Home / Assignment Help / The x- intercepts of a parabola are (-5, 0) and (3, 0). What is the function of the parabola? f(x) = -2(x2 + 2x − 5) f(x) = -2(x2 + 2x − 15) f(x) = -2(x2 − 2x − 15) f(x) = -2(x2 − 2x − 5)

The x- intercepts of a parabola are (-5, 0) and (3, 0). What is the function of the parabola? f(x) = -2(x2 + 2x − 5) f(x) = -2(x2 + 2x − 15) f(x) = -2(x2 − 2x − 15) f(x) = -2(x2 − 2x − 5)

Just need to substitute (with some patience) x=-5 and see whether you get f(x)=0, and x=3.

Now, a parabola is also f(x) proportional to (x+5)*(x-3) (if you know the solutions, which you do in this particular example). So: x^2 + 2*x – 15. This is the third one. The -2 is there to confuse, any number could be there because in this example since f(x)=0 for x=-5 and x=3, it won’t change 0*number=0.

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