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PLEASE HELP LAST QUESTION ON TEST Rock layers made of clay have very small particles. The pores between the particles are not well connected. Will a good aquifer form in a layer of clay? A. Yes, because smaller particles tend to increase permeability by increasing the surface area. B. No, because pores that are not well connected have low permeability C. Yes, because smaller particles tend to increase porosity D. both b and c

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# Tag: surface

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Question 3(Multiple Choice Worth 1 points) [FW.02]The pictures below show four Earth features. image 1 is a sinkhole, image 2 is a cave, image 3 is a geyser, and image 4 is a hotspring Which of these features are formed when hot groundwater is forced out through cracks in the Earth’s surface? 1 and 2 1 and 4 2 and 3 3 and 4

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If the side length of the base of a square pyramid is divided by 4 and the slant height is divided by 3, what is the surface area formula that represents these changes?

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In relation to surface area, how do you think a gigantic cytoplasm would affect a eukaryotic cell of a multicellular organism?

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A student wants to know how many 1 cm cubes will fit into a 10 cm by 8 cm by 12 cm box. What measure is the student trying to calculate? height volume perimeter surface area

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Which Hellenistic inventor and mathematician experimented with levers, created a machine for raising and transporting water and determined formulas for calculating the surface area and volume of a sphere?

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at the center of our Solar System, at a distance of about 150 x 106 kilometers from

Earth. The Sun produces solar heat energy. This energy travels through space in the form of electromagnetic

waves. The process of heat transfer is known as radiation.Before reaching the sea-level the sun’s rays have to pass through the whole thickness of the atmosphere.

So, the first surface that has the potential to come into contact with solar radiation are the clouds.

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for #1: l x w x a = 4 x 9 x 11 =

**396**(whatever the measurement is squared)

for #2: base x height 4 x 4 x 8 =

**128**(whatever the measurement is squared)

**hope this helps 😀**

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**
**

Other choices require further movement that may worsen the shin split.
The triangle ABC is similar to triangle LMP. The order here is very important. The letters correspond to one another

A corresponds to L (first letters of each sequence)

B corresponds to M (second letters of each sequence)

C corresponds to P (third letters of each sequence)
The gravitational force Fg between two objects is given by the equation:
The gravitational force Fg between two objects is given by the equation:
The gravitational force Fg between two objects is given by the equation:
The gravitational force Fg between two objects is given by the equation:
Fg=(G*m₁*m₂)/r₂, where G=6.67*10^-11 m³ kg⁻¹ s⁻² is the gravitational constant, m₁ and m₂ are the masses of the two bodies and r is the distance between those bodies.

Due to the gravitational attraction the pencil and the eraser will attract if we there is no friction on the surface.

v²=2as, where a is the acceleration of the pencil and s is the path. In our case s=r so we can write:

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### Answered by answersmine AT 22/10/2019 – 04:55 AM

Epimysium is the name of the connective tissue which forms the outer surface of each skeletal muscle. The term is derived from the words “epi” meaning (outer or superficial), and “mysium” meaning (of muscle).

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**The answer is B. resting until the discomfort goes away.**

Other choices require further movement that may worsen the shin split.

The pain of the injury is triggered when a movement like running is done. The best way to lessen the pain is through resting. With this kind of condition, running is impossible to do. So it’s better to avoid foot regular movement and exercises. The best way to cure this is treatment from a doctor.

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A corresponds to L (first letters of each sequence)

B corresponds to M (second letters of each sequence)

C corresponds to P (third letters of each sequence)

In a similar fashion, the segments also correspond to one another.

AB corresponds to LM (first two letters of each sequence)

AC corresponds to LP (first and last letters of each sequence)

BC corresponds to MP (last two letters of each sequence)

————————————

AB corresponds to LM. AB is 4 units long. LM is 2 units long. So AB is twice as long as LM. This ratio (of 2:1) will be applied to every paired corresponding value.

Also, the right angle is at angle M for triangle LMP. The right angle will be at angle B for triangle ABC (since B corresponds to M). The answer will have an x coordinate of 7. So the answer is either choice B or choice C.

