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## ______________ is the distance traveled during a specific unit of time.

______________ is the distance traveled during a specific unit of time.

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## An object’s speed is the distance it travels _____ the amount of time it takes.

An object’s speed is the distance it travels _____ the amount of time it takes.

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## Why did the American leaders believe that US territories were safe from Japanese attack? They had negotiated an agreement for Japan’s withdrawal from China. They believed the embargo had made Japan too weak to attack. They thought the distance between the United States and Japan was too great. They expected Japan to attack Germany next.

Why did the American leaders believe that US territories were safe from Japanese attack? They had negotiated an agreement for Japan’s withdrawal from China. They believed the embargo had made Japan too weak to attack. They thought the distance between the United States and Japan was too great. They expected Japan to attack Germany next.

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## The table shows the relationship between time spent running and distance traveled in which type of model best describes the relationship

The table shows the relationship between time spent running and distance traveled in which type of model best describes the relationship

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## True or false: If you know the Pythagorean theorem, then you can always finds the distance between two points in the plain.

True or false: If you know the Pythagorean theorem, then you can always finds the distance between two points in the plain.

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## Trevor is pulling his younger brother in a wagon. He pulls the wagon 50 m to the corner with a force that is a parallel with the ground. He then turns the wagon around and pulls it 50 m back to the starting point with the same force at an angle of 30 degrees with respect to the ground. How does the amount of work Trevor performs going to the corner compare with the amount of work he performs coming back? A) they are the same because he uses the same amount of force B) they are the same because he travels the same distance C) he does less work coming back because the force moving the wagon is only 50cos30 D)he does more work coming back because the force moving the wagon is only 50cos60

Work has the greatest value when the force done is
parallel to the direction of motion. In this case, the work done in pulling the
wagon to the corner is greater than the amount of work done in pulling the
wagon back to the starting point. This is because an angle of 30 degrees is
applied when pulling it back. The formula for work when angle is applied is:

Wx = W cos θ

Where in this case, θ = 30

Therefore,
the answer to this is letter:

C) he does less work coming back because the force moving
the wagon is only 50cos30

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## John goes for a run. From his house, he jogs north for exactly 5.0 min at an average speed of 8.0 km/h. He continues north at a speed of 12.0 km/h for the next 30.0 min. He then turns around and jogs south at a speed of 15.0 km/h for 15.0 min. Then he jogs south for another 20.0 min at 8.0 km/h. He walks the rest of the way home. Which is the correct plot of total distance as a function of time for John’s jog?

John goes for a run. From his house, he jogs north for exactly 5.0 min at an average speed of 8.0 km/h. He continues north at a speed of 12.0 km/h for the next 30.0 min. He then turns around and jogs south at a speed of 15.0 km/h for 15.0 min. Then he jogs south for another 20.0 min at 8.0 km/h. He walks the rest of the way home. Which is the correct plot of total distance as a function of time for John’s jog?

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## The main difference between gases and liquids is that in gases A.the molecules are moving faster b.the forces between molecules are greater c.the distance between molecules are greater d.the molecules collide more frequently

The main difference between gases and liquids is that in gases A.the molecules are moving faster b.the forces between molecules are greater c.the distance between molecules are greater d.the molecules collide more frequently

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## Two for service watchtowers spot a fire in the distance the fire is 27 miles from tower to about how far apart are they to watch towers please help

Two for service watchtowers spot a fire in the distance the fire is 27 miles from tower to about how far apart are they to watch towers please help

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## Describe two ways in which we explore space AND describe two situations that prevent humans from long distance space travel. plz help

1. for new forms of life
2. to find new inhabitable planets.
1.humans lack the technology to travel. by the time they get to the nearest inhabitable planet it would have been centuries.
2.ships we currently have are not made for far distance travel

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## What is the definition of absolute value? a. distance from a certain number on a number line or a coordinate graph c. distance from the origin on a number line or a coordinate graph b. the opposite of a square root of a number d. none of the above

