right option. There is no slope.

[ad_2]

Categories
Assignment Help

From the table below, determine whether the data shows an exponential function. Explain why or why not. (x) -5, -4, -3, -2 (y) 0.5, 2, 8, 32 A) Yes; the domain values are at regular intervals and the range values have a common factor 8. B) Yes; the domain values are at regular intervals and the range values have a common factor 4. C) No; the domain values are not at regular intervals. D) No; the domain values are at regular intervals and the range values have a common factor 4. Please help, and please give me an explanation on the answer you choose because I need to make corrections. Please.

[ad_1]

Answer:

Option B-  Yes; the domain values are at regular intervals and the range values have a common factor 4.

Step-by-step explanation:

Given : The data

(x) -5,   -4,  -3,   -2

(y) 0.5,  2,   8,   32

To find : The data shows an exponential function or not

Solution :

The general form of an exponential form is y=ab^x

To check whether the data give the exponential function we form equation with the help of two points and verify the other two points .

y=ab^x

Let x= -5 and y=0.5

0.5=ab^{-5}

frac{0.5}{b^{-5}}=a ……[1]

Let x= -4 and y=2

2=ab^{-4}

frac{2}{b^{-4}}=a ………[2]

Equate LHS because RHS is equal in equation [1] and [2]

frac{2}{b^{-4}}=frac{0.5}{b^{-5}}

frac{b^{-4}}{b^{-5}}=frac{2}{0.5}

b=4

Put back in [2]

frac{2}{4^{-4}}=a .

a=2times4^4

a=2times256=512

a=512 and b=4

Exponential function – y=4(512)^x

To verify this function put

1) x=-3

y=512(4)^{-3}

y=farc{512}{64}

y=8

The point satisfied.

2) x=-2

y=512(4)^{-2}

y=farc{512}{16}

y=32

The point satisfied.

Therefore, The given data is an exponential function y=4(512)^x

The domain values are at regular intervals and the range values have a common factor 4 because b=4 and the change happen but value of b remain same.

Hence, Option B is correct.

Yes; the domain values are at regular intervals and the range values have a common factor 4.

[ad_2]

Categories
Assignment Help

What feature of excel allows you to automatically calculate common formulas with selected data

[ad_1]

What feature of excel allows you to automatically calculate common formulas with selected data

[ad_2]

Categories
Assignment Help

The equipment that processes data in order to create information is called the _______.

[ad_1]

The equipment that processes data in order to create information is called the _______.

[ad_2]

Categories
Assignment Help

Jason corporation has invested in a machine that cost $75,000, that has a useful life of fifteen years, and that has no salvage value at the end of its useful life. the machine is being depreciated by the straight-line method, based on its useful life. it will have a payback period of six years. given these data, the simple rate of return on the machine is closest to: (ignore income taxes in this problem.)

[ad_1]

We can solve
this problem by first calculating the annual net cash inflow. This can be
solved by remembering that:

Payback period
= Initial investment / Annual net
cash inflow


6 years = $75,000
/ Annual net
cash inflow

Therefore,
Annual net
cash inflow = $12,500
 
Next, we
calculate for the cost. The cost we will consider here is the depreciation
value of the machine.
Annual depreciation
= $75,000 / 15 years = $5,000
 
Therefore the annual net operating income is:
Annual net operating income = $12,500 – $5,000 = $7,500
 
Simple rate of
return is calculated by:
Simple rate of
return = Annual net operating income / Initial
investment
Simple rate of
return = $7,500 /
$75,000 = 0.1 = 10%

[ad_2]

Categories
Assignment Help

________ is the amount of data that can be transmitted across a transmission medium in a certain amount of time.

[ad_1]

Answered by answersmine AT 22/10/2019 – 04:53 AM

The correct word here is BANDWIDTH. Bandwidth refers to the quantity of information that a connection to the internet can handle in a given time. For digital devices, the unit of bandwidth is bytes per second. For analog devices it is expressed as cycle per second or Hertz.

