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The library drawer-upon-drawer file that contains information about every book in the library is called the _____. A.reference B. Reader's Guide C. card catalog D. Dewey Decimal System

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The library drawer-upon-drawer file that contains information about every book in the library is called the _____. A.reference B. Reader’s Guide C. card catalog D. Dewey Decimal System

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Rosalind company reported revenues of $111,500, expenses of $92,545, and net income of $18,955 for the year. assets totaled $200,000 at the beginning of the year and $246,000 at the end of the year. the company's return on assets for the year (round the percent to one decimal) is

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Rosalind company reported revenues of $111,500, expenses of $92,545, and net income of $18,955 for the year. assets totaled $200,000 at the beginning of the year and $246,000 at the end of the year. the company’s return on assets for the year (round the percent to one decimal) is

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A right circular cylinder has a volume of 500 cu in. If the base has a radius of 4 in., what's the altitude of the cylinder? Round your answer to two decimal places. A. 9.95 in. B. 19.79 in. C. 31.25 in. D. 29.84 in.

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A right circular cylinder has a volume of 500 cu in. If the base has a radius of 4 in., what’s the altitude of the cylinder? Round your answer to two decimal places. A. 9.95 in. B. 19.79 in. C. 31.25 in. D. 29.84 in.

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Write 15 over 16 as a decimal

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Write 15 over 16 as a decimal

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Equipment acquired at the beginning of the year at a cost of $340,000 has an estimated residual value of $45,000 and an estimated useful life of 10 years. determine the following. round your answer for the straight-line rate to one decimal place, if necessary.

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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24.51 kg round this to 1 decimal

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24.51 kg round this to 1 decimal

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Write the decimal number in standard form Six and five hundred and sixteen ten-thousandths

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Answer:

Number of copy machines must be made to minimize the unit cost=160.

Step-by-step explanation:

We are given that the unit cost function C ( the cost in dollars to make each copy machine)

If machines are made =x

Then the unit cost function is given by

C(x)=0.8x^2-256x+25939

We have to find the number of copy machines for  minimize the unit  cost

C(x)=0.8x^2-256x+25939

Differentiate with respect to x

Then we get

frac{mathrm{d}C}{mathrm{d}x}=1.6x-256 ……(equation I)

To find the value of x then we susbtitute frac{mathrm{d}C}{mathrm{d}x} is equal to zero

frac{mathrm{d}C}{mathrm{d}x}=0

1.6x-256=0

1.6x=256

x=frac{256}{1.6}

By using division property of equality

x= 160

Again differentiate the equation I with respect to x then we get

frac{mathrm{d}^2 C}{mathrm{d}^2 x}=1.6 >0

Hence, the unit cost is minimize for x=160

Therefore, the number of copy machines must be made to minimize the unit cost =160

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What is the average speed (miles/hour) for an object going 1500 feet in 1 minute. Round answer to two decimal places.

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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A toy basketball hoop for toddlers has a diameter of 10 cm. A regulation basketball hoop has a diameter of 46 cm. Determine the scale factor for the diameter of the toddler size basketball hoop to the diameter of the regulation size basketball hoop. (round answer to two decimal places)

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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A regulation soccer goal net is 24 ft wide by 8 ft high. A soccer net for children is 6 ft wide. If the manufacturer wishes to keep the children’s soccer net to scale, how tall should the children’s net be? What is the scale factor? (round answer to two decimal places)

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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Using the Dewey Decimal System, where would you look for books written in a Romance language by a stirist known as Moliere?

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Answer: The correct answer is :  a  block format

 

Explanation:    The typeface used for business correspondence is standard. Most business letters will involve routine messages that carry good or neutral news. The objective of business letters is to share neutral, good or negative news. The components of the business letters are: company letterhead, current date, inside address, salutation, body, complimentary close, written signature, and keyboarded name / title. additional components include attention line, subject line, enclosure notation, copy notation, and postscript.

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What decimal number is 1722 equal too

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The basis to respond this question are:

1) Perpedicular lines form a 90° angle between them.

2) The product of the slopes of two any perpendicular lines is – 1.

So, from that basic knowledge you can analyze each option:

a.Lines s and t have slopes that are opposite reciprocals.

TRUE. Tha comes the number 2 basic condition for the perpendicular lines.

slope_1 * slope_2 = – 1 => slope_1 = – 1 / slope_2, which is what opposite reciprocals means.

b.Lines s and t have the same slope.

FALSE. We have already stated the the slopes are opposite reciprocals.

c.The product of the slopes of s and t is equal to -1

TRUE: that is one of the basic statements that you need to know and handle.

d.The lines have the same steepness.

