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In a situation where handicapped person can only input data into the computer using a stylus or light pen, which keyboard configuration might be the solution?

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In a situation where handicapped person can only input data into the computer using a stylus or light pen, which keyboard configuration might be the solution?

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function has the function rule y = -7x – 2. If the input is -4, what is the output?

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Plug in the input to the equation and you will get x=26


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What is the range of the function f(x) = 3×2 + 6x – 9

I have a solution here however with a slight change in the equation:

 f(x)=3x^2-6x+1

My solution is:

The domain is all real numbers–there are no restrictions like a square root or variable in the denominator 

this is a U shape parabola and you want to find the bottom point, it is at the vertex 

x=-b/2a =- (-6) /2 (3) =1 
f(1) =3(1)^2 -6(1) +1 =3-6+1 =-2 
the minimum is (1, -2) 
so the range is all real numbers >= -2

By examining my solution, you could just answer the problem on your own! I hope it helps!

Posted in Mathematics

Solve the equation for y 2x+6y=13

So here is how we are going to solve for y for the given equation above:
2x+6y=13
Next, transfer 2x to the right side and it will look like this:
6y=13-2x
Now, divide both sides by 6, and it will look like this:
y=13-2x
    ——–
       6
So, this is the final answer for y.
Hope this answers your question. Have a great day!

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The discriminant of a quadratic equation is negative. One solution is 3+4i . What is the other solution? A.4-3i B.3-4i C.4+3i D.-3+4i

The way you stated the problem, there is an infinity of possibilities for the other solution. 

► For instance, the quadratic equation: 
   x² – (6 + 4i)x + (9 + 12i) = 0 
has for discriminant: 
   Δ = (6 + 4i)² – 4(9 + 12i) = 36 – 16 + 48i – 36 – 48i = -16 
which is indeed negative. 
Its solutions will then be: 
   x₁ = [(6 + 4i) + 4i]/2 = 3 + 4i 
   x₂ = [(6 + 4i) – 4i]/2 = 3 
And the other solution here is 3. 

► If you are not convinced, the quadratic equation: 
   x² – (6 + 5i)x + (5 + 15i) = 0 
has for discriminant: 
   Δ = (6 + 5i)² – 4(5 + 15i) = 36 – 25 + 60i – 20 – 60i = -9 
which is indeed negative. 
Its solutions will then be: 
   x₁ = [(6 + 5i) + 3i]/2 = 3 + 4i 
   x₂ = [(6 + 5i) – 3i]/2 = 3 + i 
And the other solution here is 3+i. 

► In fact, every quadratic equation of the form: 
   x² – [6 + (4 + α)i]x + (3 + 4i)(3 + αi) = 0 
where α is any real, has for discriminant: 
   Δ = [6 + (4 + α)i]² – 4(3 + 4i)(3 + αi) 
      = 36 – (4 + α)² + 12(4 + α)i – 36 + 16α – 12(4 + α)i 
      = 16α – (4 + α)² 
      = 16α – 16 – 8α – α² 
      = -16 + 8α – α² 
      = -(α – 4)² 
WILL be negative. 
Their solutions will then be: 
   x₁ = [ [6 + (4 + α)i] – (α – 4)i ]/2 = 3 + 4i 
   x₂ = [ [6 + (4 + α)i] + (α – 4)i ]/2 = 3 + αi 
And the other solution will then be is 3+αi. 

Since α can take any real value, you’ll obtain an infinity of solutions of the form 3+αi. 

► So conclusively: 
If the discriminant of a quadratic is negative AND one of the solutions is 3+4i, the only thing we can say about the other solution is that its real part must be 3. 

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Each set of ordered pairs represents a function. Write a rule that represents the function. 1. (0,0),(1,4),(2,16),(3,36),(4,64) 2. (0,0),(1,0.5),(2,2),(3,4.5),(4,8)

My answer to the question is as follows:

First one looks like you are squaring the number, then multiplying the result by 4, i.e.

y=4x2

second one is similar, but instead of squaring and multiplying by 4, you are squaring and then dividing by 2

I hope my answer has come to your help. God bless and have a nice day ahead!

