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Read the poem below and answer the question that follows. “Blazon” by Cecilia Woloch —after Breton My love with his hair of nightingales With his chest of pigeon flutter, of gray doves preening themselves at dawn With his shoulders of tender balconies half in shadow, half in sun My love with his long-boned thighs the map of Paris of my tongue With his ink-stained tongue, his tongue the tip of a steeple plunged into milky sky My love with his wishing teeth With his fingers of nervous whispering, his fingers of a boy whose toys were cheap and broken easily My love with his silent thumbs With his eyes of a window smudged of a train that passes in the night With his nape of an empty rain coat hung by the collar, sweetly bowed My love with his laughter of an empty stairwell, rain all afternoon With his mouth the deepest flower to which I have ever put my mouth Source: Woloch, Cecilia. “Blazon.” Blogalicious. Diane Lockward, 17 Jan. 2010. Web. 17 May 2011. How does this poem represent a modern version of the blazon? A. The poet selects less expected features and comparisons. B. The poet uses the conventions of the blazon structure. C. The poet uses parody and omission to emphasize her love. D. The poet uses rhyme and iambic pentameter to exaggerate the subject’s beauty.

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Answered by answersmine AT 22/10/2019 – 02:46 AM

The poem represent a modern version of the Blazon by Cecilia Woloch with The poet uses rhyme and iambic pentameter to exaggerate the subject’s beauty. The answer is letter D. The story shows how Cecilia loved his husband by implicitly describing how and what she felt with comparisons of nature and things.

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From the top of the CN Tower, the angle of depression to to tip of the towers shadow is 88 degrees. The shadow is 19.5m long

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From the top of the CN Tower, the angle of depression to to tip of the towers shadow is 88 degrees. The shadow is 19.5m long

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George is 1.94 meters tall and wants to find the height of a tree in his yard. He started at the base of the tree and walked 10.20 meters along the shadow of the tree until his head was in a position where the tip of his shadow exactly overlaps the end fo the tree top's shadow. He is now 5.1 meters from the end of the shadows. How tall is the tree?

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George is 1.94 meters tall and wants to find the height of a tree in his yard. He started at the base of the tree and walked 10.20 meters along the shadow of the tree until his head was in a position where the tip of his shadow exactly overlaps the end fo the tree top’s shadow. He is now 5.1 meters from the end of the shadows. How tall is the tree?

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A man standing 9 feet from the base of a lamppost casts a shadow 6 feet long. if the man is 6 feet tall and walks away from the lamppost at a speed of 30 feet per minute, at what rate, in feet per minute, will his shadow lengthen?

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A man standing 9 feet from the base of a lamppost casts a shadow 6 feet long. if the man is 6 feet tall and walks away from the lamppost at a speed of 30 feet per minute, at what rate, in feet per minute, will his shadow lengthen?

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In sunlight, a vertical stick 6ft tall casts a shadow 2 ft long. At the same time a nearby tree casts a shadow 14ft long. How tall is the tree?

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In sunlight, a vertical stick 6ft tall casts a shadow 2 ft long. At the same time a nearby tree casts a shadow 14ft long. How tall is the tree?

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A tree casts a 9 ft shadow at the same time that a person 6 ft tall casts a 4 ft shawdow. what is the height of the tree?

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Ahemmm having x-intercepts of -3 and -5.. ..well, that simply means, -3 and -5 are roots or solutions or zeros of the equation

it namely means x = -3 and x = -5, an x-intercept is when the graph touches the x-axis, at that point, the y-intercept is 0, so the point is (-3, 0) and (-5, 0)

if the roots are -3, and -5, then

bf begin{cases}
x=-3implies x+3=0implies &(x+3)=0\
x=-5implies x+5=0implies &(x+5)=0
end{cases}\\
-------------------------------\\
(x+3)(x+5)=0implies (x+3)(x+5)=yimplies x^2+8x+15=y

if you have the zeros/x-intercepts/solutions of the polynomial, all you have to do is, get the factors, as above, and get their product, to get the parent original polynomial.

