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A random sample of 25 statistics examinations was taken. the average score in the sample was 76 with a standard deviation of 12. assuming the scores are normally distributed, the 99% confidence interval for the population average examination score is:

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Since the sample size is less than 30, therefore we use
the t statistic.

Let us define the given variables:

N = sample size = 25

X = average score = 76

s = standard deviation = 12

99% Confidence interval

Degrees of freedom = n – 1 = 24

 

The formula for confidence interval is given as:

CI = X ± t * s / sqrt N

 

using the standard distribution table, the t value for DF
= 24 and 99% CI is:

t = 2.492

 

Therefore calculating the CI using the known values:

CI = 76 ± 2.492 * 12 / sqrt 25

CI = 76 ± 5.98

CI = 70.02, 81.98

 

Answer: The average score ranges from 70 to 82.

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The durations of a random sample of 16 commercials are below (in seconds). find the mean, median, and mode of these durations. 30, 12, 26, 7, 14, 35, 20, 30, 55, 8, 35, 18, 42, 15, 30, 10

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First arrange in ascending order of time:-

7, 8, 10, 12, 14, 15, 18, 20, 26, 30, 30, 30, 35, 35, 42, 55

MOde is the value occuring mos  = 30.

Median is the mean of 2 middle numbers = (20 + 26) / 2 = 23

Mean = sum of the 16 numbers  / 16  =  387/16  = 24.2

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What price do farmers get for the peach crops? in the third week of June, a random sample of 40 farming regions gave a sample mean of $6.88 per basket. assume that the standard deviation is known to be $1.92 per basket. find a 90% confidence interval for the population mean price per basket that farmers in this region get for their peach crop

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Given:
Sample size, n = 40
Sample mean, xb = $6.88
Population std. deviation, σ = $1.92 (known)
Confidence interval = 90%

Assume normal distribution for the population.
The confidence interval is
(xb + 1.645*(σ/√n), xb – 1.645*(σ/√n)
= (6.88 + (1.645*1.92)/√40, 6.88 – (1.645*1.92)/√40)
= (7.38, 6.38)

Answer: The 90% confidence interval is (7.38, 6.38)

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bridge hand is made up of 13 cards from a deck of 52. Find the probability that a hand chosen at random contains at least 1 nine. The probability that a bridge hand chosen at random contains at least 1 nine is:

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C(n,r) = n!/(r!(n-r)!)

You take the number of possible 13 card hands with no 9 in them and subtract that from the total number of possible 13 card hands 9’s included.

so C(52,13) – C(48,13)
The number of all possible 13 card hands is:
52!/13!(52-13)! or 52!/13!*39! which is 635,013,559,600

The number of all possible 13 card hands with no 9s is:

48!/13!(48-13)!  or 48!/13!*35! = 192,928,249,296

The difference is 635,013,559,600 – 192,928,249,296 = 442,085,310,304

So 442,085,310,304 out of 635,013,559,600 hands will have at least 1 nine.  The ratio of  442,085,310,304 to 635,013,559,600 is 0.696182472…  So roughly 70% of the time 

27,630,331,894/39,688,347,475 is the best I could do for a whole number ratio.

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You put the names of all the students in your class in a paper bag. There are 14 boys and 16 girls. If you draw a name at random, what is P(boy’s name)?

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You put the names of all the students in your class in a paper bag. There are 14 boys and 16 girls. If you draw a name at random, what is P(boy’s name)?

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Given that the random variable x is normally distributed with a mean of 80 and a standard deviation of 10, p(85 < x < 90) is

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Given that the random variable x is normally distributed with a mean of 80 and a standard deviation of 10, p(85 < x < 90) is

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Dana downloads music into her computers random access memory, or ram, without authorization. this is?

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Dana downloads music into her computers random access memory, or ram, without authorization. this is?

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A bag contains 10 marbles: 4 are green, 4 are red, and 2 are blue. Heather chooses a marble at random, and without putting it back, chooses another one at random. What is the probability that both marbles she chooses are blue? Write your answer as a fraction in simplest form.

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Employee                                 Mary      Zoe         Greg         Ann           Tom

Cumulative Pay                       $6,800   $10,500  $8,400    $66,000   $4,700

Pay subject to FICA S.S.         $421.60  $651.00  $520.80 $4092.00 $291.40
6.2%, (First $118,000)

Pay subject to FICA Medicare $98.60 $152.25    $121.80    $957.00    $68.15
1.45% of gross

Pay subject to FUTA Taxes      $40.80  $63.00     $50.40    $396.00  $28.20
0.6%

Pay subject to SUTA Taxes   $367.20  $567.00  $453.60  $3564.00 $253.80
5.4% (First $7000)

Totals                                     $928.20 $1,433.25 $1,146.60 $9,009.00 $641.55

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A dog breeder currently has 9 breeding dogs. 6 of the dogs have exactly 1 littermate, and 3 of the dogs have exactly 2 littermates. if 2 dogs are selected at random, what is the probability that both selected dogs are not littermates?

