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Learning MEAN Stack By Building Real World Application

Learn how to build Full-Stack Web Application with Nodejs, Express, MongoDB, Angular5/6, Angular Material, and Passport

What Will I Learn?

  • Integrate Any Angular Application with Nodejs
  • CURD(Create,Read,Update,Delete) Operation with Nodejs, Express and Mongoose
  • CURD(Create,Read,Update,Delete) Operation with Nodejs, Express and Mongoose
  • JSON Web Token Authentication with PassportJs in MEAN Stack
  • Social(Twitter, Github, Google) Authentication with PassportJs in MEAN Stack
  • Send Email in Nodejs

Requirements

  • Basic NodeJS/Express and Angular Experience is required
  • Basic knowledge of HTML, CSS, and Javascript is required

Description

Today many enterprise leaders are struggling to use the diverse options available to create web development projects. With technological advancements taking place every few months, it becomes difficult to keep pace unless you are a fast learner. Just when the web development community was getting comfortable with LAMP, MEAN stack made its entry and boy it has completely redefined how web developers work.

MEAN Stack is an acronym for MongoDB, Express, Angular and Node.js – whereby all these four are integrated to form solution-built full-stack JavaScript applications.

Almost, every web development player in the market is trying to become a MEAN stack app developer.

Why MEAN Stack App Development is such a great choice?

Using the same programming language in both the front and back ends of the application has multiple benefits. For one thing, it makes data communication between server and client simpler and faster. It makes modifications to either end easier. It also promotes reusing code across the multiple technologies that in turn helps keep the application secure and stable.

1)Time Saver – as all the JavaScript libraries are combined together, it saves a lot of time for the developers as they can access all the libraries at one go. The time saved here can be used to advance the project further.

2) Speedy data storage and retrieval – MongoDB does not require any predefined regulation to establish field relations unlike MySQL database that cannot operate without predefined database schemas and rules. Moreover, addition or deletion of records is very easy in MongoDB – all thanks to the dynamic schemas that it relies on. All this ensures that the system becomes efficient and more speedy regular functions can be performed.

3) Uniform Programming Language – what works in favor of MEAN stack is that one can control both the front end and back end activities because of JSON which is compatible with MongoDB database, Express and Node.js server and Angular. As such the need for any other programming languages like PYTHON or PHP.

Furthermore, node.js framework reduces the page load time making it a hot favorite for web based applications.

4) OS Compatibility – MEAN stack is compatible with MS Windows, MAC OS and Linux. You still have doubts about the feasibility of MEAN stack?

5) Agility and Quality of Apps – the basic architecture of MEAN is set up to support automated testing; as such developers can easily make corrections as and when the situation arises. Hence one can expect agile and quality app development with MEAN stack.

6) MEAN stack supports the MVC architecture –The single programming language and flexible database of MEAN stack allows it to handle the complex procedures of MVC framework. This ensures that development work does not become tedious or less productive.

 You will learn how to:

  • Create Nodejs server with Express.js
  • Use ES6 with Nodejs
  • Create Restful APIS with Nodejs, Express and Mongoose
  • Secure Restful APIS with Passport and JWT
  • Social(Twitter, Google, Github) Authentication in Nodejs
  • CRUD(Create, Read, Update, Delete) Operation in Angular
  • Build Angular App with Angular Material, Material Data Table, and Material Dialog
  • Learn how to use Angular Material Components in Real world Application
  • JSON Web Token Authentication in Angular
  • Social(Twitter, Google, Github) Authentication in Angular
  • Generate PDF File in Nodejs
  • Download PDF File in Angular
  • Document RESTFUL APIS with Swagger
  • Send Email in Nodejs

Who is the target audience?

  • Intermediate Angular Developer who want to learn full-stack web developement
  • Nodejs Developer who want to learn full-stack web development

Created by Haider Malik
Last updated 8/2018
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Firebase Authentication Masterclass With Angular

Implement User Authentication with Facebook, Twitter, Google, Github, Email/Password, Phone, and Anonymous.

What Will I Learn?

