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The library drawer-upon-drawer file that contains information about every book in the library is called the _____. A.reference B. Reader’s Guide C. card catalog D. Dewey Decimal System

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# Tag: decimal

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Rosalind company reported revenues of $111,500, expenses of $92,545, and net income of $18,955 for the year. assets totaled $200,000 at the beginning of the year and $246,000 at the end of the year. the company’s return on assets for the year (round the percent to one decimal) is

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A right circular cylinder has a volume of 500 cu in. If the base has a radius of 4 in., what’s the altitude of the cylinder? Round your answer to two decimal places. A. 9.95 in. B. 19.79 in. C. 31.25 in. D. 29.84 in.

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## Write 15 over 16 as a decimal

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Write 15 over 16 as a decimal

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So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

= **47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.**

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## 24.51 kg round this to 1 decimal

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24.51 kg round this to 1 decimal

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**Answer:**

**Number of copy machines must be made to minimize the unit cost=160.**

**Step-by-step explanation:**

We are given that the unit cost function C ( the cost in dollars to make each copy machine)

If machines are made =x

Then the unit cost function is given by

We have to find the number of copy machines for minimize the unit cost

Differentiate with respect to x

Then we get

……(equation I)

To find the value of x then we susbtitute is equal to zero

By using division property of equality

Again differentiate the equation I with respect to x then we get

Hence, the unit cost is minimize for x=160

**Therefore, the number of copy machines must be made to minimize the unit cost =160**

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So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

= **47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.**

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So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

= **47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.**

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C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

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**Answer: The correct answer is : a block format**

**Explanation: The typeface used for business correspondence is standard. Most business letters will involve routine messages that carry good or neutral news. The objective of business letters is to share neutral, good or negative news. The components of the business letters are: company letterhead, current date, inside address, salutation, body, complimentary close, written signature, and keyboarded name / title. additional components include attention line, subject line, enclosure notation, copy notation, and postscript.**

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**The basis to respond this question are:**

**1) Perpedicular lines form a 90° angle between them.**

**2) The product of the slopes of two any perpendicular lines is – 1.**

So, from that basic knowledge you can analyze each option:

**a.Lines s and t have slopes that are opposite reciprocals.**

**TRUE. Tha comes the number 2 basic condition for the perpendicular lines.**

slope_1 * slope_2 = – 1 => slope_1 = – 1 / slope_2, which is what opposite reciprocals means.

b.Lines s and t have the same slope.

FALSE. We have already stated the the slopes are opposite reciprocals.

**c.The product of the slopes of s and t is equal to -1**

**TRUE: that is one of the basic statements that you need to know and handle.**

d.The lines have the same steepness.

FALSE: the slope is a measure of steepness, so they have different steepness.

e.The lines have different y intercepts.

FALSE: the y intercepts may be equal or different. For example y = x + 2 and y = -x + 2 are perpendicular and both have the same y intercept, 2.

f.The lines never intersect.

FALSE: perpendicular lines always intersept (in a 90° angle).

**g.The intersection of s and t forms right angle.**

**TRUE: right angle = 90°.**

h.If the slope of s is 6, the slope of t is -6

FALSE. – 6 is not the opposite reciprocal of 6. The opposite reciprocal of 6 is – 1/6.

**So, the right choices are a, c and g.**

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The Contribution Margin per unit (CM) can be calculated

from the difference of Selling Price per unit (SP) and Total Expenses per unit

(TE).

First, let’s calculate the value of SP:

SP = Sales / Units sold

SP = $1,043,400 / 22,200 units sold

SP = $47

Second, calculate all expenses:

Direct materials per unit = $234,948 / 27,970 units

manufactured = $8.4

Direct labor per unit = $131,459 / 27,970 units

manufactured = $4.7

Variable manufacturing overhead per unit = $240,542 / 27,970

units manufactured = $8.6

Variable selling expenses per unit = $113,220 / 22,200

units sold = $5.1

TE = $26.8

Therefore the CM is:

CM = SP – TE

CM = $47 – $26.8

**CM = $20.2 per unit**

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**Answer: The correct option is (B) **

**Step-by-step explanation: **We are given to **select the correct fraction by which the following be multiplied to produce an equivalent fraction with a rational denominator. **

We know that

to rationalize the denominator having radical terms, **we multiply both numerator and denominator by a common term which contains the opposite sign before the radical term as in the original denominator.**