If we move 4 units down from point B, we land on (7,-10). That isn’t listed as an answer choice. Let’s try moving 4 units up from point B. We land on (7,-2). This is an answer choice

**So the final answer is choice C) (7,-2)**

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**Explanation :**

In the net ionic equations, we are not include the spectator ions in the equations.

**Spectator ions :** The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

**(a) The given balanced ionic equation is,**

The ionic equation in separated aqueous solution will be,

In this equation, are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

**The net ionic equation will be,**

**(b) The given balanced ionic equation is,**

The ionic equation in separated aqueous solution will be,

In this equation, are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

**The net ionic equation will be,**

**(c) The given balanced ionic equation is,**

The ionic equation in separated aqueous solution will be,

In this equation, are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

**The net ionic equation will be,**

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**Solution:**

The Given Rectangle having dimensions

Length = 80 cm

Breadth = 50 cm

Let the Six squares which has been cut from this rectangle have side of length a cm.

Area of each square = (Side)²= a²

Area of 6 Identical Squares = 6 × a²= 6 a²

If four squares are cut from four corners and two along Length,

then , Length of Box = (80 – 3 a)cm, Breadth of Box = (50 – 2 a)cm, Height = a cm

Volume of Box =V = Length × Breadth × Height

V = (80 – 3 a)× (50 – 2 a)× a

V = 4000 a – 310 a² + 6 a³

For Maximum Volume

V’= 0 , where V’ = Derivative of V with respect to a.

V’= 4000 – 620 a + 18 a²

V’ =0

18 a² – 620 a + 4000= 0

9 a² – 310 a + 2000=0

using determinant method

cm

V”=1 8 a – 310 = -ve

which shows , when a = 8.6 cm , volume is maximum.

So, V = 4000×8.6 – 310×(8.6)²+6×(8.6)³=15288.736 cm³

OR

If four squares are cut from four corners and two along Breadth,

then , Length of Box = (80 – 2 a)cm, Breadth of Box = (50 – 3 a)cm, Height = a cm

Volume of Box =V = Length × Breadth × Height

V = (80 – 2 a)× (50 – 3 a)× a

V = 4000 a – 340 a² + 6 a³

For Maximum Volume

V’= 0 , where V’ = Derivative of V with respect to a.

V’= 4000 – 680 a + 18 a²

V’ =0

18 a² – 680 a + 4000= 0

9 a² – 340 a + 2000=0

Using Determinant method

cm

V”=18 a -340= -ve value when a = 7.6 cm, shows volume is maximum when a = 7.6 cm

V= 4000×7.6 -340 × (7.6)² +6× (7.6)³=13395.456 cubic cm

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Two spheres of the same density have a ratio of 9 to 16 in surface area. If the small sphere weighs 15 kg, what does the large sphere weigh?

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1- The correct answer is B, as one result of the Great Society was that the lives of many underprivileged Americans improved.

The Great Society was a set of US national reform programs announced by President Lyndon B. Johnson for the first time in a speech at Ohio University on May 7, 1964 and more fully illustrated on May 22, 1964 at the University of Michigan. These reform programs were subsequently presented to the Congress of the United States and largely approved during the 1960s, thanks to the consent of its supporters of the Democratic Party.

Two main goals of social reforms were the elimination of poverty and racial injustice. During this period new large spending programs were launched in the fields of education, medical care, urban problems and transport. Johnson’s “Great Society” was linked, in its objectives and policies, to President Franklin Delano Roosevelt’s New Deal program.

Some proposals of the Great Society resumed initiatives contained in the New Frontier program, interrupted by the tragic death of President John F. Kennedy. Johnson’s success in promoting and endorsing his reforms depended on his considerable congressional political influence, his persuasion, and the favorable historical circumstances resulting from the 1964 presidential elections, which allowed the Democratic Party to dominate Congress and to elect the House of Representatives with the largest number of exponents of the liberal current since 1938.