  • Create an Angular App that showcases User Authentication
  • Implement User Authentication using social channels like Facebook, Twitter, GitHub, and Google
  • Build sign-in/sign-up experiences using pop-ups as well as redirects
  • Develop User Authentication using Phone Sign-in

Requirements

  • Sound knowledge of TypeScript
  • Working knowledge of ES6 or later
  • Hands-on experience with Angular
  • Angular CLI(1.5+) and NodeJS(Latest Version) installed.
  • A code Editor. Preferrably Visual Studio Code
  • A laptop or PC with 4 GB of RAM and around 100 GB+ of Harddisk

Description

Learn to implement User Authentication using Facebook, Twitter, Google, Github, Email/Password, Phone, and Anonymous strategies using Firebase Authentication.

We’ll start with understanding the Firebase Console. We’ll then configure and enable several sign-in methods on Firebase Authentication Providers Section. We’ll then implement User Authentication in our Angular App. Finally we’ll refactor the code.

By the end of this course, you’ll be able to implement User Authentication using social identity providers like Facebook, Google, Twitter, and GitHub. You’ll also be able to implement User Authentication using Email/Password, Phone and Anonymous strategies.Who is the target audience?

  • Beginner Angular Developers curious about Firebase Authentication.
  • Angular Developers looking to implement User Authentication with Email/Password combination, Phone Number, and social Open Identity providers like Facebook, Twitter, Google, GitHub etc.
  • Developers looking to learn implementing Social Sign-in in their apps.

Created by Siddharth Ajmera
Last updated 7/2018
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Python REST APIs with Flask, Docker, MongoDB, and AWS DevOps

Learn Python coding with RESTful API’s using the Flask framework. Understand how to use MongoDB, Docker and Tensor flow.

What you’ll learn

  • Have a deeper knowledge and understanding of core elements of web development using Python
  • Understand and be able to use the flask framework
  • Plan, build, setup and deploy a RESTful API to an Amazon EC2 instance
  • Make use of a NoSQL (MongoDB) Database
  • Build a machine-learning API using Tensorflow for image recognition

Requirements

  • Basic knowledge of the Python programming language
  • Enthusiasm and a willingness to take your Python skills to the next level

Description

So you know a bit of Python and want to learn about RESTful API’s and other cool technologies like Flask, Docker, MongoDB to name just a few?

Or maybe you just want to add web development Python skills to your resume.

Whatever the reason is, you have landed on the right page if you have an interest in taking your Python skills to the next level.

Why use Python for web development?

Coding in Python is simple, and a student with no prior knowledge can easily understand a line of code and its use – this means with only the basics, you can comfortably write a complete program.

Python has a great number of frameworks and tools to get you up and going fast with web development.

It’s a great match – a powerful language with a great range of tools that you can put to use quickly.

Why choose this course?

  • You will be able to learn and understand how to design and implement RESTful API’s via the Flask framework.
  • Ever wanted to know what a NoSQL database is, and how to use one?  You’ll learn how to do that as well, using Python.
  • And what is Docker, and what does it mean to “dockerize” your apps?  Yep, you guessed it, you will learn that as well in this course.
  • You’ll even learn how to build a machine learning API using TensorFlow for image recognition.
  • Another hot topic is DevOps, and you will learn about that and go through the process of deploying a RESTful API on an Amazon EC2 instance.
  • In short, this course is designed to take your basic Python skills and take you to the next level in the shortest period of time.

What topics are covered in this course?

Understanding the Basics of the Python Flask Framework

Understanding and Implementing a  REST API

Docker

MongoDB

Project: Database as a Service Restful API

Project: Building a Restful API for similarity check using Natural Language Processing

Project: Building an Image Recognition Restful API using Tensorflow and Deep Learning

Project: Building a Restful API to Handle Bank Transactions

Deploying Restful API into an AWS EC2 Instance

You’ll come away with a firm understanding of how all the pieces work individually, and more importantly how they fit together.

This really is an all in one course to get you up to speed with these topics, fast.

What skills do you need?

The ideal student would be someone with a basic knowledge of Python who is eager to improve their skills.  That’s it!

Ready to start?

If you’re ready to start the course, then click the enroll button to get started. We look forward to seeing you on the inside.oWho this course is for:

  • This course is suitable for those with basic skills, who wish to learn about Python web development
  • This course is ideal for those who wish to learn more about RESTful API’s
  • Anyone with an interest in database,DevOps, MongoDb and more

Created by Tim Buchalka’s Learn Programming Academy, El Farouk Yasser
Last updated 11/2018
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React + Redux: Fundamentos e Duas Apps do ABSOLUTO ZERO!

