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A firefighter stood on the middle rung of a ladder, spraying water on a fire. the smoke lessened, so she moved up 3 rungs. it got too hot, so she backed down 5 rungs. later, she went up 7 rungs and stayed until the fire was out. then, she climbed the remaining 4 rungs and went into the building. how many rungs does the ladder have?

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A firefighter stood on the middle rung of a ladder, spraying water on a fire. the smoke lessened, so she moved up 3 rungs. it got too hot, so she backed down 5 rungs. later, she went up 7 rungs and stayed until the fire was out. then, she climbed the remaining 4 rungs and went into the building. how many rungs does the ladder have?

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1. If 500 ML of a 3 L sample of 0.20 M sodium chloride solution is spilled, what is the concentration of the remaining solution? A. 300 M B. .033 M C. 15.2 M D. .20 M

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D. 0.2 MThe concentration of a solution is basically the ratio of the solute present to the solvent in the solution. This is an intrinsic property, independent of the amount of solution that is present. A similar example is that of density. No matter the size of a sample, the density and concentration of that sample remain constant.

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Stress surrounds us on a daily basis. Which of the following statements BEST describes ways to reduce or handle stress? A. Handling stress effectively involves ignoring stressors and remaining silent about stressful issues. B. Handling stress effectively involves recognizing what your stressors are, developing healthy behaviors to minimize stress, and adopting positive coping skills. C. Handling stress effectively involves recognizing what stressors are and visiting a psychologist weekly to discuss stressful issues. D. Handling stress effectivley involves doing whatever it takes to erase the stressful issue from your mind.

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1. The answer is “C”.

“Identical twins” who have been raised apart are typically more similar in intelligence level than biological siblings raised together because they have been born with the same genetic code.

Identical twins originate from a single fertilized egg that parts into two. Before it parts, it is either male or female. After it parts, there are either two guys or two females. The two sections of the fertilized egg embed in the uterus and every create one of the twins.  

Identical twins have the equivalent hereditary source. No immediate reason for monozygotic twinning has been resolved; it isn’t innate. Monozygotic twins speak to around 33% all things considered. They may look strikingly comparative, and it might be hard to reveal to them separated.

2. The answer is “A”.

Lawrence Kohlberg felt that one of the only ways individuals will accomplish the objectives in each of his six stages was to participate in “consensus democracy” in small group settings.

Lawrence Kohlberg felt that the best way to support development through these stages was by discourse of good problems and by investment in consensus democracy inside small groups. Consensus democracy was rule by understanding of the gathering, not larger part rule. This would invigorate and widen the reasoning of youngsters and grown-ups, enabling them to advance starting with one phase then onto the next.

3. The answer is “D.  showing a learner how to correct common mistakes”.

The term scaffolding alludes to a procedure in which instructors display or exhibit how to take care of an issue, and afterward venture back, offering support as required. Analyst and instructional architect Jerome Bruner first utilized the term ‘scaffolding’ in this setting, harking back to the 1960s. The hypothesis is that when understudies are given the help they require while discovering some new information, they stand a superior possibility of utilizing that learning freely. Bruner suggests positive association and three methods of portrayal amid educating: activities, pictures, and dialect.  

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The half-life of sodium-22 is 2.6 years. A sample contains 800 mg of this isotope. Which expression represents the mass.od sodium remaining after h half-lives?

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The half-life of sodium-22 is 2.6 years. A sample contains 800 mg of this isotope. Which expression represents the mass.od sodium remaining after h half-lives?

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Find the remaining sides of a 45°-45°-90° triangle if the longest side is 20.

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Since we do not know where the angle of 23 degrees is located, then we can find the remaining side using the Pythagorean theorem. This can be done because we know that we have a triangle with a right angle.

We have then:
 27.6 ^ 2 + x ^ 2 = 30 ^ 2

From here, we clear the value of x.

We have then:

 x ^ 2 = 30 ^ 2 - 27.6 ^ 2x = sqrt{30 ^ 2 - 27.6 ^ 2}x = 11.8

Then, the area of the triangle is given by:

 A = (frac{1}{2}) * (b) * (h)

Where,

b: base of the triangle

h: height of the triangle

Substituting values:

 A = (frac{1}{2}) * (27.6) * (11.8)A = 162.8 ft ^ 2

Note: Maybe the height of the triangle is 27.6 instead of 11.8. This will depend on where the angle of 23.8 is located.

