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The longest wavelength within the visible spectrum is light

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# Tag: longest

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Quadrilateral ABCD ABCD is similar to quadrilateral EFGH EFGH. The lengths of the three longest sides in quadrilateral ABCD ABCD are 20 feet, 18 feet, and 14 feet long. If the two shortest sides of quadrilateral EFGH EFGH are 6 feet long and 5 feet long, how long is the 4th side on quadrilateral ABCD A:13 ft B:6.4ft C:9.2ft D:11.7

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The shortest wavelength of the spectrum is the Gamma Ray waves, they are 400nm and are the most deadly, because of how often and frequent they are able to vibrate. Shorter the wavelength the more active.

So the list from “shortest,” to “longest,” is,

Gamma Ray, X-Ray, Ultraviolet, Visible, Infrared, Microwave, and Radio wavelengths.

In the spectrum, Radio has the longest and furthest traveling waves. This means that they are not harmful and that they can travel extreme distances.

Hope this helps!

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PLEASE HELP Mr. Utterson the lawyer was a man of a rugged countenance, that was never lighted by a smile; cold, scanty and embarrassed in discourse; backward in sentiment; lean, long, dusty, dreary, and yet somehow lovable. At friendly meetings, and when the wine was to his taste, something eminently human beaconed from his eye; something indeed which never found its way into his talk, but which spoke not only in these silent symbols of the after-dinner face, but more often and loudly in the acts of his life. He was austere with himself; drank gin when he was alone, to mortify a taste for vintages; and though he enjoyed the theatre, had not crossed the doors of one for twenty years. But he had an approved tolerance for others; sometimes wondering, almost with envy, at the high pressure of spirits involved in their misdeeds; and in any extremity inclined to help rather than to reprove. “I incline to, Cain’s heresy*,” he used to say. “I let my brother go to the devil in his quaintly ‘own way.'” In this character, it was frequently his fortune to be the last reputable acquaintance and the last good influence in the lives of down-going men. And to such as these, so long as they came about his chambers, he never marked a shade of change in his demeanour. No doubt the feat was easy to Mr. Utterson; for he was undemonstrative at the best, and even his friendship seemed to be founded in a similar catholicity of good-nature. It is the mark of a modest man to accept his friendly circle ready-made from the hands of opportunity; and that was the lawyer’s way. His friends were those of his own blood or those whom he had known the longest; his affections, like ivy, were the growth of time, they implied no aptness in the object. Hence, no doubt, the bond that united him to Mr. Richard Enfield, his distant kinsman, the well-known man about town. It was a nut to crack for many, what these two could see in each other, or what subject they could find in common. It was reported by those who encountered them in their Sunday walks, that they said nothing, looked singularly dull, and would hail with obvious relief the appearance of a friend. For all that, the two men put the greatest store by these excursions, counted them the chief jewel of each week, and not only set aside occasions of pleasure, but even resisted the calls of business, that they might enjoy them uninterrupted. *The biblical story of Cain and Abel is a story about two brothers who gave offerings to God. Abel’s offering was accepted by God, but Cain’s was not. Jealous, Cain killed his brother. When God asked Cain where Abel was, Cain said, “Am I my brother’s keeper?” By saying this, Cain implied that what his brother did was his own business. (Genesis 4:1-16) What is significant about “Cain’s heresy” in this passage? A.It shows that Mr. Utterson is a deeply religious and righteous person. B.It shows that Mr. Utterson tries not to judge others or get in their business. C.It shows the Mr. Utterson wants to steal from other people’s businesses. D.It shows that Mr. Utterson does not believe in any kind of religion at all.

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check the picture

The 2 adjacent rectangles (corrals) form one larger rectangle.

as shown in the figure, let x be the length of the fences perpendicular to the river, then the length of the side opposite to the river will be 420- 2x (yard)

so we can write the following function, which calculates the area A enclosed by the fence, as a function of x.