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Read the passage from Sir Arthur Conan Doyle’s novel The Hound of the Baskervilles. As the old man stood there he saw something coming across the moor, something which terrified him so that he lost his wits… There was the long, gloomy tunnel down which he fled. And from what? A sheep-dog of the moor? Or a spectral hound, black, silent, and monstrous? Was there a human agency in the matter? Did the pale, watchful Barrymore know more than he cared to say? It was all dim and vague, but always there is the dark shadow of crime behind it. The effect of the questions is to make the tone of the passage _______. humorous and sarcastic personal and poetic playful and light-hearted dramatic and tense Description

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Hey there!

Correct answer is D. Comma or Period Inside Rule

A. Question mark or exclamation point inside: those are not really necessary.

B. Colon or semicolon: not, a semicolon would divide the whole sentence and it would be shorten; a colon would work but after requested, when there is already a comma.

C. Question mark or Exclamation Point Outside Rule: would not work, becase it is an very polite and affirmative sentence.

D: A comma or period inside rule: actually, just a comma would work. Please, Cooper’s dad requested, go… Cooper’s dad requested must be in between commas as it is a vocative.

Hope this helps

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A telephone pole casts a shadow that is 37 m long. Find the height of the telephone pole if a statue that is 33 cm tall casts a shadow 83 cm long.

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Answer:

3 hours.          

Step-by-step explanation:

Let x be the time taken by shoe repairman to repair one pair.

We have been given that his assistant, who takes twice as long to repair a pair of shoes. So time taken by his assistant to repair one pair of shoes would be 2x.

The number of pair of shoes repaired by repairman in one hour would be frac{1}{x}.

The number of pair of shoes repaired by assistant in one hour would be frac{1}{2x}.

We have been given that together they can fix 16 pairs of shoes in an eight-hour day. We can represent this information in an equation as:

frac{1}{x}+frac{1}{2x}=frac{8}{16}

frac{1}{x}+frac{1}{2x}=frac{1}{2}

Let us have a common denominator.

frac{2*1}{2*x}+frac{1}{2x}=frac{1}{2}

frac{2}{2x}+frac{1}{2x}=frac{1}{2}

frac{2+1}{2x}=frac{1}{2}

frac{3}{2x}=frac{1}{2}  

Upon cross multiplying our equation we will get,

2x*1=3*2

2x=3*2

frac{2x}{2}=frac{3*2}{2}

x=3

Therefore, it take 3 hours for the repairman to fix one pair of shoes by himself.

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A telephone pole casts a shadow that is 34 m long. find the height of the telephone pole if a statue that is 36cm tall casts a shadow 77cm long

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Answer:

3 hours.          

Step-by-step explanation:

Let x be the time taken by shoe repairman to repair one pair.

We have been given that his assistant, who takes twice as long to repair a pair of shoes. So time taken by his assistant to repair one pair of shoes would be 2x.

The number of pair of shoes repaired by repairman in one hour would be frac{1}{x}.

The number of pair of shoes repaired by assistant in one hour would be frac{1}{2x}.

We have been given that together they can fix 16 pairs of shoes in an eight-hour day. We can represent this information in an equation as:

frac{1}{x}+frac{1}{2x}=frac{8}{16}

frac{1}{x}+frac{1}{2x}=frac{1}{2}

Let us have a common denominator.

frac{2*1}{2*x}+frac{1}{2x}=frac{1}{2}

frac{2}{2x}+frac{1}{2x}=frac{1}{2}

frac{2+1}{2x}=frac{1}{2}

frac{3}{2x}=frac{1}{2}  

Upon cross multiplying our equation we will get,

2x*1=3*2

2x=3*2

frac{2x}{2}=frac{3*2}{2}

x=3

Therefore, it take 3 hours for the repairman to fix one pair of shoes by himself.

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A telephone pole casts a shadow that is 29 m long. find the height of the telephone pole if a statue that is 38cm tall casts a shadow 78cm long

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Answer:

3 hours.          

Step-by-step explanation:

Let x be the time taken by shoe repairman to repair one pair.