But for the moment of looking for the area of the triangle, this is not relevant because the product of the base for the height is the same.

Answer:

The approximate area of the triangle is:

 A = 162.8 ft ^ 2

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I'm stuck on this question, PLZ HELP. –Mama Mia restaurant used 1/2 of their mozzarella cheese making pizza and the remaining 64 ounces making pasta. How many pounds of mozzarella cheese did Mama Mia start with?

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I’m stuck on this question, PLZ HELP. –Mama Mia restaurant used 1/2 of their mozzarella cheese making pizza and the remaining 64 ounces making pasta. How many pounds of mozzarella cheese did Mama Mia start with?

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how would you solve for the length of the remaining side?

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how would you solve for the length of the remaining side?

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Six identical squares are cut from the corners and edges of an 80 cm by 50 cm cardboard rectangle. the remaining piece is folded into a closed box with 3 flaps. what is the largest possible volume of such a box?

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Solution:

The Given Rectangle having dimensions

Length = 80 cm

Breadth = 50 cm

Let the Six squares which has been cut from this rectangle have side of length a cm.

Area of each square = (Side)²= a²

Area of 6 Identical Squares = 6 × a²= 6 a²

If four squares are cut from four corners and two along Length,

then , Length of Box = (80 – 3 a)cm, Breadth of Box = (50 – 2 a)cm, Height = a cm

Volume of Box =V = Length × Breadth × Height

    V = (80 – 3 a)× (50 – 2 a)× a

     V   = 4000 a – 310 a² + 6 a³

For Maximum Volume

V’= 0 , where V’ = Derivative of V with respect to a.

V’= 4000 – 620 a + 18 a²

V’ =0

18 a² – 620 a + 4000= 0

9 a² – 310 a + 2000=0

using determinant method

a = frac{310pmsqrt{96100-72000}}{18}=frac{310pm155}{18}=frac{310-155}{18}=8.6 cm

V”=1 8 a – 310 = -ve

which shows , when a = 8.6 cm , volume is maximum.

So, V = 4000×8.6 – 310×(8.6)²+6×(8.6)³=15288.736 cm³

OR

If four squares are cut from four corners and two along Breadth,

then , Length of Box = (80 – 2 a)cm, Breadth of Box = (50 –  3 a)cm, Height = a cm

Volume of Box =V = Length × Breadth × Height

    V = (80 – 2 a)× (50 – 3 a)× a

     V   = 4000 a – 340 a² + 6 a³

For Maximum Volume

V’= 0 , where V’ = Derivative of V with respect to a.

V’= 4000 – 680 a + 18 a²

V’ =0

18 a² – 680 a + 4000= 0

9 a² – 340 a + 2000=0

Using Determinant method

a = frac{340pmsqrt{115600-72000}}{18}=frac{340pm209}{18}=frac{131}{18}=7.6 cm

V”=18 a -340= -ve value when a = 7.6 cm, shows volume is maximum when a = 7.6 cm

V= 4000×7.6 -340 × (7.6)² +6× (7.6)³=13395.456 cubic cm

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Raymond estimates that the fixed costs associated with opening a new bank branch are $500,000. he expects the branch to attract 1,000 new customer accounts in the first year, each of which will cost $50 per year to service. he also expects to generate $100,000 per year in revenue. for raymond, the total cost of opening the new branch and remaining open for one year will be

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The Contribution Margin per unit (CM) can be calculated
from the difference of Selling Price per unit (SP) and Total Expenses per unit
(TE).

 

First, let’s calculate the value of SP:

SP = Sales / Units sold

SP = $1,043,400 / 22,200 units sold

SP = $47

 

Second, calculate all expenses:

Direct materials per unit = $234,948 / 27,970 units
manufactured = $8.4

Direct labor per unit = $131,459 / 27,970 units
manufactured = $4.7

Variable manufacturing overhead per unit = $240,542 / 27,970
units manufactured = $8.6

Variable selling expenses per unit = $113,220 / 22,200
units sold = $5.1

TE = $26.8

 

Therefore the CM is:

CM = SP – TE

CM = $47 – $26.8

CM = $20.2 per unit

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A company used straight-line depreciation for an item of equipment that cost $16,950, had a salvage value of $4,200 and a six-year useful life. after depreciating the asset for three complete years, the salvage value was reduced to $1,695 but its total useful life remained the same. determine the amount of depreciation to be charged against the equipment during each of the remaining years of its useful life:

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The Contribution Margin per unit (CM) can be calculated
from the difference of Selling Price per unit (SP) and Total Expenses per unit
(TE).