A(x)=2x(420-2x)

clearly A is a quadratic function, its graph is a parabola. This parabola looks downwards because of the minus of the term -2x

from A(x)=2x(420-2x) we can find that the x intercepts of the parabola are:

one of the roots is x=0

and

420-2x=0,

2x=420

x=210 is the other root.

The x coordinate of the vertex is the midpoint of (0, 210), that is 210/2=105

f(105)=2*105(420-2*105)=210*(420-210=2110*210=44,100 square yard.

the highest point of the parabola is the largest value the function takes, so the maximal area of the fence.

Answer: max area= 44,100 square yard.

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1984, you might have been asked to read this one already in school, if not I suggest going ahead and reading it; its fun to be ahead of your class.

Originally published in 1949 by George Orwell, 1984 depicts a dystopian world of the ‘future’. The book is less of a prediction more then it is a warning of what could be. It follows one character who is desperately trying to remember what real life is like, and gets tangled up in all sorts of messes along the way.

You could read Alice in Wonderland or Mary Poppins, theres a million great classics out there Im sure you can find on any website.

Personally I prefer fantasy novels;

Brandon Sanderson’s The Rithmatist

This book follows a young student through a steampunk style, magic infused world. It takes a moment to not chuckle at the concept of monsters that are essentially drawings, but its a very well done book with beautiful writing and mental scenery

Patrick Rothfuss’s, The Name of the Wind

This is my favorite book of all time. Patrick Rothfuss’s work is honestly amazing in this book. Mind you its probably not all that wise for the feint of heart through perhaps the second chapter; but it really is amazing. The sculpting of the world, the depth of the characters its utterly masterful. The story opens with Kote, a fairly normal seeming innkeeper and his dark haired companion Bast. Fairly normal until a man happens upon the inn, looking for a certain Kvothe, a man thought to just be a legend and a story… and Kote’s past is drug up, and other things that should probably be better left alone.

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**Answer:**

Option C – BD=76 cm

**Step-by-step explanation:**

**Given :** You are designing a diamond-shaped kite. you know that AD = 44.8 cm, DC = 72 cm, and AC = 84.8 cm.

**To find : **How long BD should it be?

**Solution : **

First we draw a rough diagram.

The given sides were AD = 44.8 cm, DC = 72 cm and AC = 84.8 cm.

According to properties of kite

**Two disjoint pairs of consecutive sides are congruent.**

**So,** AD=AB=44.8 cm

DC=BC=72 cm

**The diagonals are perpendicular.**

**S**o, AC ⊥ BD

Let O be the point where diagonal intersect let let the partition be x and y.

AC= AO+OC

AC= …….[1]

Perpendicular bisect the diagonal BD into equal parts let it be z.

BD=BO+OD

BD=z+z

**Applying Pythagorean theorem in ΔAOD**

where H=AD=44.8 ,P= AO=x , B=OD=z

………[2]

**Applying Pythagorean theorem in ΔCOD**

where H=DC=72 ,P= OC=y , B=OD=z

…………[3]

**Subtract [2] and [3]**

……….[4]

**Add equation [1] and [4], to get values of x and y**

**Substitute x in [1]**

**Substitute value of x in equation [2], to get z**

**We know, **BD=z+z

BD= 38.06+38.06

BD= 76.12

**Nearest to whole number **BD=76 cm

**Therefore, Option c – BD=76 cm is correct.**

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A corresponds to L (first letters of each sequence)

B corresponds to M (second letters of each sequence)

C corresponds to P (third letters of each sequence)

In a similar fashion, the segments also correspond to one another.

AB corresponds to LM (first two letters of each sequence)

AC corresponds to LP (first and last letters of each sequence)

BC corresponds to MP (last two letters of each sequence)

————————————

AB corresponds to LM. AB is 4 units long. LM is 2 units long. So AB is twice as long as LM. This ratio (of 2:1) will be applied to every paired corresponding value.

Also, the right angle is at angle M for triangle LMP. The right angle will be at angle B for triangle ABC (since B corresponds to M). The answer will have an x coordinate of 7. So the answer is either choice B or choice C.