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Solve for x. round to nearest tenth if needed. 1. 7r-7=2r+18 a.r=-5 b.r=5 c.r=2.2 d.r=1.2 2. 2x+12=18-x a.x=3 b.x=10 c.x=6 d.x=2 3. 8x-3=15x+18 a.x=-3 b.x=3 c.x=2.1 d.x=0.9 4. 6y-6=4y+16 a.y=2.2 b.y=-2.2 c.y=11 d.y=5 5. 3(x-4)=5(x+2) a.x=11 b.x=-11 c.x=1 d.x=-1

1)  The answer is: [B]: r = 5 .
__________________________
Explanation:
__________________________ 
Given: 7r − 7 = 2r + 18 ; Round your answer to the nearest tenth, if necessary.
____________________________
Since “r” is the only variable given, let us assume we want to solve for “r” (instead of “x”).
___________________________
→ Subtract “2r” from EACH SIDE of the equation; and & add “7” to EACH SIDE of the equation:
_____________
→ 7r − 7 − 2r + 7 = 2r + 18 − 2r + 7 ;  to get: → 5r = 25 ;
_____________
→ Now, divide EACH SIDE of the equation by “5”; to isolate “r” on one side of the equation; and to solve for “r” :
______________
→ 5r / 5 = 25 / 5 → r = 5 → which is: “Answer choice: [B]”.
_________________
Let us check our answer, by plugging in “5” for “r” in the original equation:
_________________
 → 7r − 7 = 2r + 18 ;  →  7(5) − 7 =? 2(5) + 18? ;
______________________
→ 35 − 7 =? 10 + 18 ?;     → 28 =? 28? Yes!
______________________
 2) The answer is: [D]: x = 2 .
_____________
Explanation: 
_____________
Given: 2x + 12 = 18 − x ; Solve for “x” (round to nearest tenth, if necessary).
_______________
→ Add “x” to EACH SIDE of the equation, & subtract “12” from EACH SIDE of the equation:  → 2x + 12 + x − 12 = 18 − x + x − 12 ; 
______________
→ To get: 3x = 6 ;  → Divide EACH SIDE of the equation by “3”;
to isolate “x” on one side of the equation; and to solve for “x”:
_____________
→ 3x / 3 = 6 / 3 ; → x = 2 ; which is: “Answer choice: [D]”.
______________
Let us check our answer, by plugging in “2” for “x” in the original equation:
________________
→ 2x + 12 = 18 − x ; → 2(2) + 12 =? 18 − 2 ?
________________
→ 4 + 12 =? 18 − 2 ? ;   → 16 =? 16?  Yes!
________________________________
3)  The answer is: [A]: x = -3 . 
_____________
Explanation:
________________
Given:  8x − 3 = 15x + 18 ; Solve for “x”. Round your answer to the nearest tenth, if necessary.
_________________
→ Subtract “8x” from EACH SIDE of the equation, & add “3” to EACH SIDE of the equation:
_______________
→ 8x − 3 − 8x + 3 = 15x + 18 − 8x + 3 ; to get:
_______________
→ 0 = 7x + 21 ; → Subtract “21” from EACH SIDE of the equation;
_______________
→ 0 − 21 = 7x + 21 − 21 ; to get:
_______________
→  -21 = 7x ; Now divide EACH SIDE of the equation by “7”;
    to isolate “x” on one side of the equation; & to solve for “x”:
_______________
→ = -21 / 7 = 7x / 7 ; →  -3 = x ; which is “Answer choice: [A].”
_________________
Let us check our answer, by plugging in “-3” for “x” in the original equation:
________________
→  8x − 3 = 15x + 18 ;  → 8(-3) − 3 =?  15(-3) + 18 ?;
________________________
→ -24 − 3 =?  -45 + 18 ? ;   →  -27 =? -27?  Yes!
___________________________
4)  The answer is: [C]: y = 11 .
_____________
Explanation:
____________
Given: 6y − 6 = 4y + 16 ; Solve for “y”; Round to the nearest tenth, if necessary.
____________
(Note: Since “y” is the only variable given; assume we are to solve for “y” instead of “x”).
____________
→ Subtract “4y” from EACH SIDE of the equation, & add “6” to EACH SIDE of the equation; → 6y − 6 − 4y + 6 = 4y + 16 − 4y + 6 ; to get:
_______________
→ 2y  = 22 ; Now, divide EACH SIDE of the equation by “2”; to isolate “y” one side of the equation; and to solve for “y” ;
_______________
→ 2y / 2 = 22 / 2 ; →  y = 11 → which is “Answer choice: [C]”.
_______________________________
Let us check our answer, by plugging in “11” for “y” in the original equation:
___________________
→  6y − 6 = 4y + 16 ; → 6(11) − 6 =? 4(11) + 16 ?
_______________________
→ 66 − 6  =? 44 + 16 ?  → 60 =? 60 ?  Yes!
__________________
5)  The answer is: [B]: x = -11 .
_____________________
Explanation:
_________________
Given: 3(x − 4) = 5(x + 2) ; Solve for “x”. Round to the nearest tenth, if necessary.
___________
→Note the “distributive property of multiplication”: 
_____________
a*(b + c) = ab + ac ;  and: a*(b − c) = ab − ac ;
_______________
→ Let us expand EACH SIDE of our given equation.
→Start with the “left-hand side”:
____________
3(x − 4) = (3*x)  − (3*4) = 3x − 12;
______________________________
→Now let us expand the “right-hand side” of the given equation:
____________
→  5(x + 2) = (5*x) + (5*2) = 5x + 10 ;
______________
→Now, we can rewrite the original equation:
_______________
→ 3(x − 4) = 5(x + 2) ; by substituting the expanded values for EACH SIDE of the question:   →  3x − 12 = 5x + 10 ;
__________________
→ Subtract “3x” from EACH SIDE of the equation; and add “12” to EACH SIDE of the equation: →  3x − 12 − 3x + 12 = 5x + 10 − 3x + 12 ; to get:
________________
→  0 = 2x + 22;  → Now subtract “22” from EACH SIDE of the equation:
______________
→  0 − 22 = 2x + 22 − 22 ; to get:  →  -22 = 2x ;
__________
→ Divide EACH SIDE of the equation by “2”; to isolate “x” on one side of the equation; & to solve for “x” ;
_____________
→  -22 / 2 = 2x /2 ;  →  -11 = x ; which is “Answer choice: [B]”.
______________
Let us check our answer, by plugging in “-11” for “x” in the original equation:
___________
→ 3(x − 4) = 5(x + 2) ; →  3(-11 − 4) =? 5(-11 + 2) ? ; 
_______________________
→3(-15) =? 5(-9) ? ; → -45 =? -45 ?  Yes!
_____________________________________________
Hope these answers and explanations are helpful. Best of luck!