FALSE: the slope is a measure of steepness, so they have different steepness.

e.The lines have different y intercepts.

FALSE: the y intercepts may be equal or different. For example y = x + 2 and y = -x + 2 are perpendicular and both have the same y intercept, 2.

f.The lines never intersect.

FALSE: perpendicular lines always intersept (in a 90° angle).

g.The intersection of s and t forms right angle.

TRUE: right angle = 90°.

h.If the slope of s is 6, the slope of t is -6

FALSE. – 6 is not the opposite reciprocal of 6. The opposite reciprocal of 6 is – 1/6.

So, the right choices are a, c and g.

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Dma corporation has bonds on the market with 19.5 years to maturity, a ytm of 6.6 percent, and a current price of $1,043. the bonds make semiannual payments and have a par value of $1,000. what must the coupon rate be on these bonds? (do not round intermediate calculations. enter your answer as a percent rounded to 2 decimal places, e.g., 32.16.)

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The Contribution Margin per unit (CM) can be calculated
from the difference of Selling Price per unit (SP) and Total Expenses per unit
(TE).

 

First, let’s calculate the value of SP:

SP = Sales / Units sold

SP = $1,043,400 / 22,200 units sold

SP = $47

 

Second, calculate all expenses:

Direct materials per unit = $234,948 / 27,970 units
manufactured = $8.4

Direct labor per unit = $131,459 / 27,970 units
manufactured = $4.7

Variable manufacturing overhead per unit = $240,542 / 27,970
units manufactured = $8.6

Variable selling expenses per unit = $113,220 / 22,200
units sold = $5.1

TE = $26.8

 

Therefore the CM is:

CM = SP – TE

CM = $47 – $26.8

CM = $20.2 per unit

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In italy about 74 of every 100 people use celular telephones. Write the fraction of celular phone users in italy. Then write it as a decimal.

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Answer:  The correct option is (B) dfrac{sqrt{17}+sqrt{2}}{sqrt{17}+sqrt{2}}.

Step-by-step explanation:  We are given to select the correct fraction by which the following be multiplied to produce an equivalent fraction with a rational denominator.

F=dfrac{3}{sqrt{17}-sqrt2}~~~~~~~~~~~~~~~~~~~~~~~~(i)

We know that

to rationalize the denominator having radical terms, we multiply both numerator and denominator by a common term which contains the opposite sign before the radical term as in the original denominator.

In the given denominator, both terms are radical ones, so we can change the sign of any one of them and then multiply to the denominator and numerator simultaneously.

So, we will multiply both numerator and denominator by the term sqrt{17}+sqrt2.

From (i), we have

F\\=dfrac{3}{sqrt{17}-sqrt2}\\\=dfrac{3(sqrt{17}+sqrt{2})}{(sqrt{17}-sqrt{2})(sqrt{17}+sqrt{2})}\\\=dfrac{3(sqrt{17}+sqrt{2})}{17-2},~~~~~~~~textup{since}~(a+b)(a-b)=a^2-b^2\\\=dfrac{3(sqrt{17}+sqrt{2})}{15}\\=dfrac{sqrt{17}+sqrt{2}}{5}.

Thus, the denominator is rationalized and the required fraction to be multiplied is

dfrac{sqrt{17}+sqrt{2}}{sqrt{17}+sqrt{2}}.

Option (B) is CORRECT.

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You have $36,948.61 in a brokerage account, and you plan to deposit an additional $3,000 at the end of every future year until your account totals $280,000. you expect to earn 11% annually on the account. how many years will it take to reach your goal? round your answer to two decimal places at the end of the calculations.

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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Three cards are drawn with replacement from a standard deck. what is the probability that the first card will be a diamond, the second card will be a black card, and the third card will be an ace? express your answer as a fraction or a decimal number rounded to four decimal places.

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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Can someone answer this ASAP? I got 52 which as a decimal would be 0.52 but it was wrong. What is the correct answer?

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The basis to respond this question are:

1) Perpedicular lines form a 90° angle between them.

2) The product of the slopes of two any perpendicular lines is – 1.

So, from that basic knowledge you can analyze each option:

a.Lines s and t have slopes that are opposite reciprocals.

TRUE. Tha comes the number 2 basic condition for the perpendicular lines.

slope_1 * slope_2 = – 1 => slope_1 = – 1 / slope_2, which is what opposite reciprocals means.

b.Lines s and t have the same slope.

FALSE. We have already stated the the slopes are opposite reciprocals.

c.The product of the slopes of s and t is equal to -1

TRUE: that is one of the basic statements that you need to know and handle.

d.The lines have the same steepness.

