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The x- intercepts of a parabola are (-5, 0) and (3, 0). What is the function of the parabola? f(x) = -2(x2 + 2x − 5) f(x) = -2(x2 + 2x − 15) f(x) = -2(x2 − 2x − 15) f(x) = -2(x2 − 2x − 5)

Just need to substitute (with some patience) x=-5 and see whether you get f(x)=0, and x=3. Now, a parabola is also f(x) proportional to (x+5)*(x-3) (if you know the solutions, which you do in this particular example). So: x^2 + 2*x – 15. This is the third one. The -2 …

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Identify both the x- and y-intercepts of the linear equation graphed on the coordinate plane above. Use the intercepts to write an equation of the line in point-slope form, slope-intercept form, and general form of a linear equation.Complete your work in the space provided or upload a file that can display math symbols if your work requires it. In your work, be sure to include the coordinates for both intercepts and the equations of the line in all three formats.

The x int (where the line crosses the x axis) is (-2,0)the y int (where the line crosses the y axis) is (0,-2) (-2,0)(0,-2)slope = (-2 – 0) / (0 – (-2) = -2/2 = -1 y = mx + bslope(m) = -1use either of ur points (-2,0)…x = -2 …

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Which polynomial function has x intercepts –1, 0, and 2 and passes through the point (1, –6)? f(x) = x3 – x2 – 2x f(x) = 3×3 – 3×2 – 6x f(x) = x3 + x2 – 2x f(x) = 3×3 + 3×2 – 6x

Which polynomial function has x intercepts –1, 0, and 2 and passes through the point (1, –6)? f(x) = x3 – x2 – 2x f(x) = 3×3 – 3×2 – 6x f(x) = x3 + x2 – 2x f(x) = 3×3 + 3×2 – 6x

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W(x)=x^3 – 5x^2 + 8x – 4 I need the x and y intercepts and the behavior of this equation.

X intercept is where the line crosses the x axis or where y=0y intercept is where the line crosses the y axis or where x=0 the equation is 3rd degree and the leading coefient is positive so it goes from bottom left to top right, with 2 changes in direction …

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