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## Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of 1/3? y + 2 =(x + 3) y – 2 = (x – 3) y + 3 = (x + 2) y – 3 = (x – 2)

Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of 1/3? y + 2 =(x + 3) y – 2 = (x – 3) y + 3 = (x + 2) y – 3 = (x – 2)

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## Identify both the x- and y-intercepts of the linear equation graphed on the coordinate plane above. Use the intercepts to write an equation of the line in point-slope form, slope-intercept form, and general form of a linear equation.Complete your work in the space provided or upload a file that can display math symbols if your work requires it. In your work, be sure to include the coordinates for both intercepts and the equations of the line in all three formats.

The x int (where the line crosses the x axis) is (-2,0)
the y int (where the line crosses the y axis) is (0,-2)

(-2,0)(0,-2)
slope = (-2 – 0) / (0 – (-2) = -2/2 = -1

y = mx + b
slope(m) = -1
use either of ur points (-2,0)…x = -2 and y = 0
sub and find b
0 = -1(-2) + b
0 = 2 + b
-2 = b

so ur equation in slope intercept form is : y = -x – 2

y = -x – 2
x + y = -2
x + y + 2 = 0 <== general form

there can be 2 answer for point slope form…
y – y1 = m(x – x1)
slope(m) = -1
(-2,0)…x1 = -2 and y1 = 0
sub
y – 0 = – (x – (-2)
y – 0 = -(x + 2) <=== point slope form

y – y1 = m(x – x1)
slope(m) = -1
(0,-2)…x1 = 0 and y1 = -2
sub
y – (-2) = – (x – 0)
y + 2 = – (x – 0) <== point slope form

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## What is the equation in point−slope form of the line passing through (−2, −5) and (2, 3)?

What is the equation in point−slope form of the line passing through (−2, −5) and (2, 3)?

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## Smitty’s car breaks down on a country road. He starts walking toward home at a rate of 1.25 miles an hour. After 0.75 hours, he is 3 miles from home. What is the point-slope formula for this information.

(A)

Step-by-step explanation:

It is given that lines v and w are parallel, then from the given figure, ∠2 and ∠6 form corresponding angle pair, therefore ∠2=∠6.

A.∠2+∠6=180°, his is incorrect because ∠2 and ∠6 form corresponding angle pair and are equal.

B.∠5≅∠8 because ∠5 and ∠8 form vertically opposite angle pair. Thus, this option is correct.

C.Since, sum of interior angles on the same side of transversal is 180°, therefore ∠3+∠5=180°, thus this option is correct.

D.∠1≅∠5 because ∠1 and ∠5 form the corresponding angle pair and are equal. Thus, this option is correct.

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## What is the equation in point-slope form of the line passing through (1, 9) and (−1, 11)?

What is the equation in point-slope form of the line passing through (1, 9) and (−1, 11)?

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## Write an equation in​ point-slope form of the line that passes through the given​ points, then write the equation in​ slope-intercept form. ​(−9​,7​), ​(9,11) What is the​ point-slope form of the equation of the​ line?

width of the rectangular prism is 4.5 inches.

Step-by-step explanation:

Carltren solves for w and writes the equivalent equation as

Now, we have to find the width of a rectangular prism that has a volume of 138.24 cubic inches a height of 9.6 inches and a length of 3.2 inches.

Thus, we have

V = 138.24 cubic inches

l = 3.2 inches

h = 9.6 inches.

Substituting these values in the above formula to find w

On simplifying, we get

Thus, width of the rectangular prism is 4.5 inches.

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## If a line has a slope of 2 and contains the point (-2, 1), what is its equation in point-slope form?

Slope-intercept form is y = mx + b, so to turn that equation into slope-intercept you’ll need to get y alone

4x – 8y = 8 — subtract 4x
-8y = 8 – 4x — divide by -8
y = -1 + (1/2)x — reorder to match “mx + b”
y = (1/2)x – 1

in y = mx + b, “m” is the slope and “b” is the y-intercept. so for part B, your slope is (1/2) and your y-intercept is (-1). take the sign with you.

for part C, you’ll need to know point-slope form: (y – y1) = m(x – x1)
you’ll also need to be aware that “perpendicular” lines have a slope that is the opposite reciprocal of the original line.

the original slope is (1/2). change the sign to negative and form a reciprocal: your new slope is -2. plug that into your point-slope form

(y – y1) = m(x – x1)
(y – y1) = (-2)(x – x1)

and lastly, plug in your given point: (1, 2)

y – 2 = (-2)(x – 1)

so, just to look a little neater without all of the work:
A) y = (1/2)x – 1
B) m = (1/2), b = -1
C) y – 2 = (-2)(x – 1)