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Which rule represents the translation of hexagon DEFGHI to hexagon D’E’F’G’H’I’? (x, y)→(x – 8, y – 7) (x, y)→(x – 7, x – 8) (x, y)→(x – 4, x – 5) (x, y)→(x – 5, y – 4)

Correct answer is A.

Each vertex of the hexagon is translated 8 units left and 7 units down. So, the x-coordinate is 8 units smaller (x – 8), and the y-coordinate is 7 units smaller (y – 7).

Therefore (x, y) → (x – 8, y -7)

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In an input/output table, all outputs are 0, regardless of the input. What could the function equation be? Select all that apply. y = x y =x/0 y = 0x y = 0/x

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In an input/output table, all outputs are 0, regardless of the input. What could the function equation be? Select all that apply. y = x y =x/0 y = 0x y = 0/x

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Nine times the input minus seven is equal to the output. Which of the following equations describes this function? A) 9y – 7 = x B) 7y – 9 = x C) 9x – 7 = y D) 7x – 9 = y

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Nine times the input minus seven is equal to the output. Which of the following equations describes this function? A) 9y – 7 = x B) 7y – 9 = x C) 9x – 7 = y D) 7x – 9 = y

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Programmers employ the acronym ____ to mean that if your input is incorrect, your output is worthless.

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When making an email for professional purposes, it is important to make one that uses your full name as a username, if possible. However, common names might face difficulties since other people might have already taken the username. In this case, you can abbreviate your name, or include numbers behind it.

The best answer, thus, based on this, would be (D) alison.s-yahoo.com.

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What type of gate does this input-output table correspond to? Input: Output: A B ? 0 1 1 0 0 0 1 0 1 1 1 1

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Answer:

Tables 1 and 5 are equal.