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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In square qrst, points u and v are midpoints. if the square has a side length of 18 mm, what is the probability that a point chosen at random in the square lies in the shaded triangle region? round the answer to the nearest thousandth. a. 0.028 b. 0.056 c. 0.125 d. 0.222

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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Which statement would the character Grendel most likely agree with, based on his outlook on life? A. Life is made up of random events with accidental consequences. B. Life is a chance to punish the beautiful with pain and reward the ugly with peace. C. Life is meant to be adventurously defeating the boredom that threatens. D. Life is good for the brave and bad for the cowardly.

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Here are a few pointers; hope this is useful)

Ovation-by definition- is show of appreciation from an audience, for a person’s accomplishments or flaw.

“Everyone deserves a standing ovation because we all overcometh the world.”

A person’s accomplishment could be how they made a positive change in this world, strong leadership- that makes them a effective leader or simply helping others. A person’s flaw- mistakes in life, sin or even guilt should also be considered an appreciation- an ovation for representing mankind’s flaw and that humanity makes mistakes, fulfilling at least one deadly sin such as greed, lust, selfishness etc.

Thus, regardless of a person’s achievement or flaw- a person deserves an applause for, not the least, living in this society and this world that we are all living together and dying together.

That was just the introduction.. the best part is yet to come.. now it’s your turn!!

Here are other pointers to talk about in your essay:

Shakespeare’s famous line “All the World’s a stage. That agrees with your line: “Everybody deserves a standing ovation…”

Shakespeare explains that men and women are like players: they live, and die, some being celebrated and some forever living in solitude till their death. Shakespeare states the world is a “stage” which symbolizes that mankind is in its peak. The world is changing everyday: little by little and humanity is falling behind.
Due to our world turning into machinery: factories, an automotive future: where humans only job to live (entrance) and to die (exit) the famous humans remembered and the flawed not recalled.

This is according to Shakespeare’s imagery.

I don’t know what grade your in, but I think simplifying Shakespeare’s word of mouth in your essay would be handy and useful as it has strong references of your quote, and agrees strongly in your essay.

Hope this helps 🙂

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At equilibrium what happens to the random movement of molecules

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Answer:

Rate of movement of snail, s = 0.25 meters per hour

Explanation:

It is given that,

Distance covered by snail, d = 0.5 m

The snail moved this distance in 2 hours

Since, 1 hour = 3600 seconds

So, 2 hour = 7200 seconds

We have to find the rate of movement of snail i.e. s

s=dfrac{d}{t}

So,

s=dfrac{0.5}{7200}

s = 0.000069 m/s

Converting m/s to m/h

So, s = 0.248 m/h

or s = 0.25 meters per hour

Hence, the correct option is (d)

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A person in a casino decides to play blackjack until he loses a game, but he will not play more than 3 games. let l denote a loss and w denote a win. what is the sample space for this random experiment

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Answer:

The age of a rock is determined by the function:

A(t) = A_0 cdot e^{-0.000002t}             …..[1]

where,

A(t) be the age of rock after t years

A_0 be the initial value of Isotope Q.

t be the number of years.

As per the statement:

A sample originally has 80 grams of Isotope Q, decays, and now has 20 grams of the isotope.

A_0 = 80 gram and A(t) = 20 grams

Substitute in [1] we have;

20 =80 cdot e^{-0.000002t}

Divide both sides by 80 we have;

0.25 = e^{0.000002t}

Taking ln with base e both sides we have;

ln 0.25 = -0.000002t

-1.3862943611199 = -0.000002t

Divide both sides by 0.000002 we have;

693147.18056  = t

or

t = 693147.18056  years

Therefore, the current age of the sample, in years to the nearest thousand years is, 6,93,147 year

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Half of the population of cool town owns a bicycle, and 25% of the population owns a car. if 10% of the population owns both a car and a bicycle, what is the probability that a person chosen at random from cool town owns either a car or a bicycle or both?

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Answer:  The correct option is (C). 10 = square root of the quantity of x minus 8 all squared plus y minus 9 all squared

Step-by-step explanation:  Given that the segment AB has point A located at (8, 9). The distance from A to B is 10 units.