Created by Leonardo Moura Leitao
Last updated 6/2017
Portuguese
What Will I Learn?

  • Configurar uma aplicação com Webpack
  • Criar componentes em React
  • Integrar o Redux em uma aplicação React
  • Desenvolver uma aplicação do zero com React/Redux
  • Desenvolver uma aplicação full-stack em Javascript
  • Aplicar boas práticas de desenvolvimento

Requirements

  • É importante que o aluno conheça o básico da linguagem Javascript
  • É importante que o aluno conheça o básico de HTML

Description

O principal objetivo de um desenvolvedor de software é sem
dúvida construir aplicações, então que tal construir duas aplicação do
absoluto zero usando o principal framework web do mercado?

A proposta desse curso é te guiar passo a passo na construções de
duas aplicações completas, mas se você ainda está iniciando no mundo do
React, não tem problema porque antes de entrarmos no desenvolvimento das
aplicações, serão apresentados vários exercícios para ensinar os
fundamentos de Webpack, React, Redux e todo o ecossistema envolvido no
processo. Inclusive tecnologias de backend, como Node, Express e
MongoDB.

Falaremos desde o básico, mostrando os primeiros passos, até assuntos
complexos como geração de formulários dinâmicos e middlewares.

Curso 100% prático, mas sempre deixando muito claro os conceitos
essenciais para que o aluno aprenda os princípios associados à prática.

Tenho certeza que esse curso te dará uma visão bastante robusta sobre desenvolvimento Web com Javascript!

Seja muito bem vindo!
Who is the target audience?

  • Programadores Javascript que desejem aprender a desenvolver aplicações profissionais
  • Programadores que desejem aprender React
  • Programadores que desejem aprender React com Redux
  • Programadores que desejem aprender a desenvolver uma aplicação do zero

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MEVP Stack Vue JS 2 Course: MySQL + Express.Js + Vue.Js +PHP

  • Basic JavaScript knowledge is needed
  • You should know what is a class and how to instantiate it into an object
  • You should know how to use object properties and methods

Description

If all you still think jQuery can completely replace JavaScript and want to learn Vue.JS, then this course is PERFECT for you because you will learn EVERYTHING you need here. 

Minumum Requirement:

This course is designed for students with zero ES6 foundation, BUT you do need to know basic ES5. If you know how to set background color for a DIV using native JavaScript and jQuery, then you are good to go.

Set a background color…

Course Contents: 

This course has 46 sections and covers 17 areas:

  1. Vue JS Basics (Section 1-27)
  2. Ajax (Section 28)
  3. Connecting Vue to PHP and MySQL (Section 29)
  4. Command Line Instrument (Section 30)
  5. NPM (Section 31)
  6. Babel (Section 32)
  7. JS modular system, including module.exports, import and export (Section 33)
  8. Webpack (Section 33)
  9. Vue CLI (Section 34)
  10. Vue Single-file Components (Section 34)
  11. Vue Router (Section 35)
  12. VueX (Section 36)
  13. Axios (Section 37, 38, and 39)
  14. Vue UI Library: iView (Section 40)
  15. Advanced JavaScript: scope, scope chain, JavaScript Garbage Collection, Closure, IIFE(Instantly Invoked Function Expression), THIS, etc.
  16. Node.js and Express.js
  17. Connecting Vue to Express and MySQL

Note: The Vue version taught in this lesson will be 2.0+

Content Description:

Your VueJS study is made of two stages.

In stage one, you will learn Vue basics like Vue instance, directives, components, etc.

In stage two, you will learn Vue single file component, Vue router, VueX and a Vue UI library called iView.

Between stage one and two, you will learn command line, npm, Babel, and Webpack. You need these skills to take the leap from stage one to stage two.

By the way, skills you learn between stage one and stage two are not just for Vue. You will also need them when you are learning other modern JS-based frameworks.

A frontend program alone is useless until it is connected to backend program and database.

We will teach you how to connect Vue to PHP and MySQL via Ajax and Ajax-based techs like Axios.