What is the definition of absolute value? a. distance from a certain number on a number line or a coordinate graph c. distance from the origin on a number line or a coordinate graph b. the opposite of a square root of a number d. none of the above

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## What is the definition of absolute value? a. distance from a certain number on a number line or a coordinate graph c. distance from the origin on a number line or a coordinate graph b. the opposite of a square root of a number d. none of the above

What is the definition of absolute value? a. distance from a certain number on a number line or a coordinate graph c. distance from the origin on a number line or a coordinate graph b. the opposite of a square root of a number d. none of the above

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## 23. A grid shows the positions of a subway stop and your house. The subway stop is located at (-5, 2) and your house is located at (-9, 9). What is the distance, to the nearest unit, between your house and the subway stop?

23. A grid shows the positions of a subway stop and your house. The subway stop is located at (-5, 2) and your house is located at (-9, 9). What is the distance, to the nearest unit, between your house and the subway stop?

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## An engineer on the ground is looking at the top of a building. The angle of elevation to the top of the building is 46°. The engineer knows the building is 250 ft tall. What is the distance from the engineer to the base of the building to the nearest whole foot?

An engineer on the ground is looking at the top of a building. The angle of elevation to the top of the building is 46°. The engineer knows the building is 250 ft tall. What is the distance from the engineer to the base of the building to the nearest whole foot?

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## As the distance between two objects decreases, what happens to the force of gravity between the two objects It remains the same It increases It decreases Itincreases or decreases, depending on the object

As the distance between two objects decreases, what happens to the force of gravity between the two objects It remains the same It increases It decreases Itincreases or decreases, depending on the object

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## Which statement best describes how work and power are different? A)To find work we need to know force and distance; to find power we need to know force and velocity. B) To find work we need to know energy and time; to find power we need to know energy and distance. C)To find work we need to know velocity and distance; to find power we need to know distance and time. D)To find work we need to know distance and force; to find power we need to know energy and velocity.

Which statement best describes how work and power are different? A)To find work we need to know force and distance; to find power we need to know force and velocity. B) To find work we need to know energy and time; to find power we need to know energy and distance. C)To find work we need to know velocity and distance; to find power we need to know distance and time. D)To find work we need to know distance and force; to find power we need to know energy and velocity.

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## A sailboat travels a distance of 2 1/2 miles in 1/6 of an hour. Which complex fraction represents the unit rate in miles per hour?

Rewrite “2 1/2 miles” as the improper fraction (5/2) miles.
Divide this by (1/6) hour:

5

2

——– (miles/hour)
1

6

To divide by the fraction 1/6, invert it and multiply.  We get

5                  6
— (miles) * ———— = (30/2) mph = 15 mph
2                  1 hour

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## About how many revolutions must a 20-inch diameter wheel make in order to travel a distance of 100 feet? A.1 1/2 B. 5 C. 9 1/2 D. 19

About how many revolutions must a 20-inch diameter wheel make in order to travel a distance of 100 feet? A.1 1/2 B. 5 C. 9 1/2 D. 19

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## In a race that consist of three parts,the cycling 12 1/2 miles long,the running part of the race was 1/4 the distance of cycling,the kayaking is 1/2 the distance running.what is the entire distance in miles of the race

In a race that consist of three parts,the cycling 12 1/2 miles long,the running part of the race was 1/4 the distance of cycling,the kayaking is 1/2 the distance running.what is the entire distance in miles of the race

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## Find the distance between point A (5,3) and point B (1,0) on a graph using the Pythagorean theorem

Find the distance between point A (5,3) and point B (1,0) on a graph using the Pythagorean theorem

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## In An Experiemnt, A Snail Was Observed To Have Moved A Distance Of 0.5 Meters In 2 Hours What Rate Movement Was Observed In This Experiment a. 4 hours per meter b. 1 meter hour c. 0.1 d.0.25 meters per hour

Rate of movement of snail, s = 0.25 meters per hour

Explanation:

It is given that,

Distance covered by snail, d = 0.5 m

The snail moved this distance in 2 hours

Since, 1 hour = 3600 seconds

So, 2 hour = 7200 seconds

We have to find the rate of movement of snail i.e. s So, s = 0.000069 m/s

Converting m/s to m/h

So, s = 0.248 m/h

or s = 0.25 meters per hour

Hence, the correct option is (d)

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## If you ran 15 km/h for 20 min, how much distance would you cover?

