To solve this problem,

we can use the Henderson-Hasselbalch Equation which relates the pH to the measure

of acidity pKa. The equation is given as:

pH = pKa + log ([base]/[acid]) —> 1

Where,

[base] = concentration

of C2H3O2

in molarity or moles

[acid] = concentration of HC2H3O2 in molarity or moles

For the sake of easy calculation, let us assume that:

[base] = 1

[acid] = x

Therefore using equation 1,

4.24 = 4.74 + log (1 / x)

log (1 / x) = – 0.5

1 / x = 0.6065

x =

1.65

**The required ratio of C2H3O2 /HC2H3O2 ****is 1:1.65 or 3:5. **