Solution:

Data represented as number of hours spent in studying by Group A Students:

1,2,1,1,3,3,2,2,3

Arranging it in ascending order: 1,1,1 ,2, 2, 2, 3, 3, 3,

As number of terms is odd, The median will be middle value of observation.Which is 2.

The Data arranged in ascending order are , (1,1,1,2),2(2,3,3,3).

Median of (1,1,1,2) = =1

Median of (2,3,3,3)==3

=Interquartile Range ==3-1=2

For Data Set 2,

The Data for group B students are: 3 2 3 2 2 2 1 1 2

Arranging in ascending order: 1,1,2,2,2,2,2,3,3

total number of observation = 9

Median = 2

Arranging the data as : (1,1,2,2) 2,(2,2,3,3)

Median of (1,1,2,2)= Number of observation is 4 which is even , so Median= =

Median of (2,2,3,3)==

S=Interquartile Range = =

Interquartile range for Group A Students =Interquartile range for Group B students + 1

**Option (D) The interquartile range for Group A employees is 1 more than the interquartile range for Group B students is true.**