The evolution of the Vietnam war and the massive involvement of the American military machine in the conflict, however, partly undermined the success of the “Great Society” program. Growing, huge expenditures for the continuation of the war made more difficult to finance the reform programs. Representatives of the Democratic Party against the war in Vietnam complained that military spending decisively stifled the Great Society program. On the whole, however, despite growing political and economic difficulties, which forced the administration to eliminate or reduce the financing of some projects, President Johnson managed to activate a series of programs of great importance, including Medicare, Medicaid, the Older Americans Act and the federal education funding, which are still active.

2- The correct answer is C, as the Immigration and Nationality Act of 1965 was necessary because the previous existing American immigration policies were discriminatory.

On October 3, 1965, President Lyndon B. Johnson signed the law into effect, saying: “The [old] system violates the basic principle of American democracy, the principle according to which the valuation and reward of each man should be established on the basis of his merits as a man. It has been anti-American in the highest sense, because it has been unfaithful to the faith that led thousands to these shores, even before we were a country. ”

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Two spheres of the same density have a ratio of 4 to 9 in surface area. If the small sphere weighs 10 kg, what does the large sphere weigh?

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Fg=(G*m₁*m₂)/r₂, where G=6.67*10^-11 m³ kg⁻¹ s⁻² is the gravitational constant, m₁ and m₂ are the masses of the two bodies and r is the distance between those bodies.

Due to the gravitational attraction the pencil and the eraser will attract if we there is no friction on the surface.

m₁=10 g=0.01 kg is the mass of the pencil

m₂=20 g=0.02 kg is the mass of the eraser

r=2.5 cm = 0.025 m

First we calculate the Fg:

Fg={(6.67*10^-11)*0.01*0.02}/(0.025²)=2.1344*10^-11 N

To get the velocity v of the pencil:

v²=2as, where a is the acceleration of the pencil and s is the path. In our case s=r so we can write:

v²=2ar

a=Fg/m₁= 2.133*10^-9 m/s²

v²=2*(2.133*10^-9)*0.025=1.0665*10^-10

v=√(1.0665*10^-10)=1.0327*10^-5 m/s

We have the velocity and the acceleration, so we can calculate the time t with the equation:

t=v/a=(1.0327*10^-5)/(2.133*10^-9)=4841.6 s

1 hour has 3600 s so when we divide time t in seconds by 3600 we get time T in hours:

T=t/3600=4841.6/3600=1.3449 h.

So the time for the pencil and eraser to touch is T=1.3449 hours.

Also time T can be expressed like T= 1h and 20 mins and 41.64 s

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Fg=(G*m₁*m₂)/r₂, where G=6.67*10^-11 m³ kg⁻¹ s⁻² is the gravitational constant, m₁ and m₂ are the masses of the two bodies and r is the distance between those bodies.

Due to the gravitational attraction the pencil and the eraser will attract if we there is no friction on the surface.

m₁=10 g=0.01 kg is the mass of the pencil

m₂=20 g=0.02 kg is the mass of the eraser

r=2.5 cm = 0.025 m

First we calculate the Fg:

Fg={(6.67*10^-11)*0.01*0.02}/(0.025²)=2.1344*10^-11 N

To get the velocity v of the pencil:

v²=2as, where a is the acceleration of the pencil and s is the path. In our case s=r so we can write:

v²=2ar

a=Fg/m₁= 2.133*10^-9 m/s²

v²=2*(2.133*10^-9)*0.025=1.0665*10^-10

v=√(1.0665*10^-10)=1.0327*10^-5 m/s

We have the velocity and the acceleration, so we can calculate the time t with the equation:

t=v/a=(1.0327*10^-5)/(2.133*10^-9)=4841.6 s

1 hour has 3600 s so when we divide time t in seconds by 3600 we get time T in hours:

T=t/3600=4841.6/3600=1.3449 h.

So the time for the pencil and eraser to touch is T=1.3449 hours.

Also time T can be expressed like T= 1h and 20 mins and 41.64 s

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The correct answer is – 4) Rainfall.