FALSE: the slope is a measure of steepness, so they have different steepness.

e.The lines have different y intercepts.

FALSE: the y intercepts may be equal or different. For example y = x + 2 and y = -x + 2 are perpendicular and both have the same y intercept, 2.

f.The lines never intersect.

FALSE: perpendicular lines always intersept (in a 90° angle).

g.The intersection of s and t forms right angle.

TRUE: right angle = 90°.

h.If the slope of s is 6, the slope of t is -6

FALSE. – 6 is not the opposite reciprocal of 6. The opposite reciprocal of 6 is – 1/6.

So, the right choices are a, c and g.

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What is the distance between the points (22, 27) and (2, -10)? If necessary, round your answer to two decimal places. A. 57 units B. 37 units C. 31.13 units D. 42.06 units

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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Find the indicated probability. round to three decimal places. a test consists of 10 a. True b. False questions. to pass the test a student must answer at least 6 questions correctly. if a student guesses on each question, what is the probability that the student will pass the test?

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To answer this
problem, we use the binomial distribution formula for probability:

P (x) = [n!
/ (n-x)! x!] p^x q^(n-x)

Where,

n = the
total number of test questions = 10

x = the
total number of test questions to pass =   >6

p =
probability of success = 0.5

q =
probability of failure = 0.5

Given the
formula, let us calculate for the probabilities that the student will get at
least 6 correct questions by guessing.

P (6) = [10!
/ (4)! 6!] (0.5)^6 0.5^(4) = 0.205078

P (7) = [10!
/ (3)! 7!] (0.5)^7 0.5^(3) = 0.117188

P (8) = [10!
/ (2)! 8!] (0.5)^8 0.5^(2) = 0.043945

P (9) = [10!
/ (1)! 9!] (0.5)^9 0.5^(1) = 0.009766

P (10) = [10!
/ (0)! 10!] (0.5)^10 0.5^(0) = 0.000977

Total
Probability = 0.376953 = 0.38 = 38%

There is a
38% chance the student will pass.

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Among the contestants in a competition are 3636 women and 2525 men. if 5 winners are randomly? selected, find the probability that they are all? men? round to five decimal places.

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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Your parents are always complaining that you do not do enough housework. they say that you should be helping them out because you are only a student and you have a lot more spare time than them. the number of hours per week that your parents work has a mean of 48.69 hours and a standard deviation of 2.90 hours. you believe that the number of hours per week that you have to study for university has a mean of 48.17 hours and a standard deviation of 2.60 hours. you plan to record the number of hours that you study each week over 15 randomly selected weeks throughout the year. calculate the probability that the mean of your sample is greater than the mean number of hours per week worked by your parents. assume that the population of study hours per week is normally distributed. give your answer as a decimal to 4 decimal places. probability

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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Find the probability that 4 randomly selected people all have the same birthday. Ignore leap years. Round to eight decimal places.

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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Write 0.55% as a decimal and as a fraction.

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Write 0.55% as a decimal and as a fraction.

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Write the decimal 5.16 as a percent

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Answer:

The correct option is 1.

Step-by-step explanation:

It is given that Inez has to pay 4 percent in closing costs and 16 percent for the down payment on a purchase of $225,500 with an ARM.

So, Inez has to pay 20% of $225,500.

225500times frac{20}{100}=45100

Therefore Inez has to pay $45100 as closing cost and down payment.

Over the life of the loan, she will pay $262,072.72.

The total cost of her house is the sum of $262,072.72 and $45100. Because the total cost is the sum of down payment, closing cost and the payments over the life of the loan.

$262,072.72+$45100=$307,172.72

Therefore the correct option is 1.

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Through how many radians does the minute hand of a clock rotate in 25 minutes. Round answer to one decimal place.

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Greatest common factor (or denominator) is 6,
least common multiple is 180

hmm
(note:
I spent like 30 mins trying to use a math only of finding the values
but it didn’t work so I did a  force brute and elimination method
explained below)

so
a and b must be multiples of 6
so list all the multiples of 6
wait
180=6*30
and 30’s factors are 1,2,3,5,6,10,15,30 so only list the numbers that
are the result of multiplying 6 and any of those numbers in that list
(so we can have the lcm of 180)
so
6*1=6
6*2=12
6*3=18
6*5=30
6*6=36
6*10=60
6*15=90
6*30=180
these are our possible candidates for the 2 numbers
now we must find the pair that has a GCD of only 6

doing the math is long and tedious so do it yourself (trial and error)

we see that our choices that fulfill both requirements (GCD of 6 and LCM of 180) are
90&12
60&18
30&36
sum them to find the least one

90+12=102
60+18=78
30+36=66

the least possible sum is 66

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