Step-by-step explanation:

Given are 5 tables in x and y with two values each.

We are to find out which two represent the same function.

As for every function, two points are given.

Let us compare the slopes of each function.

Slope=change in y coordinate/change in x coordinate

Table           Slope

   I                 -0.5

   2               -0.5

   3               -0.5

   4                 1

   5                -0.5

Table 4 is eliminatednow.

Though slopes are the same for 1 and 2,f(4) =8 and 5 different . Hence I and II cannot be the same.  Similarly for 2 different values are there in table 3,4,5.  Hence 3,4,5 cannot be pairwise equal.

We find that table I and table 5 have the same slope. Also when pairwise taken, (4,8) and (2,9) slope = -0.5

So table I = table 5

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Consider the functions shown on the graph. What is the input value for which the statement f(x) = g(x) is true? 0.25 0.5 1.5 2.75

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The basis to respond this question are:

1) Perpedicular lines form a 90° angle between them.

2) The product of the slopes of two any perpendicular lines is – 1.

So, from that basic knowledge you can analyze each option:

a.Lines s and t have slopes that are opposite reciprocals.

TRUE. Tha comes the number 2 basic condition for the perpendicular lines.

slope_1 * slope_2 = – 1 => slope_1 = – 1 / slope_2, which is what opposite reciprocals means.

b.Lines s and t have the same slope.

FALSE. We have already stated the the slopes are opposite reciprocals.

c.The product of the slopes of s and t is equal to -1

TRUE: that is one of the basic statements that you need to know and handle.

d.The lines have the same steepness.

FALSE: the slope is a measure of steepness, so they have different steepness.

e.The lines have different y intercepts.

FALSE: the y intercepts may be equal or different. For example y = x + 2 and y = -x + 2 are perpendicular and both have the same y intercept, 2.

f.The lines never intersect.

FALSE: perpendicular lines always intersept (in a 90° angle).

g.The intersection of s and t forms right angle.

TRUE: right angle = 90°.

h.If the slope of s is 6, the slope of t is -6

FALSE. – 6 is not the opposite reciprocal of 6. The opposite reciprocal of 6 is – 1/6.

So, the right choices are a, c and g.

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In order to process information from the external world, _____ receive input from the body and transfer the information to the brain through the spinal cord. motor neurons mirror neurons interneurons sensory neurons

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There are two systems in the human body that are responsible for the coordination between the functions of different systems to achieve the unity of the living organism’s body. These two systems are the nervous system and the endocrine system. The action of the nervous system is fast and takes a short time, while the action of the endocrine system is slow and takes a long time.

The functional unit of the nervous system is the nerve cell or the neuron. The neuron consists of a cell body and the axon. The cell body starts with the dendrites that receive the messages or the impulses from other neurons or from different sense organs or receptors. These impulses are then transmitted through the cell body. The cell body contains a nucleus and different organelles which help the nerve cell to perform its functions. The nerve impulse is then transmitted to the axon.

The axon is an extension from the cell body. There are some cells called Schwan cells that secrete a myelin sheath to insulate the axon from the surrounding medium. The insulated axons have more ability to conduct the impulses than non-insulated axons. The axon ends with the terminal arborizations. The terminal arborizations of a nerve cell connect to the dendrites of the next cell or to the afferent organ. The gaps between the dendrites and the terminal arborizations are called the synapses.

The nerve impulse is an electrochemical phenomenon i.e. an electrical phenomenon with a chemical nature. The membrane of the axon acts as a barrier between an outside positively charged medium and an inside negatively charged medium. This makes a potential difference of  -70mV. This state is called the resting potential. When the membrane is subjected to a stimulus, the positive charges enter to inside and the negative charges exit to the outside. The potential difference now becomes +40mV. This state is called the depolarization state. The point of stimulation acts as a new stimulus for the next point and so on. The membrane sooner gains its permeability again and the positive charges return to the outside and the negative charges to inside. This state is called repolarization.

The nerve impulse reaches the synapse. There are some neurotransmitters that are excited by the nerve impulse coming and carry the message across the membrane. Some receptors receive theses neurotransmitters on the dendrites of the next neuron. These receptors act as a stimulus for the new cell.

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What is the constant term in the expression 4x3y + 8×2 + 6x + 5? (Input a numeric value only.)

