Plug in the input to the equation and you will get x=26

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]]>In a situation where handicapped person can only input data into the computer using a stylus or light pen, which keyboard configuration might be the solution?

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]]>The post function has the function rule y = -7x – 2. If the input is -4, what is the output? appeared first on EduHawks.com.

]]>Plug in the input to the equation and you will get x=26

What is the range of the function f(x) = 3×2 + 6x – 9

I have a solution here however with a slight change in the equation:

f(x)=3x^2-6x+1

My solution is:

The domain is all real numbers–there are no restrictions like a square root or variable in the denominator

this is a U shape parabola and you want to find the bottom point, it is at the vertex

x=-b/2a =- (-6) /2 (3) =1

f(1) =3(1)^2 -6(1) +1 =3-6+1 =-2

the minimum is (1, -2)

so the range is all real numbers >= -2

By examining my solution, you could just answer the problem on your own! I hope it helps!

Solve the equation for y 2x+6y=13

So here is how we are going to solve for y for the given equation above:

2x+6y=13

Next, transfer 2x to the right side and it will look like this:

6y=13-2x

Now, divide both sides by 6, and it will look like this:

y=13-2x

——–

6

So, this is the final answer for y.

Hope this answers your question. Have a great day!

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No matter what kind of academic paper you need, it is simple and secure to hire a writer for a price you can afford at StudyHawks. Save more time for yourself.

The way you stated the problem, there is an infinity of possibilities for the other solution.

► For instance, the quadratic equation:

x² – (6 + 4i)x + (9 + 12i) = 0

has for discriminant:

Δ = (6 + 4i)² – 4(9 + 12i) = 36 – 16 + 48i – 36 – 48i = -16

which is indeed negative.

Its solutions will then be:

x₁ = [(6 + 4i) + 4i]/2 = 3 + 4i

x₂ = [(6 + 4i) – 4i]/2 = 3

And the other solution here is 3.

► If you are not convinced, the quadratic equation:

x² – (6 + 5i)x + (5 + 15i) = 0

has for discriminant:

Δ = (6 + 5i)² – 4(5 + 15i) = 36 – 25 + 60i – 20 – 60i = -9

which is indeed negative.

Its solutions will then be:

x₁ = [(6 + 5i) + 3i]/2 = 3 + 4i

x₂ = [(6 + 5i) – 3i]/2 = 3 + i

And the other solution here is 3+i.

► In fact, every quadratic equation of the form:

x² – [6 + (4 + α)i]x + (3 + 4i)(3 + αi) = 0

where α is any real, has for discriminant:

Δ = [6 + (4 + α)i]² – 4(3 + 4i)(3 + αi)

= 36 – (4 + α)² + 12(4 + α)i – 36 + 16α – 12(4 + α)i

= 16α – (4 + α)²

= 16α – 16 – 8α – α²

= -16 + 8α – α²

= -(α – 4)²

WILL be negative.

Their solutions will then be:

x₁ = [ [6 + (4 + α)i] – (α – 4)i ]/2 = 3 + 4i

x₂ = [ [6 + (4 + α)i] + (α – 4)i ]/2 = 3 + αi

And the other solution will then be is 3+αi.

Since α can take any real value, you’ll obtain an infinity of solutions of the form 3+αi.

► So conclusively:

If the discriminant of a quadratic is negative AND one of the solutions is 3+4i, the only thing we can say about the other solution is that its real part must be 3.

My answer to the question is as follows:

First one looks like you are squaring the number, then multiplying the result by 4, i.e.

y=4x2

second one is similar, but instead of squaring and multiplying by 4, you are squaring and then dividing by 2

I hope my answer has come to your help. God bless and have a nice day ahead!

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**1) The answer is: [B]: r = 5 .****__________________________****Explanation:****___________**_______________

Given: 7r − 7 = 2r + 18 ; Round your answer to the nearest tenth, if necessary.

____________________________

Since “r” is the only variable given, let us assume we want to solve for “r” (instead of “x”).

___________________________

→ Subtract “2r” from EACH SIDE of the equation; and & add “7” to EACH SIDE of the equation:

_____________

→ 7r − 7 − 2r + 7 = 2r + 18 − 2r + 7 ; to get: → 5r = 25 ;

_____________

→ Now, divide EACH SIDE of the equation by “5”; to isolate “r” on one side of the equation; and to solve for “r” :

______________

→ 5r / 5 = 25 / 5 → r = 5 → which is: “Answer choice: [B]”.