In the given denominator, both terms are radical ones, **so we can change the sign of any one of them and then multiply to the denominator and numerator simultaneously.**

**So, we will multiply both numerator and denominator by the term **

**From (i), we have**

**Thus, the denominator is rationalized and the required fraction to be multiplied is **

**Option (B) is CORRECT.**

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C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

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C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

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**The basis to respond this question are:**

**1) Perpedicular lines form a 90° angle between them.**

**2) The product of the slopes of two any perpendicular lines is – 1.**

So, from that basic knowledge you can analyze each option:

**a.Lines s and t have slopes that are opposite reciprocals.**

**TRUE. Tha comes the number 2 basic condition for the perpendicular lines.**

slope_1 * slope_2 = – 1 => slope_1 = – 1 / slope_2, which is what opposite reciprocals means.

b.Lines s and t have the same slope.

FALSE. We have already stated the the slopes are opposite reciprocals.

**c.The product of the slopes of s and t is equal to -1**

**TRUE: that is one of the basic statements that you need to know and handle.**

d.The lines have the same steepness.

FALSE: the slope is a measure of steepness, so they have different steepness.

e.The lines have different y intercepts.

FALSE: the y intercepts may be equal or different. For example y = x + 2 and y = -x + 2 are perpendicular and both have the same y intercept, 2.

f.The lines never intersect.

FALSE: perpendicular lines always intersept (in a 90° angle).

**g.The intersection of s and t forms right angle.**

**TRUE: right angle = 90°.**

h.If the slope of s is 6, the slope of t is -6

FALSE. – 6 is not the opposite reciprocal of 6. The opposite reciprocal of 6 is – 1/6.

**So, the right choices are a, c and g.**

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C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

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To answer this

problem, we use the binomial distribution formula for probability:

P (x) = [n!

/ (n-x)! x!] p^x q^(n-x)

Where,

n = the

total number of test questions = 10

x = the

total number of test questions to pass = >6

p =

probability of success = 0.5

q =

probability of failure = 0.5

Given the

formula, let us calculate for the probabilities that the student will get at

least 6 correct questions by guessing.

P (6) = [10!

/ (4)! 6!] (0.5)^6 0.5^(4) = 0.205078

P (7) = [10!

/ (3)! 7!] (0.5)^7 0.5^(3) = 0.117188

P (8) = [10!

/ (2)! 8!] (0.5)^8 0.5^(2) = 0.043945

P (9) = [10!

/ (1)! 9!] (0.5)^9 0.5^(1) = 0.009766

P (10) = [10!

/ (0)! 10!] (0.5)^10 0.5^(0) = 0.000977

**Total
Probability = 0.376953 = 0.38 = 38%**

There is a

38% chance the student will pass.

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C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

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C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

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C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

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Write 0.55% as a decimal and as a fraction.

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**Answer:**

The correct option is 1.

**Step-by-step explanation:**

It is given that Inez has to pay 4 percent in closing costs and 16 percent for the down payment on a purchase of $225,500 with an ARM.

So, Inez has to pay 20% of $225,500.

Therefore Inez has to pay $45100 as closing cost and down payment.

Over the life of the loan, she will pay $262,072.72.

The total cost of her house is the sum of $262,072.72 and $45100. Because the total cost is the sum of down payment, closing cost and the payments over the life of the loan.

Therefore the correct option is 1.

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least common multiple is 180

hmm

(note:

I spent like 30 mins trying to use a math only of finding the values

but it didn’t work so I did a force brute and elimination method

explained below)

so

a and b must be multiples of 6

so list all the multiples of 6

wait

180=6*30

and 30’s factors are 1,2,3,5,6,10,15,30 so only list the numbers that

are the result of multiplying 6 and any of those numbers in that list

(so we can have the lcm of 180)

so

6*1=6

6*2=12

6*3=18

6*5=30

6*6=36

6*10=60

6*15=90

6*30=180

these are our possible candidates for the 2 numbers

now we must find the pair that has a GCD of only 6

doing the math is long and tedious so do it yourself (trial and error)

we see that our choices that fulfill both requirements (GCD of 6 and LCM of 180) are

90&12

60&18

30&36

sum them to find the least one

90+12=102

60+18=78

30+36=66

the least possible sum is 66

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