Throughout the course, you will be working on several projects so that you will always have a chance to practice and apply what you have learnt.   

Who this course is for:

  • Anyone who wants to learn how to create front-end APPs using Vue
  • Anyone who wants to learn how to use command line instrument
  • Anyone who wants to learn how to use NPM
  • Anyone who wants to learn how to use Babel
  • Anyone who wants to learn how to use Webpack
  • Anyone who wants to develop single page applications using dot vue files
  • Anyone who want to learn how to use vue router, vuex and axios
  • Anyone who wants to learn how to use Express and nodejs
  • Anyone who wants to learn how to develop apps using Vuejs, PHP and MySQL
  • Anyone who wants to learn how to develop apps using vuejs, Expressjs and MySQL

Created by OnlyKiosk Tech
Last updated 12/2018
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What belief does Hughes express that whitman does not

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What belief does Hughes express that whitman does not

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2. Which sentence’s verbs express simultaneous events? I am pleased to have done well on the test. Having done well on the text, I will be pleased. I knew that I did well on the test. Having done well on the test, I am pleased.

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The correct answer is C. I knew that I did well on the test

Explanation:

Simultaneous events means when two events happen at the same time, it means there is no a difference in time between one event and the other, this simultaneity in language is usually expressed in the tense used to express the action or event, in this way, if the same tense is used to express two actions it is more likely those actions are simultaneous, as different tenses would express an explicit difference in the time the actions occurred. In the case of option C. “I knew that I did well on the test”, both actions which are “I knew” and “I did” are in simple past, which make them simultaneous, also it is possible both actions occurred at the same time as both actions can be carried out by a person at the same time. Thus, the sentence that expresses simultaneous events is C. I knew that I did well on the test, as it is the only option in which both actions are in the same tense and these actions can occur simultaneously.

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A car gets 32 mpg. How many kilometers per gallon is this? Express your answer rounded to the nearest tenth of a kilometer per gallon.

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A car gets 32 mpg. How many kilometers per gallon is this? Express your answer rounded to the nearest tenth of a kilometer per gallon.

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Express the polar coordinates (-3, pi/2) as Cartesian coordinates. Choices: (-3,0) (-3,3) (0,-3) (3,-3)

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Express the polar coordinates (-3, pi/2) as Cartesian coordinates. Choices: (-3,0) (-3,3) (0,-3) (3,-3)

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What hanging mass will stretch a 2.1-m-long, 0.43 mm – diameter steel wire by 1.5 mm ? the young’?s modulus of steel is 20×1010n/m2. express your answer using two significant figures?

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The force (weight) due to the hanging mass is
F = mg
where
m = mass, kg
g = 9.8 m/s²

The cross sectional area of the wire is
A = (π/4)*(0.43×10⁻³ m)² = 1.4522×10⁻⁷ m²

The stress in the wire is
σ = F/A = (9.8m N)/(1.4522×10⁻⁷ m²) = 6.7484×10⁷m Pa

The length of the wire is 2.1 m and the extension is 1.5 mm. Therefore the induced strain is
ε = (1.5×10⁻³ m)/(2.1 m) = 7.1429×10⁻⁴

By definition, Young’s modulus is E = σ/ε. Therefore
(6.7484×10⁷m Pa)/(7.1429×10⁻⁴) = 20×10¹⁰ Pa
9.4477×10¹⁰m = 20×10¹⁰
m = 2.117 kg 

Answer: 2.12 kg (to two sig. figures)

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Express the series using sigma notation. 5 + 8 + 11 + 14 + 17…

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So we see that each term is 3 more than the previous
so
we start with an=a1+d(n-1)
an=nth term
a1=first term
d=common difference
n=which term

first term is 5 and common differnce is 3
an=5+3(n-1)
an=5+3n-3
an=2+3n

so

ok, sigma notation
sumlimits^b_{n=a} {f(n)}
n=index of summation
a=first value of n
b=last value of n
and f(n) is the formula for the terms
so

the formula is 2+3n
the first value is 1
the last is ∞
so
sumlimits^infty_{n=1} {3n+2} represents the series

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Express the polynomial 6e^2+3e^3+1 in standard form and then classify it.

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The basis to respond this question are:

1) Perpedicular lines form a 90° angle between them.