_________________**Let us check our answer, by plugging in “5” for “r” in the original equation:**

_________________

→ 7r − 7 = 2r + 18 ; → 7(5) − 7 =? 2(5) + 18? ;

______________________

→ 35 − 7 =? 10 + 18 ?; → 28 =? 28? Yes!

______________________** 2) The answer is: [D]: x = 2 .****_____________****Explanation: **

_____________

Given: 2x + 12 = 18 − x ; Solve for “x” (round to nearest tenth, if necessary).

_______________

→ Add “x” to EACH SIDE of the equation, & subtract “12” from EACH SIDE of the equation: → 2x + 12 + x − 12 = 18 − x + x − 12 ;

______________

→ To get: 3x = 6 ; → Divide EACH SIDE of the equation by “3”;

to isolate “x” on one side of the equation; and to solve for “x”:

_____________

→ 3x / 3 = 6 / 3 ; → x = 2 ; which is: “Answer choice: [D]”.

______________**Let us check our answer, by plugging in “2” for “x” in the original equation:**

________________

→ 2x + 12 = 18 − x ; → 2(2) + 12 =? 18 − 2 ?

________________

→ 4 + 12 =? 18 − 2 ? ; → 16 =? 16? Yes!

________________________________**3) The answer is: [A]: x = -3 . ****_____________****Explanation:**

________________

Given: 8x − 3 = 15x + 18 ; Solve for “x”. Round your answer to the nearest tenth, if necessary.

_________________

→ Subtract “8x” from EACH SIDE of the equation, & add “3” to EACH SIDE of the equation:

_______________

→ 8x − 3 − 8x + 3 = 15x + 18 − 8x + 3 ; to get:

_______________

→ 0 = 7x + 21 ; → Subtract “21” from EACH SIDE of the equation;

_______________

→ 0 − 21 = 7x + 21 − 21 ; to get:

_______________

→ -21 = 7x ; Now divide EACH SIDE of the equation by “7”;

to isolate “x” on one side of the equation; & to solve for “x”:

_______________

→ = -21 / 7 = 7x / 7 ; → -3 = x ; which is “Answer choice: [A].”**_________________****Let us check our answer, by plugging in “-3” for “x” in the original equation:**

________________

→ 8x − 3 = 15x + 18 ; → 8(-3) − 3 =? 15(-3) + 18 ?;

________________________

→ -24 − 3 =? -45 + 18 ? ; → -27 =? -27? Yes!**___________________________****4) The answer is: [C]: y = 11 .****_____________****Explanation:****____________**

Given: 6y − 6 = 4y + 16 ; Solve for “y”; Round to the nearest tenth, if necessary.

____________

(Note: Since “y” is the only variable given; assume we are to solve for “y” instead of “x”).

____________

→ Subtract “4y” from EACH SIDE of the equation, & add “6” to EACH SIDE of the equation; → 6y − 6 − 4y + 6 = 4y + 16 − 4y + 6 ; to get:

_______________

→ 2y = 22 ; Now, divide EACH SIDE of the equation by “2”; to isolate “y” one side of the equation; and to solve for “y” ;

_______________

→ 2y / 2 = 22 / 2 ; → y = 11 → which is “Answer choice: [C]”.**_______________________________****Let us check our answer, by plugging in “11” for “y” in the original equation:****___________________**

→ 6y − 6 = 4y + 16 ; → 6(11) − 6 =? 4(11) + 16 ?

_______________________

→ 66 − 6 =? 44 + 16 ? → 60 =? 60 ? Yes!**__________________****5) The answer is: [B]: x = -11 .****_____________________****Explanation:****_________________**

Given: 3(x − 4) = 5(x + 2) ; Solve for “x”. Round to the nearest tenth, if necessary.**___________****→Note the “distributive property of multiplication”: ****_____________****a*(b + c) = ab + ac ; and: a*(b − c) = ab − ac ;****_______________**

→ Let us expand EACH SIDE of our given equation.