We have been given that his assistant, who takes twice as long to repair a pair of shoes. So time taken by his assistant to repair one pair of shoes would be 2x.

The number of pair of shoes repaired by repairman in one hour would be frac{1}{x}.

The number of pair of shoes repaired by assistant in one hour would be frac{1}{2x}.

We have been given that together they can fix 16 pairs of shoes in an eight-hour day. We can represent this information in an equation as:

frac{1}{x}+frac{1}{2x}=frac{8}{16}

frac{1}{x}+frac{1}{2x}=frac{1}{2}

Let us have a common denominator.

frac{2*1}{2*x}+frac{1}{2x}=frac{1}{2}

frac{2}{2x}+frac{1}{2x}=frac{1}{2}

frac{2+1}{2x}=frac{1}{2}

frac{3}{2x}=frac{1}{2}  

Upon cross multiplying our equation we will get,

2x*1=3*2

2x=3*2

frac{2x}{2}=frac{3*2}{2}

x=3

Therefore, it take 3 hours for the repairman to fix one pair of shoes by himself.

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A telephone pole cast a shadow that is 34 m long find the height of the telephone pole if a statue that is 36 cm tall cast a shadow 77 cm long ?

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Answer:

3 hours.          

Step-by-step explanation:

Let x be the time taken by shoe repairman to repair one pair.

We have been given that his assistant, who takes twice as long to repair a pair of shoes. So time taken by his assistant to repair one pair of shoes would be 2x.

The number of pair of shoes repaired by repairman in one hour would be frac{1}{x}.

The number of pair of shoes repaired by assistant in one hour would be frac{1}{2x}.

We have been given that together they can fix 16 pairs of shoes in an eight-hour day. We can represent this information in an equation as:

frac{1}{x}+frac{1}{2x}=frac{8}{16}

frac{1}{x}+frac{1}{2x}=frac{1}{2}

Let us have a common denominator.

frac{2*1}{2*x}+frac{1}{2x}=frac{1}{2}

frac{2}{2x}+frac{1}{2x}=frac{1}{2}

frac{2+1}{2x}=frac{1}{2}

frac{3}{2x}=frac{1}{2}  

Upon cross multiplying our equation we will get,

2x*1=3*2

2x=3*2

frac{2x}{2}=frac{3*2}{2}

x=3

Therefore, it take 3 hours for the repairman to fix one pair of shoes by himself.

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A telephone pole cast a shadow that is 37 m long find the height of the telephone pole if a statue that is 33 cm tall cast a shadow 83 cm long ?

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Answer:

The height of the telephone pole is 14.711 m (Approx) .

Step-by-step explanation:

Let us assume that the height be x .

Let us assume that the shadow  be y .

(As the shadow is always proportional to the height .)

Thus

xpropto y

y = kx

Where k is the constant of proportionality .

As given

if a statue that is 33 cm tall cast a shadow 83 cm long .

y = 83 cm

x = 33 cm

Put in the equation y = kx .

83 = 33k

k = frac{83}{33}

As given

A telephone pole cast a shadow that is 37 m .

Let us assume that the height of the telephone pole be z .

As

1m = 100cm

37m = 3700 cm

y = 3700 cm

x = z

Put in the equation  y = kx .

3700 = zk

k = frac{3700}{z}

Compare the value of k .

frac{3700}{z} = frac{83}{33}

frac{3700times 33}{83} =z

frac{122100}{83} =z

z = 1471.1 cm(Approx)

As

1 cm = frac{1}{100} m

1471.1 cm = frac{1471.1}{100} m

                       = 14.711 m (Approx)

Therefore the  height of the telephone pole is 14.711 m (Approx) .

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A building 300 feet tall casts a 100 foot long shadow. if a person looks down from the top of the? building, what is the measure of the angle between the end of the shadow and the vertical side of the building?

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Answer: If two angles are equal to the same measure, then
the angles are congruent.


That is actually the definition of congruent. Whenever they
throw the same value, they are called congruent.

