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the y int (where the line crosses the y axis) is (0,-2)

(-2,0)(0,-2)

slope = (-2 – 0) / (0 – (-2) = -2/2 = -1

y = mx + b

slope(m) = -1

use either of ur points (-2,0)…x = -2 and y = 0

sub and find b

0 = -1(-2) + b

0 = 2 + b

-2 = b

so ur equation in slope intercept form is : y = -x – 2

y = -x – 2

x + y = -2

x + y + 2 = 0 <== general form

there can be 2 answer for point slope form…

y – y1 = m(x – x1)

slope(m) = -1

(-2,0)…x1 = -2 and y1 = 0

sub

y – 0 = – (x – (-2)

y – 0 = -(x + 2) <=== point slope form

y – y1 = m(x – x1)

slope(m) = -1

(0,-2)…x1 = 0 and y1 = -2

sub

y – (-2) = – (x – 0)

y + 2 = – (x – 0) <== point slope form

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