 

First, let’s calculate the value of SP:

SP = Sales / Units sold

SP = $1,043,400 / 22,200 units sold

SP = $47

 

Second, calculate all expenses:

Direct materials per unit = $234,948 / 27,970 units
manufactured = $8.4

Direct labor per unit = $131,459 / 27,970 units
manufactured = $4.7

Variable manufacturing overhead per unit = $240,542 / 27,970
units manufactured = $8.6

Variable selling expenses per unit = $113,220 / 22,200
units sold = $5.1

TE = $26.8

 

Therefore the CM is:

CM = SP – TE

CM = $47 – $26.8

CM = $20.2 per unit

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A truck with a cost of $82,000 has an estimated residual value of $16,000, has an estimated useful life of 12 years, and is depreciated by the straight-line method. a. determine the amount of the annual depreciation. $ b. determine the book value at the end of the seventh year of use. $ c. assuming that at the start of the eighth year the remaining life is estimated to be six years and the residual value is estimated to be $12,000, determine the depreciation expense for each of the remaining six years. $

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A truck with a cost of $82,000 has an estimated residual value of $16,000, has an estimated useful life of 12 years, and is depreciated by the straight-line method. a. determine the amount of the annual depreciation. $ b. determine the book value at the end of the seventh year of use. $ c. assuming that at the start of the eighth year the remaining life is estimated to be six years and the residual value is estimated to be $12,000, determine the depreciation expense for each of the remaining six years. $

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Everything else remaining unchanged, an increase in the supply of security a and a decrease in the demand for security b will cause the price of security a to ____ and the price of security b to ____.

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There are two
basic subjects for security design principle the simplicity – KISS which makes
design and connections easy and easy to verify its safety and the other one is
restriction which is to lessen the power of entities. There are 8 security
design principles listed are the following:

·      
The least
privilege principle which the entity should be set only those privilege
needed to finish a task. The temporary elevation of opportunity should be give
up immediately and append permission only for logging procedure.

·      
The fail
safe defaults principle which unless a subject is given clear access to an
object and it should be deprived of access to the object. The default access is
none and restriction privileges at the time of creation.

·      
The economy
of mechanism principle which security mechanism must be as simple as
possible and testing and verification is easy because expectations are less and
interface to other modules is implicit.

·      
The complete
mediation principle which all right of entry to objects should be tested to
ensure they are allowed.

·      
The open
design principle which security of device should not rest on confidentiality
of its execution.

·      
The separation
of privilege principle which system should not grant authorization based on
single circumstance.

·      
The least
common mechanism principle which devices used to factual of entry resources
should not be communal.

·      
The psychological
acceptability principle which security device should not make the source hard
to access and distinguishes the most significant part in computer system which
is the human.

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A rock has 25 percent of its original amount of potassium-40 remaining in it; potassium-40 has a half-life of 1.25 billion years. How long ago was the rock formed? 1.25 billion years ago 2.50 billion years ago 5.00 billion years ago 6.25 billion years ago

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Answer: The percent yield of NO is 71.43 %.

Explanation:

To calculate the number of moles, we use the equation:

text{Number of moles}=frac{text{Given mass}}{text{Molar mass}}      …..(1)

Given mass of ammonia = 9.5 g

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

text{Moles of ammonia}=frac{9.5g}{17g/mol}=0.56mol

The given chemical equation follows:

4NH_3+5O_2rightarrow 4NO+6H_2O

By Stoichiometry of the reaction:

4 moles of ammonia produces 4 moles of NO

So, 0.56 moles of ammonia will produce frac{4}{4}times 0.56=0.56mol of NO

Now, calculating the mass of NO from equation 1, we get:

Molar mass of NO = 30 g/mol

Moles of NO = 0.56 moles

Putting values in equation 1, we get:

0.56mol=frac{text{Mass of NO}}{30g/mol}\\text{Mass of NO}=(0.56moltimes 30g/mol)=16.8g

  • To calculate the percentage yield of NO, we use the equation:

%text{ yield}=frac{text{Experimental yield}}{text{Theoretical yield}}times 100

Experimental yield of NO = 12.0 g

Theoretical yield of NO = 16.8 g

Putting values in above equation, we get:

%text{ yield of NO}=frac{12.0g}{16.8g}times 100\\% text{yield of NO}=71.43%

Hence, the percent yield of NO is 71.43 %.