We are to select the correct option that could be used to calculate the coordinates for point B.

Let, (x, y) be the co-ordinates of point B.

According to distance formula, the distance between two points (a, b) and (c, d) is given by

d=sqrt{(c-a)^2+(d-b)^2}.

Therefore, the distance between the points A(8, 9) and B(x, y) is given by

d=sqrt{(x-8)^2+(y-9)^2}.

Since, distance between A and B is 10 units, so

d = 10.

Therefore,

10=sqrt{(x-8)^2+(y-9)^2}.

Thus, the correct statement is

10 = square root of the quantity of x minus 8 all squared plus y minus 9 all squared.

Option (C) is correct.

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Exit A bag contains 4 red marbles and 5 blue marbles. If two marbles are chosen at random, one at a time and without replacement, what is the probability of getting two red marbles?

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Exit A bag contains 4 red marbles and 5 blue marbles. If two marbles are chosen at random, one at a time and without replacement, what is the probability of getting two red marbles?

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A random change in allele frequency is called __________. genetic drift stabilizing selection directional selection natural selection

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A random change in allele frequency is called __________. genetic drift stabilizing selection directional selection natural selection

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Identify the sampling method used. every third student signing up for astronomy class is asked about telescope preferences.. a. systematic c. stratified b. random

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The Venn diagram is not included, so I am going to explain the procedure and you will be able to calculate the result just plugging the numbers.

From Vend diagram you will be able to conclude two numbers:

1) the total number os students surveyed that participate in band (B)

2) the total number of students surveyed that participate in track (T)

3) the total number of students surveyed that participate in both band (B) and track (T) = B∩T

4) ) the total number of students surveyed, which is: total number of students in band B + total number of students in track – less the number of students that participate in both. = B + T – (B∩T)

So, the probability that one student that participate in band (B) also participate in track (T) =

Number of students that participate in both / number of students that participate in band = (B∩T) / B

Now, you just have to find B∩T and B from the diagram and plugg in into the formula (B∩T)/B. That’s it.

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A jar of coins contains 8 pennies, 5 nickels, 12 dimes, 7 quarters. you choose a coin at random, do not replace it, and then choose another coin. what is probability of choosing a dime first and quarter second

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A jar of coins contains 8 pennies, 5 nickels, 12 dimes, 7 quarters. you choose a coin at random, do not replace it, and then choose another coin. what is probability of choosing a dime first and quarter second

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A continuous random variable is a random variable that can: ?assume any value in one or more intervals ?assume no continuous random frequency ?have no random sample ?assume only a countable set of values

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Answer:

False

Step-by-step explanation:

Suposse that we are given a function f(x) and a constant value h.

1. Case:

If we take the function g(x)=f(x)+h, then the graph of the function g(x) will be the graph of the funcion f(x) moved up or down.

2.Case:

If we take the function g(x)=hf(x), then the graph of the function g(x) will be the graph of the function f(x) just taller or shorter.

3.Case:

If we take the function g(x)=f(x-h), then the graph of the function g(x) will be the graph of the fuction f(x) moved horizontally.

4. Case:

If we take the function g(x)=f(hx), then the graph of the function g(x) will be tha graph of the function f(x) wither or thiner.

For example:

If we take f(x)=sin(x) and h=2. Then, if we take g(x)=sin(2x) then f(0)=g(0)=0, which means that the graph of the functiction is not moved up or down. However, f(π/2)=sin(π/2)=1 and g(π/2)=sin(π)=0 which gives us a hint that the graph of the function became thiner.

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A record label surveyed 150 random visitors to its website to discover whether they prefer metal, rock, hip-hop, or jazz. The survey showed that 27 visitors preferred metal, 78 preferred rock, 21 voted for hip-hop, and 24 liked jazz. If the company estimates sales of 6,000 copies a week at its online store, how many will likely be from the rock genre? 1,040 3,000 3,120 4,200

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A record label surveyed 150 random visitors to its website to discover whether they prefer metal, rock, hip-hop, or jazz. The survey showed that 27 visitors preferred metal, 78 preferred rock, 21 voted for hip-hop, and 24 liked jazz. If the company estimates sales of 6,000 copies a week at its online store, how many will likely be from the rock genre? 1,040 3,000 3,120 4,200

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In order to create unity in a paragraph, the sentences following a topic sentence must _____. Contain random and interesting ideas Follow random train of thought Contain the controlling idea of paragraph Support the controlling idea

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Hey there!