→Start with the “left-hand side”:

____________

3(x − 4) = (3*x) − (3*4) = 3x − 12;

______________________________

→Now let us expand the “right-hand side” of the given equation:

____________

→ 5(x + 2) = (5*x) + (5*2) = 5x + 10 ;

______________

→Now, we can rewrite the original equation:

_______________

→ 3(x − 4) = 5(x + 2) ; by substituting the expanded values for EACH SIDE of the question: → 3x − 12 = 5x + 10 ;

__________________

→ Subtract “3x” from EACH SIDE of the equation; and add “12” to EACH SIDE of the equation: → 3x − 12 − 3x + 12 = 5x + 10 − 3x + 12 ; to get:

________________

→ 0 = 2x + 22; → Now subtract “22” from EACH SIDE of the equation:

______________

→ 0 − 22 = 2x + 22 − 22 ; to get: → -22 = 2x ;

__________

→ Divide EACH SIDE of the equation by “2”; to isolate “x” on one side of the equation; & to solve for “x” ;

_____________

→ -22 / 2 = 2x /2 ; → -11 = x ; which is “Answer choice: [B]”.

______________**Let us check our answer, by plugging in “-11” for “x” in the original equation:****___________**

→ 3(x − 4) = 5(x + 2) ; → 3(-11 − 4) =? 5(-11 + 2) ? ;

_______________________

→3(-15) =? 5(-9) ? ; → -45 =? -45 ? Yes!**_____________________________________________****Hope these answers and explanations are helpful. Best of luck!**

Correct answer is A.

Each vertex of the hexagon is translated 8 units left and 7 units down. So, the x-coordinate is 8 units smaller (x – 8), and the y-coordinate is 7 units smaller (y – 7).

Therefore (x, y) → (x – 8, y -7)

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]]>The post In an input/output table, all outputs are 0, regardless of the input. What could the function equation be? Select all that apply. y = x y =x/0 y = 0x y = 0/x appeared first on EduHawks.com.

]]>In an input/output table, all outputs are 0, regardless of the input. What could the function equation be? Select all that apply. y = x y =x/0 y = 0x y = 0/x

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]]>The post Nine times the input minus seven is equal to the output. Which of the following equations describes this function? A) 9y – 7 = x B) 7y – 9 = x C) 9x – 7 = y D) 7x – 9 = y appeared first on EduHawks.com.

]]>Nine times the input minus seven is equal to the output. Which of the following equations describes this function? A) 9y – 7 = x B) 7y – 9 = x C) 9x – 7 = y D) 7x – 9 = y

The post Nine times the input minus seven is equal to the output. Which of the following equations describes this function? A) 9y – 7 = x B) 7y – 9 = x C) 9x – 7 = y D) 7x – 9 = y appeared first on EduHawks.com.

]]>The post Programmers employ the acronym ____ to mean that if your input is incorrect, your output is worthless. appeared first on EduHawks.com.

]]>When making an email for professional purposes, it is important to make one that uses your full name as a username, if possible. However, common names might face difficulties since other people might have already taken the username. In this case, you can abbreviate your name, or include numbers behind it.

The best answer, thus, based on this, would be **(D) alison.s-yahoo.com.**

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]]>The post What type of gate does this input-output table correspond to? Input: Output: A B ? 0 1 1 0 0 0 1 0 1 1 1 1 appeared first on EduHawks.com.

]]>**Answer:**

Tables 1 and 5 are equal.

**Step-by-step explanation:**

Given are 5 tables in x and y with two values each.

We are to find out which two represent the same function.

As for every function, two points are given.

Let us compare the slopes of each function.

Slope=change in y coordinate/change in x coordinate

Table Slope

I -0.5

2 -0.5

3 -0.5

4 1

5 -0.5

Table 4 is eliminatednow.

Though slopes are the same for 1 and 2,f(4) =8 and 5 different . Hence I and II cannot be the same. Similarly for 2 different values are there in table 3,4,5. Hence 3,4,5 cannot be pairwise equal.

We find that table I and table 5 have the same slope. Also when pairwise taken, (4,8) and (2,9) slope = -0.5

So table I = table 5

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]]>The post Consider the functions shown on the graph. What is the input value for which the statement f(x) = g(x) is true? 0.25 0.5 1.5 2.75 appeared first on EduHawks.com.