The rainfall is crucial and the most important factor that contributes to the formation of the soil. The rainfall has such big influence because of few things:

– weathering

The water from the rainfall contributes to the weathering of the rocks, thus making them in little sandy pieces.

– plant life

The plant life needs water to exist, and the rainfall provides that. Further, the plants that die are the biggest factor that helps into the soil formation and fertilization.

– animal life

Once there’s rainfall and plants, the animals can exist too, and the animals are very import in both the fertilization of the soil, and fertilization of the plants that also fertilize the soil.

– decomposition

The dead plants and animals decompose much quicker and much more efficiently when there’s bigger humidity and water, so the rainfall is essential in this process.

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Hello!

**The statement is False. **

It is impossible for someone to reasonably believe that it is safe to pass while their view is obstructed.

In the state of Florida is recommended to follow the Two-Second rule. This means that when you’re behind a vehicle, you should watch it pass a fixed object (such as an overpass, sign, corner, etc) and count the seconds that it takes for you to reach the same marker. However, there are many situations where the following distance should increase. For example, when driving in poor weather conditions such as rain, smoke or fog. In those cases, it is recommended that you double or triple your following distance.

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**Answer:**

Option C – BD=76 cm

**Step-by-step explanation:**

**Given :** You are designing a diamond-shaped kite. you know that AD = 44.8 cm, DC = 72 cm, and AC = 84.8 cm.

**To find : **How long BD should it be?

**Solution : **

First we draw a rough diagram.

The given sides were AD = 44.8 cm, DC = 72 cm and AC = 84.8 cm.

According to properties of kite

**Two disjoint pairs of consecutive sides are congruent.**

**So,** AD=AB=44.8 cm

DC=BC=72 cm

**The diagonals are perpendicular.**

**S**o, AC ⊥ BD

Let O be the point where diagonal intersect let let the partition be x and y.

AC= AO+OC

AC= …….[1]

Perpendicular bisect the diagonal BD into equal parts let it be z.

BD=BO+OD

BD=z+z

**Applying Pythagorean theorem in ΔAOD**

where H=AD=44.8 ,P= AO=x , B=OD=z

………[2]

**Applying Pythagorean theorem in ΔCOD**

where H=DC=72 ,P= OC=y , B=OD=z

…………[3]

**Subtract [2] and [3]**

……….[4]

**Add equation [1] and [4], to get values of x and y**

**Substitute x in [1]**

**Substitute value of x in equation [2], to get z**

**We know, **BD=z+z

BD= 38.06+38.06

BD= 76.12

**Nearest to whole number **BD=76 cm

**Therefore, Option c – BD=76 cm is correct.**

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Fg=(G*m₁*m₂)/r₂, where G=6.67*10^-11 m³ kg⁻¹ s⁻² is the gravitational constant, m₁ and m₂ are the masses of the two bodies and r is the distance between those bodies.

Due to the gravitational attraction the pencil and the eraser will attract if we there is no friction on the surface.

m₁=10 g=0.01 kg is the mass of the pencil

m₂=20 g=0.02 kg is the mass of the eraser

r=2.5 cm = 0.025 m

First we calculate the Fg:

Fg={(6.67*10^-11)*0.01*0.02}/(0.025²)=2.1344*10^-11 N

To get the velocity v of the pencil:

v²=2as, where a is the acceleration of the pencil and s is the path. In our case s=r so we can write:

v²=2ar

a=Fg/m₁= 2.133*10^-9 m/s²

v²=2*(2.133*10^-9)*0.025=1.0665*10^-10

v=√(1.0665*10^-10)=1.0327*10^-5 m/s

We have the velocity and the acceleration, so we can calculate the time t with the equation:

t=v/a=(1.0327*10^-5)/(2.133*10^-9)=4841.6 s

1 hour has 3600 s so when we divide time t in seconds by 3600 we get time T in hours:

T=t/3600=4841.6/3600=1.3449 h.

So the time for the pencil and eraser to touch is T=1.3449 hours.

