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A] The table of both functions from 0 to 3 will be:

h(t)=-16t^2+48t+12

t 0 1 2 3

h(t) 12 44 44 12

g(t)=10+15.2t

t 0 1 2 3

g(t) 10 25.2 40.4 55.6

the point in which h(t)=g(t) will be given by:

-16t^2+48t+12=10+15.2t

forming quadratic equation we get:

-16t^2+32.8t+12=0

solving the above quadratic equation using the formula we get:

t=-0.32 or t=2.4

therefore we conclude that they only met once, at point t=2.4 sec

therefore they met between points t=-0.32 and t=2.4

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