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Answer:

The possible terms are a^5b^3,b^8,a^4b^4,a^8,ab^7.

Step-by-step explanation:

Binomial Theorem:

(a+b)^n=^nC_0a^n+^nC_1a^{n-1}b+...+^nC_{n-1}a^1b^{n-1}+^nC_nb^n

Using Binomial Theorem, we get

(x + 2)^6=^6C_0a^n+^6C_1a^{5}b+...+^6C_{5}a^1b^{5}+^5C_5b^5

(x + 2)^6=x^6 + 12 x^5 + 60 x^4 + 160 x^3 + 240 x^2 + 192 x + 64

Similarly,

(x-4)^4=x^4 - 16 x^3 + 96 x^2 - 256 x + 256

(2x+3)^5=32 x^5 + 240 x^4 + 720 x^3 + 1080 x^2 + 810 x + 243

(2x-3y)^4=16 x^4 - 96 x^3 y + 216 x^2 y^2 - 216 x y^3 + 81 y^4

The Pascal’s triangle is given below. In Pascal’s triangle nth row represents the coefficients of the expression of (a+n)^{n-1}.

In the expression (x + 2)^6, a=x, b=2 and n=6. Using 7th row of Pascal’s triangle we get

(x + 2)^6=1(x^6)(2^0)+6(x^5)(2^1)+15(x^4)(2^2)+20(x^3)(2^3)+15(x^2)(2^4)+6(x^1)(2^5)+1(x^0)(2^6)

(x + 2)^6=x^6 + 12 x^5 + 60 x^4 + 160 x^3 + 240 x^2 + 192 x + 64

Similarly,

In (x-4)^4 a=x, b=-4 and n=4. Using 5th row of Pascal’s triangle we get

(x-4)^4=x^4 - 16 x^3 + 96 x^2 - 256 x + 256

In (2x+3)^5 a=2x, b=3 and n=5. Using 6th row of Pascal’s triangle we get

(2x+3)^5=32 x^5 + 240 x^4 + 720 x^3 + 1080 x^2 + 810 x + 243

In (2x-3y)^4 a=2x, b=-3y and n=4. Using 5th row of Pascal’s triangle we get

(2x-3y)^4=16 x^4 - 96 x^3 y + 216 x^2 y^2 - 216 x y^3 + 81 y^4

In binomial expansion of (3a + 4b)^8 the degree of each term must be 8. It means the sum of powers of a and b is equal to 8.

For a^2b^3 the dgree of term is 2+3=5. So, it is not possible variable term.

Therefore the possible terms are a^5b^3,b^8,a^4b^4,a^8,ab^7.

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___________ efficiency is gaining the most output with a given amount of input, but not relating output to consumer utility.

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Depreciation=(equipment cost-salvage value)/useful life

Depreciation=(16,950−4,200)÷6
=2,125 per year

Book value after 3 years
=16,950−2,125×3
=10,575

Now find the amount of depreciation to be charged against the equipment during each of the remaining years of its useful life
Depreciation=(equipment cost-salvage value)/useful life

Depreciation=(10,575−1,695)÷3
=2,960

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A database into which employees manually input customer names and addresses is riddled with errors and you have been charged with rectifying the situation. in considering the organizational dimensions of this problem, you should consider:

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Hey there!

Let’s assume that this question is referring to every digital calendar ever made. As in, even those made on devices without internet connectivity or any other fancy features that we utilize with many digital calendars today. 

If a planning device that came with a digital calendar didn’t have internet connectivity, it wouldn’t be able to be connected to the cloud. Back when these devices were around, it wasn’t even plausible to store things like calendar events and contacts in what we know as the “cloud”. Also, these devices probably had to be hardwired to a computer and new software had to be downloaded to them, so the updates weren’t automatic. Archaic, right?

Also, consider the fact that even reputable websites/companies such as Google with Google Calendars or Apple with iCalendar will never go without their malfunctions or threats. Sometimes, these websites can be hacked and the data that they contain can be compromised, especially if they’re stored on the cloud. Also, even though it’s not realistic, Google or Apple could one day decide to completely get rid of their calendar programs altogether. So, this means that digital calendars are definitely able to be destroyed or lost. 