2) The product of the slopes of two any perpendicular lines is – 1.

So, from that basic knowledge you can analyze each option:

a.Lines s and t have slopes that are opposite reciprocals.

TRUE. Tha comes the number 2 basic condition for the perpendicular lines.

slope_1 * slope_2 = – 1 => slope_1 = – 1 / slope_2, which is what opposite reciprocals means.

b.Lines s and t have the same slope.

FALSE. We have already stated the the slopes are opposite reciprocals.

c.The product of the slopes of s and t is equal to -1

TRUE: that is one of the basic statements that you need to know and handle.

d.The lines have the same steepness.

FALSE: the slope is a measure of steepness, so they have different steepness.

e.The lines have different y intercepts.

FALSE: the y intercepts may be equal or different. For example y = x + 2 and y = -x + 2 are perpendicular and both have the same y intercept, 2.

f.The lines never intersect.

FALSE: perpendicular lines always intersept (in a 90° angle).

g.The intersection of s and t forms right angle.

TRUE: right angle = 90°.

h.If the slope of s is 6, the slope of t is -6

FALSE. – 6 is not the opposite reciprocal of 6. The opposite reciprocal of 6 is – 1/6.

So, the right choices are a, c and g.

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Find the quotient of 5+4i/6+8i , and express it in the simplest form

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Find the quotient of 5+4i/6+8i , and express it in the simplest form

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Calculate the answer. Express it in scientific notation. All answers should have the correct number of significant figures. (386) (204) =

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Answer:

Velocity of plane = 30.93 m/s

Explanation:

Considering vertical motion of ball

    Initial velocity, u =  0 m/s

   Acceleration , a = 9.81 m/s²

   Displacement, s = 195 m

   We have equation of motion s= ut + 0.5 at²

   Substituting

       s= ut + 0.5 at²

       195 = 0 x t + 0.5 x 9.81 x t²

        t = 6.31 seconds

Now considering horizontal motion of ball

   Acceleration , a = 0 m/s²

   Displacement, s = 195 m

   Time, t = 6.31 s

   We have equation of motion s= ut + 0.5 at²

   Substituting

       s= ut + 0.5 at²

       195 = u x 6.31 + 0.5 x 0 x 6.31²

        u = 30.93 m/s

Velocity of plane is horizontal initial speed of ball = 30.93 m/s

Velocity of plane = 30.93 m/s

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Which statements express key Confucian teachings? Select all that apply. A.Rulers should focus on the yang force. B.People should follow the way of nature. C.People should respect their parents. D.Rulers should provide good government. Description

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Answer:

C) Nations begin to rely on each other for things they cannot produce themselves.

Explanation:

Globalization can lead to interdependence among nations. One of the most common ways in which this happens is through free trade. When two countries trade, they exchange goods and services. If the relationship is long and stable enough, the population can come to rely on the other country’s goods, which might not be produced in their country, or might be produced at a much higher price.

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Which word could be substituted for “cheap ,” if the author wanted to express a positive viewpoint?

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Here are a few pointers; hope this is useful)

Ovation-by definition- is show of appreciation from an audience, for a person’s accomplishments or flaw.

“Everyone deserves a standing ovation because we all overcometh the world.”

A person’s accomplishment could be how they made a positive change in this world, strong leadership- that makes them a effective leader or simply helping others. A person’s flaw- mistakes in life, sin or even guilt should also be considered an appreciation- an ovation for representing mankind’s flaw and that humanity makes mistakes, fulfilling at least one deadly sin such as greed, lust, selfishness etc.

Thus, regardless of a person’s achievement or flaw- a person deserves an applause for, not the least, living in this society and this world that we are all living together and dying together.

That was just the introduction.. the best part is yet to come.. now it’s your turn!!

Here are other pointers to talk about in your essay:

Shakespeare’s famous line “All the World’s a stage. That agrees with your line: “Everybody deserves a standing ovation…”

Shakespeare explains that men and women are like players: they live, and die, some being celebrated and some forever living in solitude till their death. Shakespeare states the world is a “stage” which symbolizes that mankind is in its peak. The world is changing everyday: little by little and humanity is falling behind.
Due to our world turning into machinery: factories, an automotive future: where humans only job to live (entrance) and to die (exit) the famous humans remembered and the flawed not recalled.