If you ran 15 km/h for 20 min, how much distance would you cover?

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## A ship traveled for 4 hours heading west and for 5 hours heading north. If the total distance traveled was 119 miles, and the ship traveled 5 miles per hour faster west, at what speed was the ship traveling west

To answer this problem, we will use the formula of
hypotenuse:

c^2 = a^2 + b^2

Where,

c = total distance traveled / displacement = 119 miles

a = distance traveled north = 5 hours * x mph =  5 x

b = distance traveled west = 4 hours * (x + 5) mph = 4 (x
+ 5)

Substituting to the equation:

119^2 = (5 x)^2 + [4(x + 5)]^2

14,161 = 25 x^2 + 16 (x + 5)^2

14,161 = 25 x^2 + 16 (x^2 + 10 x + 25)

14,161 = 25 x^2 + 16 x^2 + 160 x + 400

0 = 41 x^2 + 160 x – 13,761

x =[ – b ± sqrt (b^2 – 4ac)]/ 2a

x = [- 160 ± sqrt (160^2 – 4 * 41 * (– 13,761))] / 2 * 41

x = – 1.95 ± 18.42

x = -20.37 , 16.47

Since speed cannot be negative, therefore x = 16.47

Therefore the speed of the ship travelling west is:

x +

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## Calculate the speed with which the moon orbits the earth given the distance from earth to moon as R = 3.84 · 108 m. (Astronomers note that the true orbital period of the moon, is 27.3 Earth days. Interestingly, this would mean that there are approximately 13 months in a year. Use the 27.3 days/month for T – the time required for one revolution in your calculation.)

This sounds pretty easy, in fact. The orbital motion can be assumed to be circular and with constant speed. Then, the period is the time to do one revolution. The distance is the length of a revolution. That is 2*pi*R, where R is the distance between the Moon and the Earth (the respective centers to be precise). In summary, it’s like a simple motion with constant speed:

v = 2*pi*R/T,

you have R in m and T is days, which multiplied by 86,400 s/day gives T in seconds.

Then v = 2*pi*3.84*10^8/(27.3*86,400) = 1,022.9 m/s ~ 1 km/s (about 3 times the speed of sound 🙂

For the Earth around the Sun, it would be v = 2*pi*149.5*10^9/(365*86,400)~ 29.8 km/s!

I know it’s not in the problem, but it’s interesting to know how fast the Earth moves around the Sun! And yet we do not feel it (that’s one of the reasons some ancient people thought crazy the Earth not being at the center, there would be such strong winds!)

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## A fence 6 feet tall runs parallel to a tall building at a distance of 5 feet from the building. what is the length of the shortest ladder that will reach from the ground over the fence to the wall of the building?

Looks too ugly to me, but this is what I get:

First, draw the triangle of the ladder, with the fence and the building.

There are two similar right triangles: the one from the ground to the fence, and the one from the ground to the building. Let’s call L the length of the ladder and l, the length of the ladder from the ground to the fence, then:

L/(x+d) = l/x, where x is the horizontal distance from the point where the ladder touches the ground to the base of the fence and ‘d’ is the distance between the fence and the building (d=5 ft).

L = (x+d)/x*l, now l = sqrt( x^2+h^2), where h is the height of the fence (h=6 ft).

Then, one usually squares it, because the point where the maximum or minimum is attained is the same when optimizing a distance.

So that, one could look for the minimum of L^2 = (x+d)^2/x^2*(x^2+h^2), where d = 5 ft, and h = 6ft.

What I don;t like, is that L’ = dL/dx is a bit lengthy to calculate and then you have to set it = 0. I think all this is right, but I expected a somewhat simpler expression, unless you’re doing AP or similar.