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The original amount of radioactive substance is 10 grams. After several years, 2.5 gtams of the substance is remaining. How many half-lives havr passed since the mass of the subtance was 10 grams?

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Answer: The empirical formula of the compound is SO_2

Explanation:

To know the empirical formula of the compound, we will follow some steps:

Step 1: Converting all these percentages into mass.

We take the total mass of the compound to be 100 grams, so, the percentages given for each element becomes its mass.

Mass of Sulfur = frac{50.05}{100}times 100g=50.05g

Mass of Oxygen = frac{49.94}{100}times 100g=49.95g

Molar mass of Sulfur = 32 g/mol

Molar mass of Oxygen = 16 g/mol  

Step 2: Converting the given masses into their respective moles.

Moles of Sulfur = frac{text{Given mass of S}}{text{Molar mass of S}}= frac{50.05g}{32g/mole}=1.56moles

Moles of Oxygen = frac{text{Given mass of O}}{text{Molar mass of O}}= frac{49.95g}{16g/mole}=3.12moles

Step 3: Now, calculating mole ratio, we divide each number of moles by the smallest number of moles calculated.

For Sulfur = frac{1.56}{1.56}=1  

For Oxygen = frac{3.12}{1.56}=2

The ratio of S : O = 1 : 2

Step 4: Writing the mole ratio of the element as the subscripts in molecular formula.

Empirical formula of the compound : SO_2

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Ramone has 5 difficult questions left to answer on a multiple choice test. Each question has 3 choices. For the first 2 of these questions, he eliminated 1 of the 3 choices. find the probability that he will answer the first 2 questions, as well as at least 2 of the 3 remaining questions correctly.

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1. a b c
2. a b c
3. a b c
4. a b c
5. a b c

then she eliminated 1 choice in 1 and 2, say as follows

1.    b c
2. a b 
3. a b c
4. a b c
5. a b c

Probability of answering correctly the first 2, and at least 2 or the remaining 3 is 
P(answering 1,2 and exactly 2 of 3.4.or 5.)+P(answering 1,2 and also 3,4,5 )

P(answering 1,2 and exactly 2 of 3.4.or 5.)=
P(1,2,3,4 correct, 5 wrong)+P(1,2,3,5 correct, 4 wrong)+P(1,2,4,5 correct, 3 wrong)
also P(1,2,3,4 c, 5w)=P(1,2,3,5 c 4w)=P(1,2,4,5 c 3w )
so  
P(answering 1,2 and exactly 2 of 3.4.or 5.)=3*P(1,2,3,4)=3*1/2*1/2*1/3*1/3*2/3=1/4*2/9=2/36=1/18

note: P(1 correct)=1/2
         P(2 correct)=1/2
         P(3 correct)=1/3
         P(4 correct)=1/3
         P(5 wrong) = 2/3

P(answering 1,2 and also 3,4,5 )=1/2*1/2*1/3*1/3*1/3=1/108

Ans: P= 1/18+1/108=(6+1)/108=7/108

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In a certain computer game, the computer can make 1 of 4 moves, which it chooses randomly. According to the game manual, the probability it will make 1 of the moves is 0.5, the probability it will make 2 of the remaining moves is 0.25, and the probability it will make the last move is unknown, but nonzero. Why can the player immediately know that these probabilities are incorrect?

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You cannot make negative cookies so (c(f) and f)≥0.  And since cookies must (or at least should be in the real world) integers, f must be a multiple of 1/24. (otherwise you’d have fractional cookies).  What is a “reasonable” upper bound for c(f) is very subjective, obviously we cannot make an infinite amount of cookies 🙂

Because of this, the designer of this question, did so quite poorly.  Now simplistically we could say that the domain would be [0,+oo) and the range [0,+oo), But this would be ignoring all of the above.  In reality the domain would be [0, 1/24, 2/24, etc n/24]  where n/24 was some real limitation on the amount of flour (and time) that you could possibly have and the range would be [0,1,2,3,…n] where n would be the result of the the limited domain values.  (unless we were making fractional cookies :P)

Sorry, I could not resist, I cringe when I see subjective math problems.  The range and domain I put is what I would call “reasonable” range and domain.  I wonder what the designer of the question thinks is reasonable….

