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what is the strength of the electric field at the position indicated by the dot in

What are the strength and direction of the electric field at the position indicated by the dot in the diagram below, in which d = 4.9 cm, q = 11
22,904 results
Physics
3 There are two charges +Q and –Q/2 that locate at two positions with a separation of d as shown in Fig. 1. We may put +Q at the origin of the x-axis to facilitate the calculation. (a) Find the electric field for +Q and –Q/2 at the position P. (5

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A 30.0 cm diameter loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is 5.60 multiplied by 105 N·m2/C. What is the magnitude of the electric field? MN/C

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Any dielectric material other than vacuum has a maximum electric field that can be produced in the dielectric material before it physically or chemically breaks down and begins to conduct. This maximum electric field is called dielectric strength. The

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An electric dipole consists of 2.0 g spheres charged to 5.0 nC (positive and negative) at the ends of a 12 cm long massless rod. The dipole rotates on a frictionless pivot at its center. The dipole is held perpendicular to a uniform electric field with

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When an electron moves 2.5 m in the direction of an electric field, the change in electrical potential energy of the electron is 8×10-17J. What is the strength of the electric field that causes the change in potential energy? 320 N/C 200 N/C 20 N/C 3.2 N/C

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Two point charges q and q’ are placed respectively at two points A and B. Let O be the midpoint of [AB]. Charge q placed at A creates at O an electric field of strength E=9×10^6 V/m. Determine the resultant electric field at O when: a) q’=q b) q’=-q

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A circular surface with a radius of 0.058 m is exposed to a uniform external electric field of magnitude 1.49 104 N/C. The electric flux through the surface is 74 N · m2/C. What is the angle between the direction of the electric field and the normal to

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A circular surface with a radius of 0.058 m is exposed to a uniform external electric field of magnitude 1.49 104 N/C. The electric flux through the surface is 74 N · m2/C. What is the angle between the direction of the electric field and the normal to

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A circular surface with a radius of 0.058 m is exposed to a uniform external electric field of magnitude 1.49 104 N/C. The electric flux through the surface is 74 N · m2/C. What is the angle between the direction of the electric field and the normal to

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Gold ions (Au+) are accelerate to high speeds using electric fields. These ions are then passed through a region where uniform electric E and magnetic B fields are present. If the ions are traveling to the right, which configuration of E and B will serve

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