]]>**1) Perpedicular lines form a 90° angle between them.**

**2) The product of the slopes of two any perpendicular lines is – 1.**

So, from that basic knowledge you can analyze each option:

**a.Lines s and t have slopes that are opposite reciprocals.**

**TRUE. Tha comes the number 2 basic condition for the perpendicular lines.**

slope_1 * slope_2 = – 1 => slope_1 = – 1 / slope_2, which is what opposite reciprocals means.

b.Lines s and t have the same slope.

FALSE. We have already stated the the slopes are opposite reciprocals.

**c.The product of the slopes of s and t is equal to -1**

**TRUE: that is one of the basic statements that you need to know and handle.**

d.The lines have the same steepness.

FALSE: the slope is a measure of steepness, so they have different steepness.

e.The lines have different y intercepts.

FALSE: the y intercepts may be equal or different. For example y = x + 2 and y = -x + 2 are perpendicular and both have the same y intercept, 2.

f.The lines never intersect.

FALSE: perpendicular lines always intersept (in a 90° angle).

**g.The intersection of s and t forms right angle.**

**TRUE: right angle = 90°.**

h.If the slope of s is 6, the slope of t is -6

FALSE. – 6 is not the opposite reciprocal of 6. The opposite reciprocal of 6 is – 1/6.

**So, the right choices are a, c and g.**

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]]>
There are two systems in the human body that are responsible for the coordination between the functions of different systems to achieve the unity of the living organism’s body. These two systems are the nervous system and the endocrine system. The action of the nervous system is fast and takes a short time, while the action of the endocrine system is slow and takes a long time.

The functional unit of the nervous system is the nerve cell or the neuron. The neuron consists of a cell body and the axon. The cell body starts with the dendrites that receive the messages or the impulses from other neurons or from different sense organs or receptors. These impulses are then transmitted through the cell body. The cell body contains a nucleus and different organelles which help the nerve cell to perform its functions. The nerve impulse is then transmitted to the axon.

The axon is an extension from the cell body. There are some cells called Schwan cells that secrete a myelin sheath to insulate the axon from the surrounding medium. The insulated axons have more ability to conduct the impulses than non-insulated axons. The axon ends with the terminal arborizations. The terminal arborizations of a nerve cell connect to the dendrites of the next cell or to the afferent organ. The gaps between the dendrites and the terminal arborizations are called the synapses.

The nerve impulse is an electrochemical phenomenon i.e. an electrical phenomenon with a chemical nature. The membrane of the axon acts as a barrier between an outside positively charged medium and an inside negatively charged medium. This makes a potential difference of -70mV. This state is called the resting potential. When the membrane is subjected to a stimulus, the positive charges enter to inside and the negative charges exit to the outside. The potential difference now becomes +40mV. This state is called the depolarization state. The point of stimulation acts as a new stimulus for the next point and so on. The membrane sooner gains its permeability again and the positive charges return to the outside and the negative charges to inside. This state is called repolarization.

The nerve impulse reaches the synapse. There are some neurotransmitters that are excited by the nerve impulse coming and carry the message across the membrane. Some receptors receive theses neurotransmitters on the dendrites of the next neuron. These receptors act as a stimulus for the new cell.

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]]>The post What is the constant term in the expression 4x3y + 8×2 + 6x + 5? (Input a numeric value only.) appeared first on EduHawks.com.

]]>**Answer:**

The possible terms are .

**Step-by-step explanation:**

Binomial Theorem:

Using Binomial Theorem, we get

Similarly,

The Pascal’s triangle is given below. In Pascal’s triangle nth row represents the coefficients of the expression of .

In the expression , a=x, b=2 and n=6. Using 7th row of Pascal’s triangle we get

Similarly,

In a=x, b=-4 and n=4. Using 5th row of Pascal’s triangle we get

In a=2x, b=3 and n=5. Using 6th row of Pascal’s triangle we get

In a=2x, b=-3y and n=4. Using 5th row of Pascal’s triangle we get

In binomial expansion of the degree of each term must be 8. It means the sum of powers of a and b is equal to 8.

For the dgree of term is 2+3=5. So, it is not possible variable term.

Therefore the possible terms are .

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Depreciation=(equipment cost-salvage value)/useful life

Depreciation=(16,950−4,200)÷6

=2,125 per year

Book value after 3 years

=16,950−2,125×3

=10,575

Now find the amount of depreciation to be charged against the equipment during each of the remaining years of its useful life

Depreciation=(equipment cost-salvage value)/useful life

Depreciation=(10,575−1,695)÷3

=2,960

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