If we move 4 units down from point B, we land on (7,-10). That isn’t listed as an answer choice. Let’s try moving 4 units up from point B. We land on (7,-2). This is an answer choice

**So the final answer is choice C) (7,-2)**

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Since we do not know where the angle of 23 degrees is located, then we can find the remaining side using the Pythagorean theorem. This can be done because we know that we have a triangle with a right angle.

We have then:

From here, we clear the value of x.

We have then:

Then, the area of the triangle is given by:

Where,

b: base of the triangle

h: height of the triangle

Substituting values:

Note: Maybe the height of the triangle is 27.6 instead of 11.8. This will depend on where the angle of 23.8 is located.

But for the moment of looking for the area of the triangle, this is not relevant because the product of the base for the height is the same.

** Answer:**

** The approximate area of the triangle is:**

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notice, the concentration of alcohol in the 15% is, well, 0.15 :), so for a quantity of whatever, it’d be 0.15whatever

anyway, for water… water has no alcohol whatsoever, so the concentration is 0%, or 0/100 which is 0.00 or a flat 0

we know that we’ll be adding “x” water with the 14mL to get “y”, thus 14+x = y

and the concentrated quantities will also add up to -> 14(0.15) = 2.1, thus

2.1 + 0x = 0.07y

solve for “x”.

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**Answer:**

Option C – BD=76 cm

**Step-by-step explanation:**

**Given :** You are designing a diamond-shaped kite. you know that AD = 44.8 cm, DC = 72 cm, and AC = 84.8 cm.

**To find : **How long BD should it be?

**Solution : **

First we draw a rough diagram.

The given sides were AD = 44.8 cm, DC = 72 cm and AC = 84.8 cm.

According to properties of kite

**Two disjoint pairs of consecutive sides are congruent.**

**So,** AD=AB=44.8 cm

DC=BC=72 cm

**The diagonals are perpendicular.**

**S**o, AC ⊥ BD

Let O be the point where diagonal intersect let let the partition be x and y.

AC= AO+OC

AC= …….[1]

Perpendicular bisect the diagonal BD into equal parts let it be z.

BD=BO+OD

BD=z+z

**Applying Pythagorean theorem in ΔAOD**

where H=AD=44.8 ,P= AO=x , B=OD=z

………[2]

**Applying Pythagorean theorem in ΔCOD**

where H=DC=72 ,P= OC=y , B=OD=z

…………[3]

**Subtract [2] and [3]**

……….[4]

**Add equation [1] and [4], to get values of x and y**

**Substitute x in [1]**

**Substitute value of x in equation [2], to get z**

**We know, **BD=z+z

BD= 38.06+38.06

BD= 76.12

**Nearest to whole number **BD=76 cm

**Therefore, Option c – BD=76 cm is correct.**

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What is the name of Africa’s longest river?

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What is the longest book in the new testament

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**Answer:**

**The length of the rectangle is 64 cm.**

**The area of the square is 100 cm. sq.**

**Step-by-step explanation:**

**Given : **The length of a rectangle is 4 times than its width. The area of the rectangle is 1024 cm sq.

The perimeter of the rectangle 4 square has the same perimeter as that its rectangle.

**To find : **The length of the rectangle and Find the area of the square?

**Solution : **

Let l be the length of the rectangle.

Let w be the width of the rectangle.

The length of a rectangle is 4 times than its width i.e l=4w

**The area of the rectangle is **

**Reject negative value.**

The width of the rectangle is w=16 cm.

**The length of the rectangle is **

**Therefore, The length of the rectangle is 64 cm.**

**Now, **The perimeter of the rectangle 4 square has the same perimeter as that its rectangle.

**Perimeter of the rectangle is**

Perimeter of rectangle divides into 4 squares.