Post your answer

[ad_2]

Categories
Assignment Help

When completing the morning postpartum data collection, the nurse notices the clients perineal pad is completely saturated. which action should be the nurses first response?

[ad_1]

When completing the morning postpartum data collection, the nurse notices the clients perineal pad is completely saturated. which action should be the nurses first response?

[ad_2]

Categories
Assignment Help

PLEASE HELP!!!!!! The Jonas school district gives awards to its schools based on overall student attendance. The data for attendance are shown in the table, where Low represents the fewest days attended and High represents the most days attended for a single student. School Low High Range Mean Median IRQ σ High School M 128 180 62 141 160 55.5 41.5 High School N 131 180 49 159 154 48.5 36.5 High School P 140 180 40 153 165 32.5 31.5 Part A: If the school district wants to award the school that has the most consistent attendance among its students, which high school should it choose and why? Justify your answer mathematically. Part B: If the school district wants to award the school with the highest average attendance, which school should it choose and why? Justify your answer mathematically.

[ad_1]

Answer:

High School P has the most consistent attendance among its students.

School N should be awarded for the highest average attendance.

Step-by-step explanation:

Consider the provided information.

Part A: If the school district wants to award the school that has the most consistent attendance among its students, which high school should it choose and why? Justify your answer mathematically.

Standard deviation (σ) is a measure of how a data set is spread out.

If the standard deviation is low, this implies that the information tends to be near to the set mean, whereas a high standard deviation implies that the information points are spread across a wider spectrum of values.

Therefore, for more consistency we need to look for the low standard deviation.

From the provided table we can see that the school P has low standard deviation (σ) i.e 31.5

Hence, High School P has the most consistent attendance among its students.

Part B: If the school district wants to award the school with the highest average attendance, which school should it choose and why? Justify your answer mathematically.

The formula for mean is:

Mean=frac{x_1+x_2+...+x_n}{n}

Mean is the same as average.

The sum of mean or average will be larger if each students contributes more attendance.

For highest average attendance the school with higher mean should be awarded.

Hence, School N should be awarded for the highest average attendance.

[ad_2]

Categories
Assignment Help

A normal distribution of data has a mean of 15 and a standard deviation of 4. How many standard deviations from the mean is 25? 0.16 0.4 2.5 6.25

[ad_1]

Answered by answersmine AT 22/10/2019 – 05:19 AM

This is the concept of probability, to get the number of standard deviations that 25 is from the mean, we calculate the z-score given by:
Z=(X-mean)/s.d
where;
x=25
mean=15
s.d=4
hence;
z=(25-15)/4=2.5
The answer is 2.5

[ad_2]

Categories
Assignment Help

This graph shows the number of shipwrecks in the Mediterranean Sea from 150 BC to AD 350. Which conclusion can be drawn from the data?

[ad_1]

The correct answer is A) the effects of unchecked immigration.

The political that this cartoon illustrates is the effects of unchecked immigration.

The cartoon describes a situation of immigrants. So, it illustrates the effects of unchecked immigration with so many people entering the United States with no order at all. The situation shows the risk of a lack of immigration policy could have on the country and the possible consequnences of such a few restrictions to enter the U.S.

The sign that says “Baggage the only Requisite”, showed how easy was for people to enter the United States. And the pice of paper on the floor, besides Uncle Sam, with the names of “Mafia in New Orleans”, “Anarchist in Chicago”, and “Socialist in New York”, is an example of the strong journalism critic of that time.