That just leaves “They can be used anywhere”. This is true, even with those archaic devices specifically used for scheduling events and such. Nowadays, you have your phone and possibly a laptop on you at all times, which will likely have a calendar on it as a stock application. So, I think this is your answer. 

Hope this helped you out! 🙂

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Which most likely explains why the Japanese royal family was not prosecuted for war crimes? The United States feared the Japanese military would revolt. The United States needed the royal family’s input to run the government. The United States lacked evidence the royal family committed crimes. The United States wanted to build an ongoing alliance with Japan.

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Which most likely explains why the Japanese royal family was not prosecuted for war crimes? The United States feared the Japanese military would revolt. The United States needed the royal family’s input to run the government. The United States lacked evidence the royal family committed crimes. The United States wanted to build an ongoing alliance with Japan.

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Match the item to the type. Question 10 options: software input device operating system hardware 1. Windows 2. Microsoft Word 3. motherboard 4. mouse

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Step

Click “Start,” “All Programs,” and then “Windows Media Player.”

Step

Click on “Now Playing,” browse your computer for the video file you wish to resize, click on it, hold down the mouse button, drag the video icon into the Media Player window and then release the mouse button. The video will appear and start playing in the “Now Playing” window.

Step

Right-click the blank space next to the “Now Playing” menu, point to “View,” “Video Size” and then click on a size percentage (50%, 100% or 200%) or click “Fit video to Player on Resize.” Selecting “Fit video to Player on Resize” will automatically make the video fit the Media Player window. If this option is checked, selecting a different size percentage will not change the size of the video.

Step

Click the “Restore Down” button (the button next to the “X” used to close the window) and then click on the lower-right corner of the Media Player window and drag the corner to resize the video. When the video is set to “Fit video to Player on Resize,” the video will automatically fit the window as you drag the corner.

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Which of the tables represents a function? Table A Input Output 4 3 3 2 3 1 Table B Input Output 1 3 3 5 5 7 Table C Input Output 0 0 1 4 1 5 Table D Input Output 4 1 4 2 4 3 Table A Table B Table C Table D

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Answer:

The graph representing the solution is given below.

Step-by-step explanation:

We are given the system of inequality is,

2x + 5yleq  9

3x + 5y leq  9

Zero Test states that,

‘After substituting the point (0,0) in the inequalities, if the result is true, then the solution region id towards the origin. If the result is false, the solution region is away from the origin’.

So, upon substituting (0,0) in the given inequalities, we get,

2x + 5yleq  9 implies 0≤ 9, which is true.

3x + 5y leq  9 implies 0≤ 9, which is true.

Thus, the solution region for both the inequalities is towards the origin.

Hence, upon plotting, the graph representing the solution set is given below.

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Plz answer me for a Brainliest!!!!! What value should go in the empty boxes to complete the calculation for finding the product of 0.98 × 0.73? Both numbers are the same; however, only input the number one time in your answer.

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Answer:

The maximum area that can be enclosed is 40000 feet square.

Step-by-step explanation:

Given : If 800 feet of fencing is used to enclose a rectangular plot of land that borders a river.

To find : What is the maximum area that can be enclosed?  

Solution :

Let the width of the rectangular is x feet.

We have given 800 feet of fencing i.e. perimeter = 800 feet.

Perimeter of rectangle is P=2(l+w)

800=2(l+x)

400-x=l

The area of the rectangle is

A=ltimes w

A=(400-x)times x

A=400x-x^2

To maximize the area derivate w.r.t x

A'=400-2x

Put A’=0

400-2x=0

2x=400

x=200

i.e. width of the rectangle is x=200.

The length of the rectangle is l=400-x=400-200=200

The area of the rectangle is A=200times 200=40000ft^2

Therefore, The maximum area that can be enclosed is 40000 feet square.

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A function T multiplies the input z by 2/3 and divides that by the quantity (z-1/2). A Write the function equation for T(z) B Find T(3) Show your work C Find T(1/2) Show your work D Discuss the result you found for part C. How might this be related to the current discussion of Domain and Range.

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Posted in Mathematics

T(z)= frac{ frac{2}{3} z}{z- frac{1}{2} }
T(3) = 2/2.5 = 4/5 or 0.8
T(1/2) is indeterminate, he reason being that the denominator becomes zero. Division by zero gives an indeterminate result.


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