Also time T can be expressed like T= 1h and 20 mins and 41.64 s

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m₂=20 g=0.02 kg is the mass of the eraser

r=2.5 cm = 0.025 m

First we calculate the Fg:

Fg={(6.67*10^-11)*0.01*0.02}/(0.025²)=2.1344*10^-11 N

To get the velocity v of the pencil:

v²=2ar

a=Fg/m₁= 2.133*10^-9 m/s²

v²=2*(2.133*10^-9)*0.025=1.0665*10^-10

v=√(1.0665*10^-10)=1.0327*10^-5 m/s

We have the velocity and the acceleration, so we can calculate the time t with the equation:

t=v/a=(1.0327*10^-5)/(2.133*10^-9)=4841.6 s

1 hour has 3600 s so when we divide time t in seconds by 3600 we get time T in hours:

T=t/3600=4841.6/3600=1.3449 h.

So the time for the pencil and eraser to touch is T=1.3449 hours.

Also time T can be expressed like T= 1h and 20 mins and 41.64 s

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**Answer:**

a) The time the police officer required to reach the motorist was 15 s.

b) The speed of the officer at the moment she overtakes the motorist is 30 m/s

c) The total distance traveled by the officer was 225 m.

**Explanation:**

The equations for the position and velocity of an object moving in a straight line are as follows:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where:

x = position at time t

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

v = velocity at time t

a)When the officer reaches the motorist, the position of the motorist is the same as the position of the officer:

x motorist = x officer

Using the equation for the position:

x motirist = x0 + v · t (since a = 0).

x officer = x0 + v0 · t + 1/2 · a · t²

Let´s place our frame of reference at the point where the officer starts following the motorist so that x0 = 0 for both:

x motorist = x officer

x0 + v · t = x0 + v0 · t + 1/2 · a · t² (the officer starts form rest, then, v0 = 0)

v · t = 1/2 · a · t²

Solving for t:

2 v/a = t

t = 2 · 15.0 m/s/ 2.00 m/s² = 15 s

The time the police officer required to reach the motorist was 15 s.

b) Now, we can calculate the speed of the officer using the time calculated in a) and the equation for velocity:

v = v0 + a · t

v = 0 m/s + 2.00 m/s² · 15 s

v = 30 m/s

The speed of the officer at the moment she overtakes the motorist is 30 m/s

c) Using the equation for the position, we can find the traveled distance in 15 s:

x = x0 + v0 · t + 1/2 · a · t²

x = 1/2 · 2.00 m/s² · (15s)² = 225 m

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**Answer:**

a) The time the police officer required to reach the motorist was 15 s.

b) The speed of the officer at the moment she overtakes the motorist is 30 m/s

c) The total distance traveled by the officer was 225 m.

**Explanation:**

The equations for the position and velocity of an object moving in a straight line are as follows:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where:

x = position at time t

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

v = velocity at time t

a)When the officer reaches the motorist, the position of the motorist is the same as the position of the officer:

x motorist = x officer

Using the equation for the position:

x motirist = x0 + v · t (since a = 0).

x officer = x0 + v0 · t + 1/2 · a · t²

Let´s place our frame of reference at the point where the officer starts following the motorist so that x0 = 0 for both:

x motorist = x officer

x0 + v · t = x0 + v0 · t + 1/2 · a · t² (the officer starts form rest, then, v0 = 0)

v · t = 1/2 · a · t²

Solving for t:

2 v/a = t

t = 2 · 15.0 m/s/ 2.00 m/s² = 15 s

The time the police officer required to reach the motorist was 15 s.

b) Now, we can calculate the speed of the officer using the time calculated in a) and the equation for velocity:

v = v0 + a · t

v = 0 m/s + 2.00 m/s² · 15 s

v = 30 m/s

The speed of the officer at the moment she overtakes the motorist is 30 m/s

c) Using the equation for the position, we can find the traveled distance in 15 s:

x = x0 + v0 · t + 1/2 · a · t²

x = 1/2 · 2.00 m/s² · (15s)² = 225 m

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