**i.e. **Perimeter of one square is

**Now, The side of the square is **

**The area of the square is **

**Therefore, The area of the square is 100 cm. sq.**

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Answers:

**10. A: Embarrassed by her appearance**, because she did not want Mr. Short to be seen suddenly and looking worn out.

This can be verified ” After two years’ separation** both were appalled by the change in the other.** One was wrinkled, the other haggard;…….” “After gazing at each other they hastily turned away,….Mrs. tall ran inside”

**11.A. impressed by the traditions that dictate his meals**, because after narrating that about a hundred main dishes were laid on six tables for the empress, the writer goes on to say that he had about thirty main dishes laid out for** show**. Though he also uses the word “**extravagance**” to describe the manner in which this tradition had been passed on from one empress to the other. Furthermore, he continues explaining, naming and detailing the personalities involved meals are elaboration of the meals presented to him”**The food I ate was sent over by the Empress Dowager, and after her death, by the High Consorts”**….that skilled chefs produced **twenty or more really delicious…….this was consumed by him **but that those prepared by the imperial kitchens **were set at a distance for the sake of appearances.**

**13.B: Admiring, **because they had tried to release the crane into the wild and while waiting for the bird to take its own initiative** they heard a shot **but **suddenly their bird “stretched its long neck with a whoop and disappeared into the sky**. For a long time the **boys could not take their eyes away** from the b**lue sky into which their crane had soared.**

**14. B: Social Life, **because the writer states at the end of the paragraph the Jane was already aware of** Rose´s life style, clothes, lovely house…everything she needed to make life good for her** but she also wanted to know how was her varsity life like.

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Answers:

**10. A: Embarrassed by her appearance**, because she did not want Mr. Short to be seen suddenly and looking worn out.

This can be verified ” After two years’ separation** both were appalled by the change in the other.** One was wrinkled, the other haggard;…….” “After gazing at each other they hastily turned away,….Mrs. tall ran inside”

**11.A. impressed by the traditions that dictate his meals**, because after narrating that about a hundred main dishes were laid on six tables for the empress, the writer goes on to say that he had about thirty main dishes laid out for** show**. Though he also uses the word “**extravagance**” to describe the manner in which this tradition had been passed on from one empress to the other. Furthermore, he continues explaining, naming and detailing the personalities involved meals are elaboration of the meals presented to him”**The food I ate was sent over by the Empress Dowager, and after her death, by the High Consorts”**….that skilled chefs produced **twenty or more really delicious…….this was consumed by him **but that those prepared by the imperial kitchens **were set at a distance for the sake of appearances.**

**13.B: Admiring, **because they had tried to release the crane into the wild and while waiting for the bird to take its own initiative** they heard a shot **but **suddenly their bird “stretched its long neck with a whoop and disappeared into the sky**. For a long time the **boys could not take their eyes away** from the b**lue sky into which their crane had soared.**

**14. B: Social Life, **because the writer states at the end of the paragraph the Jane was already aware of** Rose´s life style, clothes, lovely house…everything she needed to make life good for her** but she also wanted to know how was her varsity life like.

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Let:

a – the longest side

b – the middle side

c – the shortest side

The perimeter of a triangular plot of land is 2400 ft: P = 2400 ft

The perimeter of a triangle is P = a + b + c, thus a + b + c = 2400

The longest feet (a) is 200 ft less than twice the shortest (c): a = 2c – 200

The middle side (b) is 200 ft less than the longest side (a): b = a – 200

Now, we have the system of three equations:

a + b + c = 2400

a = 2c – 200

b = a – 200

__________

Substitute a from the second equation into the third equation:

b = 2c – 200 – 200 = 2c – 400

__________

Substitute a and b into the first equation:

(2c – 200) + (2c – 400) + c = 2400**2c **– 200 + **2c** – 400 + **c** = 2400**2c + 2c + c** – 200 – 400 = 2400

5c – 600 = 2400

5c = 2400 + 600

5c = 3000

c = 3000/5

c = 600 ft

_________

Now, use c and substitute into the second and third equation:

a = 2c – 200

a = 2 * 600 – 200

a = 1200 – 200

a = 1000 ft

___

b = a – 200

b = 1000 – 200

b = 800 ft

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