[ad_2]

Categories
Assignment Help

Find the sample standard deviation and the population standard deviation of the data set. 70, 58, 70, 37, 58, 47, 58, 76, 77, 67, 66, 77, 33, 74, 57

[ad_1]

Employee                                 Mary      Zoe         Greg         Ann           Tom

Cumulative Pay                       $6,800   $10,500  $8,400    $66,000   $4,700

Pay subject to FICA S.S.         $421.60  $651.00  $520.80 $4092.00 $291.40
6.2%, (First $118,000)

Pay subject to FICA Medicare $98.60 $152.25    $121.80    $957.00    $68.15
1.45% of gross

Pay subject to FUTA Taxes      $40.80  $63.00     $50.40    $396.00  $28.20
0.6%

Pay subject to SUTA Taxes   $367.20  $567.00  $453.60  $3564.00 $253.80
5.4% (First $7000)

Totals                                     $928.20 $1,433.25 $1,146.60 $9,009.00 $641.55

[ad_2]

Categories
Assignment Help

James needs to clock a minimum of 9 hours per day at work. The data set records his daily work hours, which vary between 9 hours and 12 hours, for a certain number of days. {9, 9.5, 10, 10.5, 10.5, 11, 11, 11.5, 11.5, 11.5, 12, 12}. The median number of hours James worked is . The skew of the distribution is

[ad_1]

Answer:

3 hours.          

Step-by-step explanation:

Let x be the time taken by shoe repairman to repair one pair.

We have been given that his assistant, who takes twice as long to repair a pair of shoes. So time taken by his assistant to repair one pair of shoes would be 2x.

The number of pair of shoes repaired by repairman in one hour would be frac{1}{x}.

The number of pair of shoes repaired by assistant in one hour would be frac{1}{2x}.

We have been given that together they can fix 16 pairs of shoes in an eight-hour day. We can represent this information in an equation as:

frac{1}{x}+frac{1}{2x}=frac{8}{16}

frac{1}{x}+frac{1}{2x}=frac{1}{2}

Let us have a common denominator.

frac{2*1}{2*x}+frac{1}{2x}=frac{1}{2}

frac{2}{2x}+frac{1}{2x}=frac{1}{2}

frac{2+1}{2x}=frac{1}{2}

frac{3}{2x}=frac{1}{2}  

Upon cross multiplying our equation we will get,

2x*1=3*2

2x=3*2

frac{2x}{2}=frac{3*2}{2}

x=3

Therefore, it take 3 hours for the repairman to fix one pair of shoes by himself.

[ad_2]

Categories
Assignment Help

The table below shows data from a survey about the amount of time high school students spent reading and the amount of time spent watching videos each week (without reading): Reading Video 5 1 5 4 7 7 7 10 7 12 12 15 12 15 12 18 14 21 15 26 Which response best describes outliers in these data sets? A) Neither data set has suspected outliers. B) The range of data is too small to identify outliers. C) Video has a suspected outlier in the 26-hour value. D) Due to the narrow range of reading compared to video, the video values of 18, 21, and 26 are all possible outliers.

[ad_1]

Answer with explanation:

Arranging the data in ascending order

1, 4,5,5,7,7,7,7, 10,12,12,12,12,14,15,15,15,18,21,26

There are 20 data values in data set.

Mean of data set

=frac{text{Sum of all the data values in the data set}}{text{Total number of values}}\\=frac{225}{20}\\=11.25

Since there are , even number of data values in the data set,

So, Median

=frac{(10th +11th) term}{2}\\=frac{12+12}{2}=12

First Quartile and third Quartile can be calculated directly ,using the concept of even and odd number of Observations in the data set.

Q_{1}=7, Q_{2}=15

Mode> 12

Since data values is negatively skewed, Mean < Median <Mode.

To calculate Outlier

Interquartile Range (IQR)

 =Q_{3}-Q_{1}\\ =15-7\\=8

Also, 1. Q_{1}-1.5 *IQR\\=7-1.5 *8\\=-5\\2. Q_{3}+1.5 *IQR\\=15+1.5*8\\=15+12\\=27

No, value exceeds 27, nor any value is less than -5.

So, there are no outliers in Data set, which has 20 values.

Option A:  Neither data set has suspected outliers.

[ad_2]