This is according to Shakespeare’s imagery.

I don’t know what grade your in, but I think simplifying Shakespeare’s word of mouth in your essay would be handy and useful as it has strong references of your quote, and agrees strongly in your essay.

Hope this helps 🙂

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Find this quotient and express the answer in scientific natation

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Employee                                 Mary      Zoe         Greg         Ann           Tom

Cumulative Pay                       $6,800   $10,500  $8,400    $66,000   $4,700

Pay subject to FICA S.S.         $421.60  $651.00  $520.80 $4092.00 $291.40
6.2%, (First $118,000)

Pay subject to FICA Medicare $98.60 $152.25    $121.80    $957.00    $68.15
1.45% of gross

Pay subject to FUTA Taxes      $40.80  $63.00     $50.40    $396.00  $28.20
0.6%

Pay subject to SUTA Taxes   $367.20  $567.00  $453.60  $3564.00 $253.80
5.4% (First $7000)

Totals                                     $928.20 $1,433.25 $1,146.60 $9,009.00 $641.55

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You write 4 different names on index cards. You shuffle the cards and then lay them out in a row. What is the probability that they will come out in alphabetical order? Express your answer as a fraction in simplest form.

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Employee                                 Mary      Zoe         Greg         Ann           Tom

Cumulative Pay                       $6,800   $10,500  $8,400    $66,000   $4,700

Pay subject to FICA S.S.         $421.60  $651.00  $520.80 $4092.00 $291.40
6.2%, (First $118,000)

Pay subject to FICA Medicare $98.60 $152.25    $121.80    $957.00    $68.15
1.45% of gross

Pay subject to FUTA Taxes      $40.80  $63.00     $50.40    $396.00  $28.20
0.6%

Pay subject to SUTA Taxes   $367.20  $567.00  $453.60  $3564.00 $253.80
5.4% (First $7000)

Totals                                     $928.20 $1,433.25 $1,146.60 $9,009.00 $641.55

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What would be your estimate of the age of the universe if you measured a value for hubble’s constant of h0 = 30 km/s/mly ? you can assume that the expansion rate has remained unchanged during the history of the universe. express your answer using two significant figures. yr?

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Answer:

a) The time the police officer required to reach the motorist was 15 s.

b) The speed of the officer at the moment she overtakes the motorist is 30 m/s

c) The total distance traveled by the officer was 225 m.

Explanation:

The equations for the position and velocity of an object moving in a straight line are as follows:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where:

x = position at time t

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

v = velocity at time t

a)When the officer reaches the motorist, the position of the motorist is the same as the position of the officer:

x motorist = x officer

Using the equation for the position:

x motirist = x0 + v · t (since a = 0).

x officer = x0 + v0 · t + 1/2 · a · t²

Let´s place our frame of reference at the point where the officer starts following the motorist so that x0 = 0 for both:

x motorist = x officer

x0 + v · t = x0 + v0 · t + 1/2 · a · t²      (the officer starts form rest, then, v0 = 0)

v · t = 1/2 · a · t²    

Solving for t:

2 v/a = t

t = 2 · 15.0 m/s/ 2.00 m/s² = 15 s

The time the police officer required to reach the motorist was 15 s.

b) Now, we can calculate the speed of the officer using the time calculated in a) and the  equation for velocity:

v = v0 + a · t

v = 0 m/s + 2.00 m/s² · 15 s

v = 30 m/s

The speed of the officer at the moment she overtakes the motorist is 30 m/s

c) Using the equation for the position, we can find the traveled distance in 15 s:

x = x0 + v0 · t + 1/2 · a · t²

x = 1/2 · 2.00 m/s² · (15s)² = 225 m

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Three cards are drawn with replacement from a standard deck. what is the probability that the first card will be a diamond, the second card will be a black card, and the third card will be an ace? express your answer as a fraction or a decimal number rounded to four decimal places.

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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Find the common ratio and the next term for the sequence shown. Express your answers as fractions or as decimals. 333 1/3, 250, 187 1/2

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Find the common ratio and the next term for the sequence shown. Express your answers as fractions or as decimals. 333 1/3, 250, 187 1/2

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Write the ions present in a solution of k3po4. express your answers as chemical formulas separated by a comma. offset subscripts and charges on each ion.