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Geoffery went on a trip across South America. He took 1,750 US dollars (USD) with him. In Chile, he traded his money for Chilean pesos (CLP) at a rate of USD:CLP = 1:496.5000. He spent 217,513 pesos before he went to Venezuela. In Venezuela, he traded his Chilean pesos for Venezuelan bolivars (VEF) at a rate of CLP:VEF = 1:0.1283. During his time in Venezuela, he spent 38,422.19 bolivars. At his next stop, Paraguay, he traded his Venezuelan bolivars for Paraguayan guarani (PYG) at a rate of VEF:PYG = 1:1063.9500. He spent 12,857,441.39 guarani before returning to the United States, where he traded his Paraguayan guarani for US dollars at a rate of PYG:USD = 1:0.00002186. How much money did Geoffery have remaining, in US dollars? Round all currency values to two decimal places.

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Answer:

$768.98

Step-by-step explanation:

Converting $1750 USD to Chilean pesos, we have

1750(496.5) = 868,875 CLP.

Spending 217,513 pesos gives us

868,875 – 217,513 = 651,362

Converting CLP to VEF, we have

651362*0.1283 = 83569.74

Spending 38,422.19 bolivars leaves us with

83,569.74 – 38,422.19 = 45,147.55

Converting VEF to PYG, we have

45147.55(1063.95) = 48,034,735.82

Spending 12,857,441.39 guarani leaves us with

48,034,735.82-12,857,441.39 = 35,177,294.43

Converting these PYG back to USD gives us

35,177,294.43(0.00002186) = 768.98

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Here are the IQ scores of 10 randomly chosen fifth-grade students: 145,139,126,122,125,13,96,110,118,118. TRUE OR FALSE If the value 96 were removed from the data set, the IQR of the remaining 9 IQ scores would be lower than the IQR of all 10 scores.

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Answer:

Next two number would be –5, –10, –20,–40, –80, –160.

Step-by-step explanation:

Given : –5, –10, –20, –40, . . .

To find : Use inductive reasoning to describe the pattern. Then find the next two numbers in the pattern.

Solution : We have given that

–5, –10, –20, –40, . . .

We can see from given pattern

-5 * 2 = – 10.

– 10 * 2 = – 20 .

-20 * 2 = – 40

So, each number is multiplied by 2 to get next number.

-40 * 2 = – 80 .

– 80 * 2 = – 160 .

Therefore, Next two number would be –5, –10, –20,–40, –80, –160.

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Which law increased immigration quotas and eased most remaining restrictions?

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Which law increased immigration quotas and eased most remaining restrictions?

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“Ocean currents result from two processes: the wind on the surface of the water and variation in water temperature and density. These ocean currents are convection currents. Under the tropical sun, water at the equator warms up. At the frigid poles, seawater cools down and sinks. Convection cells are set up with warm water moving along the surface to the poles and deep cold water flowing toward the equator. Changes in the density of ocean waters, caused by changes in salinity re also important in the formation of ocean currents. Ice formation near the poles leaves salt behind in the remaining water. This denser, more saline water sinks, creating its own density-driven currents. Surface winds also set surface currents into motion.” Can you pick the statements that accurately describe oceans currents? Check all the statements that are true. ‘Both the wind and solar energy influence ocean currents.’ ‘Warm water flows away from the equator toward the poles.’ ‘As the salinity of ocean water increases, density decreases.’ ‘Cold water sinks, warm water rises, creating a convection current.’

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Answer: The rainfall increases the mineral content of ocean water.

Explanation:

The minerals in the oceanic water are added by the rainfall through surface runoff. It is a phenomena in which the large volume free flowing water flows over the surface of the soil. This water is not absorbed by the soil instead it takes away along with it all surface materials like chemical fertilizers, soil, sediments, inorganic and organic minerals and deposit them to the water body (ocean, river or others).

Thus this can be said that rainfall increases the mineral content of the ocean water.  

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