Correct answer is D. Comma or Period Inside Rule

A. Question mark or exclamation point inside: those are not really necessary.

B. Colon or semicolon: not, a semicolon would divide the whole sentence and it would be shorten; a colon would work but after requested, when there is already a comma.

C. Question mark or Exclamation Point Outside Rule: would not work, becase it is an very polite and affirmative sentence.

D: A comma or period inside rule: actually, just a comma would work. Please, Cooper’s dad requested, go… Cooper’s dad requested must be in between commas as it is a vocative.

Hope this helps

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PLEASE RESPOND QUICK WITH THE CORRECT ANSWER OR YOU WILL GET REPORTED (08.03)Magdeline wants to know if the number of words on a page in her computer science book is generally more than the number of words on a page in her math book. She takes a random sample of 25 pages in each book and then calculates the mean, median, and mean absolute deviation for the 25 samples of each book. Book Mean Median Mean Absolute Deviation Computer science 48.7 40 9.4 Math 34.2 45 1.9 She claims that because the mean number of words on each page in the computer science book is greater than the mean number of words on each page in the math book, the computer science book has more words per page. Based on the data, is this a valid inference?

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Employee                                 Mary      Zoe         Greg         Ann           Tom

Cumulative Pay                       $6,800   $10,500  $8,400    $66,000   $4,700

Pay subject to FICA S.S.         $421.60  $651.00  $520.80 $4092.00 $291.40
6.2%, (First $118,000)

Pay subject to FICA Medicare $98.60 $152.25    $121.80    $957.00    $68.15
1.45% of gross

Pay subject to FUTA Taxes      $40.80  $63.00     $50.40    $396.00  $28.20
0.6%

Pay subject to SUTA Taxes   $367.20  $567.00  $453.60  $3564.00 $253.80
5.4% (First $7000)

Totals                                     $928.20 $1,433.25 $1,146.60 $9,009.00 $641.55

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Urgent I need it for an assignment!!A dog store has 3 female Chihuahuas. 14 of the 25 dogs at the store are not Chihuahuas. What is the probability that a dog selected at random is female, given it is a Chihuahua? A. 3/25 B. 3/14 C. 3/11 D. 11/25

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You need to determine the number of ways in which 30 competitors from 50 can qualify. First, you have to realize that the order is irrelevant, that is: it is the same competitor_1, competitor _2, competitor _3 than competitor_3, competitor_2, competitor_1, or any combination of those three competitors.

So, the number of ways is which 30 competitors from 50 can qualify is given by the formula of combinations, which is:

C (m,n) = m! / (n! * (m -n)! )

=> C (50,30) = 50! / (30! (50 – 30)! ) = (50!) / [30! (50 – 30)!] = 50! / [30! 20!] =

 = 47,129,212,243,960 different ways the qualifiying round of 30 competitors can be selected from the 50 competitors.

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A number is chosen at random from the first twenty integers. Find the probability that the number is a multiple of 3. 3/10 3/5 6

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127=7 (mod n) means when 127 is divided by n, the division leaves a remainder of 7.

The statement is equivalent to
120=0 (mod n), meaning that n divides 120.

All divisors of 120 will satisfy the statement because 120 divided by a divisor (factor) will leave a remainder of 0.

Factors of 120 are:
n={1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120}, |n|=16.
You can count how many such values of n there are, and try to check that each one satisfies 127=7 mod n.

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A bag contains 10 marbles: 4 are green, 2 are red, and 4 are blue. Christine chooses a marble at random, and without putting it back, chooses another one at random. What is the probability that both marbles she chooses are blue? Write your answer as a fraction in simplest form.

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Answer:                

The probability  that both marbles she chooses are blue is frac{2}{15}

Step-by-step explanation:

Given : A bag contains 10 marbles: 4 are green, 2 are red, and 4 are blue. Christine chooses a marble at random, and without putting it back, chooses another one at random.

To find : What is the probability that both marbles she chooses are blue?

Solution :

Total number of marbles = 10

Green marbles = 4

Red marbles = 2

Blue marbles = 4

Probability is favorable outcome upon total number of outcomes.

Probability of getting first marble is blue

text{P(first blue marble)}=frac{4}{10}=frac{2}{5}.

Without replacement,

i.e. Blue marble left = 3

Total marble left = 9


Probability of getting second marble is blue

text{P(second blue marble)}=frac{3}{9}=frac{1}{3}

The probability that both marbles she chooses are blue is

text{P(both blue marble)}=frac{2}{5}timesfrac{1}{3}

text{P(both blue marble)}=frac{2}{15}

Therefore, The probability  that both marbles she chooses are blue is frac{2}{15}

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