There is something that proves that PTR and STQ will always
be equal to the same measure, and it was not among the given options:

Acording to the construction protocol, one side of PTR (the
PT side) is opposite to one side of STQ (the TQ side). We call two rays opposite
when they belong to the same line but they have different directions (for example,
one goes to the left and the other one goes to the right). Try building it and
you will see it! The same happens with the other sides: TR is opposite to ST. Whenever
this happens, we call those two angles a vertical pair and they are
always the same size. You can prove that tying it up with linear pairs,
which sum 180°. An angle forms a linear pair with another angle whenever they share a side
and the other two sides are in the same line.

If a and b are supplementary angles, then a+b=180°

So a=180°-b

If b and c are adjacent angles, then b+c =180°

So c=180°-b

This proves that c and a are the same size.

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A 35 – m tall building casts a shadow. the distance from the top of the building to the tip of the shadow is 36 m . find the length of the shadow. if necessary, round your answer to the nearest tenth.

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Answer:

a. Maria – 5, Keisha – 8, Leah – 13, Jo – 36

Step-by-step explanation:

Maria, Keisha, Jo, and Leah wear jerseys numbered 5, 8, 13, and 36, but not necessarily in that order.

Jo’s jersey number is divisible by 6.

36 is divisible by 6

So,  Jo’s jersey number is 36.

The girl wearing 8 has a better jump shot than Maria or Leah and Jo is wearing number 36

So, Keisha must be wearing number 8 .

Now we are supposed to find the jersey number of Maria and Leah

Now we are given that The number of letters in one name is the same as her number.

Then number of letters in Maria = 5 and Leah = 4

So, according to the number of letters in one name is the same as her number.

Maria must be wearing number 5 jersey

So, Leah must be wearing the remaining number i.e. 13

Hence ,

Name    Jersey number

Jo               36

Leah            13

Maria           5

Keisha         8

Thus Option A is correct.

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A building casts a shadow that is 72 feet long. A garage next to the building is 27 feet high and casts a shadow that is 4.5 feet long. What is the height of the building?

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Answer:

There are two outlier in the data.

Step-by-step explanation:

We are given a given a data as:

5, 45, 46, 25, 34, 73, 37, 33, 42, 40, 37, 34, 49, 46, 45.

We know that an outlier of an data are the data points that stands out of the rest of the data that is it takes either a too high or too low value as compared to other data points.

Hence, here looking at the data points we see that there are two outliers one at the left of the data and one to the right.

i.e. one is a too low values and one is a high value.

The outliers are:

5 and 73.

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The light from a lamp casts a shadow of a man standing 10 feet away from the lamppost. The shadow is 7 feet long. The angle of elevation from the tip of the shadow to the lamp is 50. To the nearest foot, the lamppost is _____ feet tall.

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Answer

Draw a graph which joins the points (100, 120) and (50, 95) and has a slope = 0.50

Explanation

A graph of y against x means that x is the independent variable and y is the dependent variable. Notice that the charge (y) depends on the number of minutes (x). Therefore, the points that we are going to join to make our graph will have coordinates (x, y)

We know that the company charges $120 for 100 minutes, so x=100 and y=120. Therefore, our first point will be (100, 120)

We also know that the company charges $95 for 50 minutes, so x=95 and y=50. Therefore, our second point will be (50, 95)

Now, to find the slope between our tow points, we are going to use the slope formula: m=frac{y_{2}-y_{1}}{x_{2}-x_{1}}

where

(x_{1},y_{1}) are the coordinates of the first point

(x_{2},y_{2}) are the coordinates of the second point

We know from our points that x_{1}=100, y_{1}=120, x_{2}=50, and y_{2}=95. So let’s replace those values in our formula to find m

m=frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=frac{95-120}{50-100}

m=frac{-25}{-50}

m=frac{1}{2}

m=0.50

Now that we have our slope, we can use the point-slope formula to complete the equation of the line joining our two points

y-y_{1}=m(x-x_{1})

y-120=0.50(x-100)

y-120=0.50x-50

y=0.50x+70

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