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This problem is to apply Roult’s Law.

Roult’s Law states that the vapor pressure, p, of a solution of a non-volatile solute is equal to the vapor pressure of the pure solvent, Po solv, times the mole fraction of the solvent, Xsolv

p = Xsolv * Po sol

X solv = number of moles of solvent / number of moles of solution

The solvent is water and the solute (not volatile) is glycerin.

Number of moles = mass in grams / molar mass

mass of water = 132 ml * 1 g/ml = 132 g

molar mass of water = 18 g/mol

=> number of moles of water = 132 g / 18 g/mol = 7.33333 mol

mass of glycerin = 27.2 g

molar mass of glycerin:, C3H8O3: 3 * 12 g/mol + 8 * 1 g/mol + 3*16 g/mol = 92 g/mol

number of moles of glycerin = 27.2g / 92 g/mol = 0.29565

total number of moles = 7.33333 moles + 0.29565 moles = 7.62898 moles

=> X solv = 7.33333 / 7.62898 = 0.96125

=> p = 0.96125 * 31.8 torr ≈ 30.57 torr ≈ 30.6 torr.

Answer: 30.6 torr

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Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck f(1) = 0. Express y in terms of x

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Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i’m a bit stuck f(1) = 0. Express y in terms of x

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A certain ionic compound is made entirely of aluminum and oxygen. part a what is the formula for this compound? express your answer as a chemical formula.

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Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a) The given balanced ionic equation is,

Ni(NO_3)_2(aq)+Na_2S(aq)rightarrow NiS(s)+2NaNO_3(aq)

The ionic equation in separated aqueous solution will be,

Ni^{2+}(aq)+2NO_3^-(aq)+2Na^+(aq)+S^{2-}(aq)rightarrow NiS(s)+2Na^+(aq)+2NO_3^-(aq)

In this equation, Na^+text{ and }NO_3^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Ni^{2+}(aq)+S^{2-}(aq)rightarrow NiS(s)

(b) The given balanced ionic equation is,

NaNO_3(aq)+KBr(aq)rightarrow KNO_3(s)+NaBr(aq)

The ionic equation in separated aqueous solution will be,

Na^+(aq)+NO_3^-(aq)+K^+(aq)+Br^-(aq)rightarrow KNO_3(s)+Na^+(aq)+Br^-(aq)

In this equation, Na^+text{ and }Br^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

NO_3^-(aq)+K^+(aq)rightarrow KNO_3(s)

(c) The given balanced ionic equation is,

Li_2SO_4(aq)+BaCl_2(aq)rightarrow BaSO_4(s)+2LiCl(aq)

The ionic equation in separated aqueous solution will be,

2Li^+(aq)+SO_4^{2-}(aq)+Ba^{2+}(aq)+2Cl^-(aq)rightarrow BaSO_4(s)+2Li^+(aq)+2Cl^-(aq)

In this equation, Li^+text{ and }Cl^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

SO_4^{2-}(aq)+Ba^{2+}(aq)rightarrow BaSO_4(s)

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The half-life for the radioactive decay of ce?141 is 32.5 days. if a sample has an activity of 3.1 ?ci after 97.5 d have elapsed, what was the initial activity, in microcuries, of the sample? express your answer using two significant figures.

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In order to get a sample of air that is 23 km above the ground, the rocket must rise by that height.

Draw a diagram (shown below) t represent the problem.

The distance h₁ is traveled from A to B with an upward acceleration of 17 m/s² over 30 s. The distance traveled is
h₁ = (1/2)(17 m/s²)(30 s)² = 7650 m = 7.65 km

At point B, the velocity attained is
V = (17 m/s²)30s) = 510 m/s

The distance h₂ is traveled from B to C with gravitational deceleration of -9.8 m/s². The distance traveled is given by
(510 m/s)² – 2(9.8 m/s²)h₂ = 0
h₂ = 13270.4 m = 13.27 km

The total height attained by the rocket is
h₁ + h₂ = 7.65 + 13.27 = 20.92 km

This height falls short of the desired height of 23 km.

Answer:
The rocket does not travel high enough to sample the air at a height of 23 km.

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