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What is the value of Fraction 1 over 2×3 + 3.4y when x = 4 and y = 2?

Answer:                

The probability  that both marbles she chooses are blue is frac{2}{15}

Step-by-step explanation:

Given : A bag contains 10 marbles: 4 are green, 2 are red, and 4 are blue. Christine chooses a marble at random, and without putting it back, chooses another one at random.

To find : What is the probability that both marbles she chooses are blue?

Solution :

Total number of marbles = 10

Green marbles = 4

Red marbles = 2

Blue marbles = 4

Probability is favorable outcome upon total number of outcomes.

Probability of getting first marble is blue

text{P(first blue marble)}=frac{4}{10}=frac{2}{5}.

Without replacement,

i.e. Blue marble left = 3

Total marble left = 9


Probability of getting second marble is blue

text{P(second blue marble)}=frac{3}{9}=frac{1}{3}

The probability that both marbles she chooses are blue is

text{P(both blue marble)}=frac{2}{5}timesfrac{1}{3}

text{P(both blue marble)}=frac{2}{15}

Therefore, The probability  that both marbles she chooses are blue is frac{2}{15}

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